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Cheers James
For B) i used the rate equation to find out the K value and then substituted it into the 2nd reation, i got the same answer.
banger video
Thank uuuu
can u make a full paper 1 walkthrough
Sorry james for the question, i thought the first one would be called rubidium perchlorate as there are 4 oxygens, similar to Mn04-?
Exam board required the inclusion of the oxidation number for Cl. I would always advise on giving a systematic name rather than something like perchlorate
@@MaChemGuytrue😂😂😂😂 some comments sometimes
@@H1-NMR do you not think it would've better not to say anything to my question? 😐
Cheers James
For B) i used the rate equation to find out the K value and then substituted it into the 2nd reation, i got the same answer.
banger video
Thank uuuu
can u make a full paper 1 walkthrough
Sorry james for the question, i thought the first one would be called rubidium perchlorate as there are 4 oxygens, similar to Mn04-?
Exam board required the inclusion of the oxidation number for Cl. I would always advise on giving a systematic name rather than something like perchlorate
@@MaChemGuytrue😂😂😂😂 some comments sometimes
@@H1-NMR do you not think it would've better not to say anything to my question? 😐