Sir, this was extremely helpful. My chemistry class is made up of a majority of students who dont know calculus, and therefore the teacher just gave us the formulas and a brief explanation. This helped me understand 🙏
In case anyone missed it as i did, during the proof of the 1st order law the integer of d[a]/[a] is equal to ln[a] due to the fact that if we derived ln[a] we would have to apply the power rule and take the derivative of the ln (1/a) times the function embbeded inside the function, [a].
the only problem you have is that you uploaded this really long before people were interested in this :) If u had posted this sometime in the past year or so, you would surely have at least 50k views :) great work man!! you've done a really fine job! I sincerely hope more people find this gem.
Hi, thanks for the video. However, I am still confused why [A] is constant (on the right side of the equation) in the differentiation for the first order equation?
-d[a]/dt=k[a] in order to integrate both sides we need to get the same variables on both sides of the equation first lets get both [a] on one side and dt on the other side like so: d[a]/dt=-k[a] [a]*d[a]/dt = -k divide by [a] [a]*d[a] = -k*dt multiply by dt now plug in your integrals and you can solve!
Video is really helpfull, idk why but the textbook I use just wrote the equations without derivation. Btw, is it legal to integrate both sides with different variables in 14.33
Sir, this was extremely helpful. My chemistry class is made up of a majority of students who dont know calculus, and therefore the teacher just gave us the formulas and a brief explanation. This helped me understand 🙏
Glad it helped!
This us one SWEET calculus-based explanation at deriving the integrated rate laws! THANK YOU!!!
You're very welcome!
Amazingly comprehensive for the maths layman such as me
Thanks for the thorough and descriptive video - really helped.
This is now the best have been looking for, thank you.
You're welcome!
Incredible
thanks!
@@MrGrodskiChemistry i will subscribe for this video
i love it, now i dont have to remember these!
Thank you sooo much. This video was very useful for a paper of mine!
Very precise, thank you.
You're very welcome
thank you verry much i appreciate you guys u are a genius man!
hello sir, your sign for the integral is wrong.
the video was good either way.
You are right! Great edit! For some reason I always wrote them that way.
@@MrGrodskiChemistry 😁👍
In case anyone missed it as i did, during the proof of the 1st order law the integer of d[a]/[a] is equal to ln[a] due to the fact that if we derived ln[a] we would have to apply the power rule and take the derivative of the ln (1/a) times the function embbeded inside the function, [a].
paying thousands to go to college just so I can look up a free video that does a better job of teaching it
Thank you so much.
the only problem you have is that you uploaded this really long before people were interested in this :) If u had posted this sometime in the past year or so, you would surely have at least 50k views :) great work man!! you've done a really fine job! I sincerely hope more people find this gem.
thank you so much :)
Thanks! You're welcome!
Hi, thanks for the video. However, I am still confused why [A] is constant (on the right side of the equation) in the differentiation for the first order equation?
-d[a]/dt=k[a]
in order to integrate both sides we need to get the same variables on both sides of the equation
first lets get both [a] on one side and dt on the other side like so:
d[a]/dt=-k[a]
[a]*d[a]/dt = -k divide by [a]
[a]*d[a] = -k*dt multiply by dt
now plug in your integrals and you can solve!
Thankyou so much
You're welcome!
Thank you
You're welcome!
Video is really helpfull, idk why but the textbook I use just wrote the equations without derivation. Btw, is it legal to integrate both sides with different variables in 14.33