I stared at my notes for about an hour and couldn't' figure out a single thing until I saw this video. Thanks for making everything easy to understand!
I must say... I have my test tomorrow. I was clueless until about 20 minutes ago when I discovered your videos. I never even comment on youtube but these are so amazing I felt the need. You deserve a medal.
Hey Leah! Remember me? I got a 94/100 on my orgo midterms. Now I have my final on monday. Thank you so so much for your videos. They're extremely helpful!!
This makes so much sense now. I love that you gave explanations for why things were happening the way that they were. I am excited about trying this mechanism on my own!
You're the best! I watched almost all of your videos over the course of a week for my final tomorrow. I was hopeless, but now I have a fighting chance. Thanks so much!
i’ve been struggling all day with a very similar practice question for my finals on friday. this made it so much easier to understand although english isn’t my native language. thank you!
isn't it suppose to be that the first carbon will be the tertiary carbocation since it is the one connected to 3 carbons (1 from C 6, 1 from C 2 and 1 from methyl)? And carbon 2 is the secondary carbocation?
Here's an idea: Do you know about JEE Mains and JEE Advanced entrance examination which is held in India? Approximately 1.3 Million students across India appear in JEE Mains and your playlists have nearly equal content as per the syllabi of that exam. If you organize your videos and tag JEE along with it, you'll get a million views and it'll really be helpful for students. You can google JEE to know more about the exam and syllabus. You teach exceptionally well! Thankyou.
Love the videos! thank you very much love whatever software your using as well. I would show the H30+ if I could but my professor is picky so I'm going to have to use H2SO4 or H3PO4, but your explanation makes it a lot easier thank you.
At around 2:20, if the water molecule is gaining electrons from the H+ ion, why is it called a nucleophile? Shouldn't it be called an electrophile? Sorry i'm just very confused!
H+ does not have electrons. When looking at nucleophile vs electrophile, look at the molecule prior to any attack. If a water has lone electron pairs available TO attack, it is considered the nucleophile. If hydronium has an extra H+ able to accept electrons it is considered the electrophile
Thanks so much for thisI really, really appreciate itI publish a lot of content and don't always catch errorsSo I count on students like yourself to help me keep an eye outThanks so much!
All your videos are awesome!! I wish you were my professor. But I realized that you never made a video based on Oxymercuration demercuration and hydroboration, cyclopropanation. Also, Im failing organic chem and I was wondering if you can tutor me online :)
+Leah Fisch So you're telling me that you can tutor people online(by making videos in a flow, or screen sharing) but you cannot do it for the whole. It's gonna take you the same amount of time, and will benefit many. Not everyone can pay that much amount and you never know if someone that can't pay is more willing to learn. I'm not disrespecting you or anything, I know you have to make a living as well. But just consider this. The videos are great and very well explained. I'm sorry if I've hurt you in any way.
I appreciate what you're saying, but I hope you can understand that I have a business to run and employees to pay. My RUclips videos are only a part of what I do, but I have to leave most of my time to my paying students.
for the symmetrical alkene, when the second water molecule came in and acted as the nucleophile and attacked the positively charged carbon, why did the product of that not include the Hydrogen on the second carbon which was a result of the first reaction? Overall your videos were very helpful thankyou!
It actually still does include that hydrogen! Just because I didn't specifically draw it there, doesn't mean it is not present. Remember that when we draw line structures, we are actually able to ignore the hydrogen atoms present and only show carbon to carbon bonds or bonds to other electronegative atoms like oxygen. For more on bond-line notation, make sure to go back and see this video: ruclips.net/video/chsPHGOepns/видео.html
I'm sorry, but I don't offer tutoring through RUclips comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
I'm confused. If alcohols undergo substitution reactions (and an alcohol group is protinated forming the oxonium ion intermediate), why are oxonium ion intermediates required?
alcohols make poor leaving groups. In the context of a substitution reaction the alcohol is protonated to an oxonium to turn it into a good leaving group for a neutral water molecule once it breaks away
HSO4- is a negative spectator ion in solution and disregarded when viewing our final mechanism product. In fact, H2SO4 is such a strong acid, it dissociates in solution BEFORE the mechanism even begins and so is not part of the net reaction
Overall yes, the addition to an asymmetrical alkene undergoing a carbocation intermediate WILL follow Markovnikov's rule. However, Markovnikov's rule tells us that the nucleophile (not H) will add to the more substituted carbon. This has to do with the stability of the carbocation intermediate as I explain in this video, and my other video specifically about Markovnikov's rule
There are hydrogen's everywhere. It can be assume that any octet rule not satisfied is filled with -H on carbons and lone pairs on oxygen for example. They do not always need to be drawn and typically are not. Just don't let that confuse aldehydes and ketones where one R- is just methyl
You don't have to show hydrogen on line structure. I show them in the first step so you can follow where they add, then they join the other invisible/implied hydrogens so we can focus on the next steps
It's called the stability of carbons. The number of carbons attached to a carbon is equal the degree of whatever it is. 3 C+ is the most stable while 1 C+ is least. This applies only to assymetrical reaction.
I stared at my notes for about an hour and couldn't' figure out a single thing until I saw this video. Thanks for making everything easy to understand!
You're so welcome! I'm happy my video helped clear things up for you!
I must say... I have my test tomorrow. I was clueless until about 20 minutes ago when I discovered your videos. I never even comment on youtube but these are so amazing I felt the need. You deserve a medal.
How'd your test go
I hope your test went well!
Aww thanks so much! I'm so glad I helped clear things up.
Hey Leah! Remember me? I got a 94/100 on my orgo midterms. Now I have my final on monday. Thank you so so much for your videos. They're extremely helpful!!
You're very welcome, happy to help!
You explained this better than my book or professor. Thanks!
You're very welcome!
This makes so much sense now. I love that you gave explanations for why things were happening the way that they were. I am excited about trying this mechanism on my own!
You're so welcome! I'm glad that my explanations helped you clear things up.
You're the best! I watched almost all of your videos over the course of a week for my final tomorrow. I was hopeless, but now I have a fighting chance. Thanks so much!
I'm so happy I could help!
i’ve been struggling all day with a very similar practice question for my finals on friday. this made it so much easier to understand although english isn’t my native language. thank you!
You're welcome! Happy to help.
You explain everything really well, wasn't lost once, thank you!
You're so welcome!
Great explanation as always!
Thank you, glad you like it!
Your videos are so helpful, thank you!
You're very welcome!
Found your channel today and it’s so informative. Thankyou!
You are so welcome!
you are a great teacher. such a lifesaver for my midterm tomorrow.
Yay, happy to help!
You are really a darling. You have saved my life. God bless you!❤
Glad I could help, thanks!
hey Leah thanks for the video it's really helpful. and your explanation is awesome. try to make videos on inorganic as well😃
+Leah Fisch oh! we need more of you... seriously your explanation is awesome....keep it up
You're so welcome, happy to help!
isn't it suppose to be that the first carbon will be the tertiary carbocation since it is the one connected to 3 carbons (1 from C 6, 1 from C 2 and 1 from methyl)? And carbon 2 is the secondary carbocation?
Exactly, but she was labeling the overall molecules as to which had 2° vs 3° carbocations, not labeling the carbon next to that label.
Thank you so much for taking the time to do these videos so so helpful.
You'revery welcome!
These videos on alkenes are well explained. Thankyou
You are welcome!
well and simply explained!u are the best!
Aww thanks!
Really awesome video thanks a ton!!! many problems which were unclear in the books were visualized at its best :)
You're very welcome, happy to clear things up!
Vry good explanation in a simple way...I appriciated...ALL D BEST..
You're so welcome, glad you liked it!
Great video, but what happen to the H on the less substituted carbon right before you added the first water on the second example
it's not required in line structures to draw hydrogens. it is still there just not drawn
@@emilyreeve9839 Exactly this
It's there but not showed, H is understood as invisible on line structure
Here's an idea: Do you know about JEE Mains and JEE Advanced entrance examination which is held in India? Approximately 1.3 Million students across India appear in JEE Mains and your playlists have nearly equal content as per the syllabi of that exam. If you organize your videos and tag JEE along with it, you'll get a million views and it'll really be helpful for students. You can google JEE to know more about the exam and syllabus. You teach exceptionally well! Thankyou.
I do know a lot about JEE and many JEE students use my resources to help them along the way, both my orgo and my MCAT materials.
Watching your video to understand mechanism FROM INDIA 🇮🇳
Happy to help!
Love the videos! thank you very much love whatever software your using as well. I would show the H30+ if I could but my professor is picky so I'm going to have to use H2SO4 or H3PO4, but your explanation makes it a lot easier thank you.
You're so welcome, and of course you must use what your professor wants
At around 2:20, if the water molecule is gaining electrons from the H+ ion, why is it called a nucleophile? Shouldn't it be called an electrophile? Sorry i'm just very confused!
H+ does not have electrons. When looking at nucleophile vs electrophile, look at the molecule prior to any attack. If a water has lone electron pairs available TO attack, it is considered the nucleophile. If hydronium has an extra H+ able to accept electrons it is considered the electrophile
very clear and concise. thank you!
You're very welcome!
At the 3:22 mark, can you change the word "tubutin" in the caption to 2-butene? Thanks!
Thanks so much for thisI really, really appreciate itI publish a lot of content and don't always catch errorsSo I count on students like yourself to help me keep an eye outThanks so much!
bless youu!! THANKS you're a wonderful human being
You're very welcome! And thanks for your kind words!
All your videos are awesome!! I wish you were my professor. But I realized that you never made a video based on Oxymercuration demercuration and hydroboration, cyclopropanation. Also, Im failing organic chem and I was wondering if you can tutor me online :)
+Leah Fisch So you're telling me that you can tutor people online(by making videos in a flow, or screen sharing) but you cannot do it for the whole. It's gonna take you the same amount of time, and will benefit many. Not everyone can pay that much amount and you never know if someone that can't pay is more willing to learn. I'm not disrespecting you or anything, I know you have to make a living as well. But just consider this. The videos are great and very well explained. I'm sorry if I've hurt you in any way.
I appreciate what you're saying, but I hope you can understand that I have a business to run and employees to pay. My RUclips videos are only a part of what I do, but I have to leave most of my time to my paying students.
Gracias!! desde Puerto Rico! :) Very Good Explanation
:) All about the reactions of alkenes. I'm going to read now about the addition of a Peroxyacid to an alkene.
Glad you liked it!
This helped me thank you so much 🙏
You're so welcome!
Great video, thanks :)
Glad you liked it!
Appreciate your efforts 🙏
Happy to help!
Hey Leah! Isnt the tertiary carbocation on C 1 and the secondary carbocation on C 2?
At which specific point in the video? (Timestamp please)
You are an amazing teacher and I want yoou to know that 💝💖💗💞💕❣
Aww, thanks!
You're awesome! Are you in California? I'm a human bio major at UCSD. Thank you very much.
Nope, on the other side of the country :) You're very welcome!
I am learning so much by watching your videos. The book is really confusing.
Thank you for the feedback. :)
for the symmetrical alkene, when the second water molecule came in and acted as the nucleophile and attacked the positively charged carbon, why did the product of that not include the Hydrogen on the second carbon which was a result of the first reaction? Overall your videos were very helpful thankyou!
It actually still does include that hydrogen! Just because I didn't specifically draw it there, doesn't mean it is not present. Remember that when we draw line structures, we are actually able to ignore the hydrogen atoms present and only show carbon to carbon bonds or bonds to other electronegative atoms like oxygen.
For more on bond-line notation, make sure to go back and see this video: ruclips.net/video/chsPHGOepns/видео.html
on the 2nd carbon does it have now h2? on the benzene and on the tertiary it has H and OH??
I'm sorry, but I don't offer tutoring through RUclips comments. For help with this and more, I recommend joining the organic chemistry study hall. Full details: leah4sci.com/join
I'm confused. If alcohols undergo substitution reactions (and an alcohol group is protinated forming the oxonium ion intermediate), why are oxonium ion intermediates required?
alcohols make poor leaving groups. In the context of a substitution reaction the alcohol is protonated to an oxonium to turn it into a good leaving group for a neutral water molecule once it breaks away
leah4sci is a boss
Thanks!
I have a doubt🙏 You said their should be no negative charges but their was HSO4-😣please help
HSO4- is a negative spectator ion in solution and disregarded when viewing our final mechanism product. In fact, H2SO4 is such a strong acid, it dissociates in solution BEFORE the mechanism even begins and so is not part of the net reaction
thank you! ( Greetings from Israel!)
You're very welcome!
Isn't the addition of hydrogen to unsymmetrical alkenes follows markovnikon's rule
Overall yes, the addition to an asymmetrical alkene undergoing a carbocation intermediate WILL follow Markovnikov's rule. However, Markovnikov's rule tells us that the nucleophile (not H) will add to the more substituted carbon. This has to do with the stability of the carbocation intermediate as I explain in this video, and my other video specifically about Markovnikov's rule
Thank you so much
You're very welcome!
crystal clear
Glad you liked it!
Love u Leah
Thank you!
U r amazing😚💖💖💖💖💖💖
Thanks so much! :)
Thanks!! ❤️
Welcome!
GOOD TEACHING
Glad you think so!
rarrangement tho...and what if methanol?
If methanol is the nucleophile, your final product would have a methoxide group instead of an alcohol.
8:27 where did the H on the second carbon go?
IT was not mentioned because carbon valency got satisfied
There are hydrogen's everywhere. It can be assume that any octet rule not satisfied is filled with -H on carbons and lone pairs on oxygen for example. They do not always need to be drawn and typically are not. Just don't let that confuse aldehydes and ketones where one R- is just methyl
You don't have to show hydrogen on line structure. I show them in the first step so you can follow where they add, then they join the other invisible/implied hydrogens so we can focus on the next steps
u are the best
Thank you :)
thank you 😊😊
You're very welcome!
Thanks a lot :)
You're welcome!
how do u know it's a 2° C+ or a 3° C+?😥😥
no: of carbons attached to a carbon = degree.
It's called the stability of carbons. The number of carbons attached to a carbon is equal the degree of whatever it is. 3 C+ is the most stable while 1 C+ is least. This applies only to assymetrical reaction.
Use my pencil trick as I teach here: leah4sci.com/pencil-trick-for-classifying-primary-secondary-and-tertiary-carbon-atoms/
you are great
Thanks!
Thanks.
You're very welcome!
I owe you a tuition payment
lol, I'll take a thank you instead :)
I have a doubt
What about?
Please help me
What type of help are you looking for?
nice
glad you like it
yu are fabulous
Aww thank you
you sound like Selena Gomez
I take that as a compliment, thanks!
And i subscribe your channel
Thanks so much!!
Your videos are very helpful, thank you!
You are welcome!
@@Leah4sci I am glad that you replied to me. I was following many of your conceptual videos and they really help me out.