I am currently taking organic chemistry......can you explain why the substiuent CH3 on C5 for the chair conformaiton is in the axial position. I though the vertical position on the cycloalkane meant Cl would be in axial position on the chair conformation. ( so I thought Cl should be axial and the wedged CH3 should be equatorial)
It is possible to draw a chair conformation with the Cl in the axial position, as you've suggested, but this would be a different chair conformation than the one I chose to draw. I chose (at 7:49) to draw the more stable chair conformation, which puts the bulky t-butyl group in the equatorial position. Once I'd made the choice to put the t-butyl group (on C1) in the equatorial position, that fixes the axial/equatorial orientation of all other substituents. We can see in the planar representation that the t-butyl group and the Cl are both wedges; this means that they are on the same side of the ring (which I refer to as the 'top' of the ring). At 8:19 I drew in the two possible substituent orientations off of C5 in the chair. Since the Cl must be closer to the 'top' of the ring, just like the t-butyl group, I must place it on the upper (i.e. equatorial) position. This leaves the CH3 group in the lower axial position. Had I originally put the t-butyl group in the axial position, then my chair would have had the Cl in the axial position and the CH3 in the equatorial position (i.e. I would have gotten the chair flip of the chair I finished drawing at 8:27).
Imagine yourself standing slightly to the right of the molecule such that carbon 2 is the closest to you and carbon 5 is the furthest (go back and look at the 3D model in the first minute of the video if you're having trouble imagining what this looks like in three dimensions). When looking from this angle, carbon 1 (with Br straight up) is to your left in the front and carbon 3 is on your right in the front. Carbon 6 is in the back left (directly behind carbon 1) and carbon 4 is in the back right (directly behind carbon 3). You might also find the 3D model at molview.org/?cid=8078 helpful to spin around to see how this perspective works. Does this help?
I had so many problems converting newman into chair so this helped a lot/ Thanks!
Glad that you found it helpful :).
*Tough Converted To Simple And Elegant Concepts . Thank You , Keep Creating Great Content Related To Chemistry.*
Is it just me or does she kinda sound like a magician when shes doing the double new man projection? :)
Best explanation!
thank you very muchh, i had problems with my homework. Very good job :D
This is perfect! Best video I have found so far
thank you so much! this was very helpful :)
That was so helpful!
thanks a lot!
Thank you!
Tu kya mast kam krta h maksud bhai
Very helpfull video
I am currently taking organic chemistry......can you explain why the substiuent CH3 on C5 for the chair conformaiton is in the axial position. I though the vertical position on the cycloalkane meant Cl would be in axial position on the chair conformation. ( so I thought Cl should be axial and the wedged CH3 should be equatorial)
It is possible to draw a chair conformation with the Cl in the axial position, as you've suggested, but this would be a different chair conformation than the one I chose to draw. I chose (at 7:49) to draw the more stable chair conformation, which puts the bulky t-butyl group in the equatorial position. Once I'd made the choice to put the t-butyl group (on C1) in the equatorial position, that fixes the axial/equatorial orientation of all other substituents. We can see in the planar representation that the t-butyl group and the Cl are both wedges; this means that they are on the same side of the ring (which I refer to as the 'top' of the ring). At 8:19 I drew in the two possible substituent orientations off of C5 in the chair. Since the Cl must be closer to the 'top' of the ring, just like the t-butyl group, I must place it on the upper (i.e. equatorial) position. This leaves the CH3 group in the lower axial position. Had I originally put the t-butyl group in the axial position, then my chair would have had the Cl in the axial position and the CH3 in the equatorial position (i.e. I would have gotten the chair flip of the chair I finished drawing at 8:27).
can we put CH2 between the two circles ? do u get it
6:18 at 5 and 2
How is it that Br is the attached to the front carbon when viewing it from the given perspective 5:32?
Imagine yourself standing slightly to the right of the molecule such that carbon 2 is the closest to you and carbon 5 is the furthest (go back and look at the 3D model in the first minute of the video if you're having trouble imagining what this looks like in three dimensions). When looking from this angle, carbon 1 (with Br straight up) is to your left in the front and carbon 3 is on your right in the front. Carbon 6 is in the back left (directly behind carbon 1) and carbon 4 is in the back right (directly behind carbon 3). You might also find the 3D model at molview.org/?cid=8078 helpful to spin around to see how this perspective works. Does this help?
So does it means,, we'll get different Newman projection if we see the structure from different angles?
That's absolutely correct. You will get different, but equivalent (and equally correct) Newman projections if you look from a different perspective.
@@Chemistry123 thankss!it helps a lot
amazing
u saved me 😭