A-Level Further Maths F5-07 Intersections: Finding the Distance from a Point to a Plane

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[@noonesherem8782]

this method is so much better than the one in the cgp revision guides. Thank you!

[@Mathspaperks1ks2]

Congratulations sir on 46k sir.

[@kabelan9660]

can't you just use that formula your given in the Edexcel formula booklet

[@TLMaths]

Yes you can, but this topic comes up in the DfE guidance document before the Vector Product does. So I show here how you can do it without the vector product, and then I develop the vector product in the next section.

[@submission8431]

Have you (or if not, would you) consider doing a playlist on Teaching GCSE Maths for all the major exam boards? May you link the playlist if you have covered all of GCSE mathematics already. Ty

[@TLMaths]

I have an old spec Foundation playlist? Thing is that I don’t teach GCSE Maths so it’s not a priority and it would be a BIG job!

[@sxwayxx7606]

Could you do some videos about finding distances using vector product please?

[@TLMaths]

Vector Product will be all in the next section

[@leahlester2620]

Hi Sir, do you know what paper these Pure questions are from:
prove by contradiction that there are no positive integers a and b with a odd such that a+2b = √(8ab)
and
A piece of jewellery used in a brooch is in the shape of a segment of a circle. The segment itself is made from the silver metal which costs £1.90 per cm2 It is bordered all the way around by a gold metal trim which costs £2.30 per cm. If the radius of the circle is 4 cm and the angle subtended at the centre is 2π/3 radians, find correct to the nearest penny the cost of the jewellery piece.
I cant find the mark scheme. thanks

[@TLMaths]

I don’t recognise them I’m afraid

[@leahlester2620]

@@TLMaths ok thank you, how would you approach the jewellery question - differentiation rates of change? its a 10 marker

[@TLMaths]

Don't you just want to find the perimeter of the segment by finding the arc length (using theta x r) + the length of the triangle (using cosine rule), then multiply by (1.90+2.30)?

[@leahlester2620]

@@TLMathsoh ok i thought that was too simple for 10 marks

[@TLMaths]

Wait a minute, I misread the question - I didn't spot the squared on the units for the silver. So the area of the segment is £1.90 per cm^2.
So you want to find the area of the segment in cm^2 and multiply that by £1.90, then find the perimeter of the segment in cm and multiply that by £2.30.