A-Level Further Maths F3-07 Scalar Product: Re-Introducing the Cartesian Equation of a Plane
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- Опубликовано: 12 сен 2024
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i was in shock when i actually understood how this all related back to the plane equation. Genius
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so helpful, thanks
Hi I asked this question and forget the answer sorry and I can't find the original comment where I asked, what should I remember/get familiar with for the AQA large data set?
I made this video on it: ruclips.net/video/-3Shq9HDIOo/видео.html
i was told d is equal to a dot n, not -a dot n
Depends if you write n_1x + n_2y + n_3z + d = 0 (as I did in the video), or n_1x + n_2y + n_3z = d
@@TLMaths Which do you use for calculating the distance from a point to a plane? a.n=d or -a.n=d
@@Tom-hp4bq The distance from (p,q,r) to the plane ax+by+cz+d=0 is |ap+bq+cr+d|/sqrt(a^2+b^2+c^2)
@@TLMaths
Should you use:
ax+by+cz+d=0 (-a.n=d)
and
ax+by+cz=d (a.n=d) ?
With these two equations d can either be positive or negative, which do you use when calculating the distance from a point to a plane? Sorry I'm just quite confused
@@Tom-hp4bq You just need to rearrange ax+by+cz=d into the form ax+by+cz+d=0 by subtracting d from both sides, then you can use:
The distance from (p,q,r) to the plane ax+by+cz+d=0 is |ap+bq+cr+d|/sqrt(a^2+b^2+c^2)