A full lesson within a 6 min.....just understood well!!! Thank you so much ......i have watched my teacher's recording too but I was unable to understand 💖
That's what I have trouble with. Basically you need to see which bits cancel out. For instance, if a grouping has one bit that is A'B and another bit that is AB, then the A cancels out leaving just B. Another way to look at it is if there is an odd number of one type of state and an even number of its complement, then that state is part of the final term. If there is an even number of a state and its complement, then that state gets cancelled out.
If the state changes then ignore it but if not count it. Look at the sets of two numbers together to the right of AB and below CD (i.e. 00, 01, 11, 10). For example - Red bit (AB and CD are changing states): AB AB 01 -----> 11 A goes from 0 to 1 (ignore it) B goes from 1 to 1 (keep it) ---> 1 = B CD CD 00 -----> 01 C goes from 0 to 0 (keep it) ---> 0 = C' D goes from 0 to 1 (ignore it) Final expression for red bit - BC' ________________________________________ Green bit (Only CD are changing states): AB AB 01 -----> 01 A goes from 0 to 0 (keep it) ---> 0 = A' B goes from 1 to 1 (keep it) ---> 1 = B CD CD CD CD 00 -----> 01 -----> 11 -----> 10 C goes from 0 to 0 to 1 to 1 (ignore it) D goes from 0 to 1 to 1 to 0 (ignore it) Final expression for green bit - A'B ________________________________________ Magenta bit (Only B is changing states): AB AB 00 -----> 01 A goes from 0 to 0 (keep it) ---> 0 = A' B goes from 0 to 1 (ignore it) CD CD 11 -----> 11 C goes from 1 to 1 (keep it) ---> 1 = C D goes from 1 to 1 (keep it) ---> 1 = D Final expression for magenta bit - A'CD Final Final expression - E = BC' + A'B + A'CD Hope that helps!
Is (AB)' = A'B' in karnaugh map? Cos I think for the first part, (AB)'CD , we should enter 1 in three places i.e when A=B=0 and A=0,B=1 and A=1,B=0 and C=D=1
It's easier if you write out the letters of each group, I do them on top of each other. Now eliminate the values that differ (ie. a group of four having A and A-Not varying throughout but BCD consistent then becomes just BCD). If you have more than one group, you continue on in the equation by +'ing it (BCD + AD + etc..). Once you're good enough you can map more quickly using 1's and 0's. I still just write it out
Each bit listed is one bit apart in all directions. Even wrapping around from one end to the other. So 00, 01, 11, 10 | 00, 01, 11, 10 | ... Note that you aren't counting. You are just making sure that each category is different by only 1 bit. So even though 01 is 1 and 11 is 3, they only differ by 1 bit. If you so 01 then 10 (2), they would differ by 2 bits (both bits need to swap states).
WOW!! in 6 minutes I understood more than in 6 hours with a university professor, congratulations
you have a shitty professor
@@edwardwhite8253
no, he was sleeping
nobody:
absolutely nobody:
comment section on every math tutorial : "WOW!! in x minutes I understood more than in x hours with a university professor,
I get this stuff in college....
Same, i dint understood it in 4 hr of courses, i had it explained to me in a damn hard and complicated way, but this video saved me.
I finally get after going through all indian tutorials and listening my recorded teacher's explanation. This is just a simple explanation.
🚳
this is the best explanation ive heard between tutor and multiple professors. thanks
thanks sir
you explained better than my teacher.
i needed this
much thanks
The only clear explanation on RUclips about KMaps. Thanks!
Thank you sir. You saved my class from bad test results!
Dude you just explained in 5 minutes what some nerd teacher would explain in a hour, good job and Thank You
A full lesson within a 6 min.....just understood well!!! Thank you so much ......i have watched my teacher's recording too but I was unable to understand 💖
Hey man i have an exam tomorrow, your example really helped me, thank you so much. Better than my teacher tbh i got the concept in 6 mins.
we have in 3 hrs
Same here!!!
Thanks man. Its at least my 8th time forgeting and relearning them. This was a real quick memory refresh :)
Thank you for posting this. I learned how to simplify Boolean expressions using Kavanaugh maps several years ago and had since forgotten how to do it.
very straightforward, reviewing this before my digital systems exam. thank you!
I have an exam tomorrow morning and this definitely helped! Lecturer taught this weird
YOU'RE A LIFE SAVER! I have an exam tomorrow and your video helped a lot! thank you Sir!
how did your exam go?
I really struggle with the grouping bit. I don’t get how you figure out the expression after grouping
That's what I have trouble with. Basically you need to see which bits cancel out. For instance, if a grouping has one bit that is A'B and another bit that is AB, then the A cancels out leaving just B.
Another way to look at it is if there is an odd number of one type of state and an even number of its complement, then that state is part of the final term. If there is an even number of a state and its complement, then that state gets cancelled out.
If the state changes then ignore it but if not count it. Look at the sets of two numbers together to the right of AB and below CD (i.e. 00, 01, 11, 10).
For example -
Red bit (AB and CD are changing states):
AB AB
01 -----> 11
A goes from 0 to 1 (ignore it)
B goes from 1 to 1 (keep it) ---> 1 = B
CD CD
00 -----> 01
C goes from 0 to 0 (keep it) ---> 0 = C'
D goes from 0 to 1 (ignore it)
Final expression for red bit - BC'
________________________________________
Green bit (Only CD are changing states):
AB AB
01 -----> 01
A goes from 0 to 0 (keep it) ---> 0 = A'
B goes from 1 to 1 (keep it) ---> 1 = B
CD CD
CD CD
00 -----> 01
-----> 11 -----> 10
C goes from 0 to 0 to 1 to 1 (ignore it)
D goes from 0 to 1 to 1 to 0 (ignore it)
Final expression for green bit - A'B
________________________________________
Magenta bit (Only B is changing states):
AB AB
00 -----> 01
A goes from 0 to 0 (keep it) ---> 0 = A'
B goes from 0 to 1 (ignore it)
CD CD
11 -----> 11
C goes from 1 to 1 (keep it) ---> 1 = C
D goes from 1 to 1 (keep it) ---> 1 = D
Final expression for magenta bit - A'CD
Final Final expression - E = BC' + A'B + A'CD
Hope that helps!
Phil Guitar Thank you!
@@philguitar3058 thank u sm this was very helpful!!
@@Undertakerfan700 You're very welcome!
Is (AB)' = A'B' in karnaugh map?
Cos I think for the first part, (AB)'CD , we should enter 1 in three places i.e when A=B=0 and A=0,B=1 and A=1,B=0 and C=D=1
Isn’t it gonna be redundant if we use it that way?
MatthewMatosis here teaching boolean algebra like a boss
based on De morgans (AB)'=A'+B' .Why did you split it like A'*B' ?
the best of all time
Logic gate..... Circuit diagram slow ka video h??????
I still dont get how to get the final formula
It's easier if you write out the letters of each group, I do them on top of each other. Now eliminate the values that differ (ie. a group of four having A and A-Not varying throughout but BCD consistent then becomes just BCD). If you have more than one group, you continue on in the equation by +'ing it (BCD + AD + etc..). Once you're good enough you can map more quickly using 1's and 0's. I still just write it out
@@brianfincher8354 ur comment makes it more clear to me 🙂
how is a table of truth not needed for this kind of question? i'm really confused even i can solve it
I understood more in this 6 minute video than in my 2 hour class 😮
(I fell asleep, that might have done something to do with it hehe)
Thank you,I learned very quickly with your help!
Sir what is non prime implicant in kmap
what is the logic behind numbering of the Karnaugh maps
Each bit listed is one bit apart in all directions. Even wrapping around from one end to the other.
So 00, 01, 11, 10 | 00, 01, 11, 10 | ...
Note that you aren't counting. You are just making sure that each category is different by only 1 bit.
So even though 01 is 1 and 11 is 3, they only differ by 1 bit. If you so 01 then 10 (2), they would differ by 2 bits (both bits need to swap states).
This is called Gray Code, and it makes sure that each combination in the sequence differs by only one bit.
Why complements are 0 and variables are 1/true?
Thanks Dr🙏🙏 Ive exam at 1
Thank you very much for your help 🤩!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
An amaizing video! Thank you so much!
Thank you so much... your explaination really great..
Short and sweet!!
fire shit bro💪🏾💯
How to find which grp is to take first
Does not matter
perfect explanation!!
Well explained :D
cool so Karnaugh maps simplify logic statements
amazing keep going
THANK YOU FOR THIS
Very good, thank you
Great explanation. Thanks
Running the video at 1.5x speed helps alot.
Thank you, very helpful. :)
Mind blown
Thankyou so much..🙏🙏..
You Are Great..
Thank you. Very helpful
i love you ❤
Thank you daddy
thank sir from india
thank you sir.
thank you
thanks so much!!!
Thank you!
Thanks for nine tutorial
Thanks man
thanks a lot
if you still do a wrong k-map, lets troubleshoot your maths by watching:
ruclips.net/video/5_dxk2FqEnY/видео.html&t
make video on one hot encoding
Thank u sir
A'CD + A'B + C'B
i cannot understand
oti naneeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
u r English is good for today but not sufficient for tommorow
Said by an Indian ha ha
lol bruh...
give me my 6 minutes back
I watched this in 2024 and thanksss alotttt u made it clear for me 🤍
Thank you!
thank you
Thank you!