Chapter 2 - Motion Along a Straight Line
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- Опубликовано: 16 июл 2024
- Marymount Physics Chapter 2 Videos supplement material from the textbook Physics for Engineers and Scientist by Ohanian and Markery (3rd. Edition) (books.wwnorton.com/books/Physi...) Feel free to post questions and/or suggestions in the comments and I'll respond if possible. The videos are mostly for my students, but since others seem to find them useful I'll help as much as I possibly can!
Amazing lecture, I was so lost in class do to unorganized lecture from my professor but this explanation cleared all my confusions. Thank you for posting.
You just saved me $40 in tutoring!! Thnx so much
Excellent video, nice pace and step by step descriptions. Thank you!
this platform is the best and so helpful we greatly appreciate
please make more videos like this
its so clear and necessary..appreciated!!!
love from India.
Thank you so much! This video helped helped me understand the equations used in chapter 2.
I have a physics exam in 2 days. Thanks, man
A body is moving with a constant acceleration , a, along the x-axis. Its initial velocity is Vo and covers a distance x in time from its original position x . Using calculus,, derive the following equation of motion V=Vo+at
Thank you for this video. It helps me a lot :)
god bless you man you helped me understand what my professors couldn't explain your'e tha goat
You're a great professor.
maybe doing some sample problems for every equation .. physics.. easy to forget equations without samples..xD
Thanks a lot Dr ❤️
thank you very much this video helps me alot...
That was the power rule! (28:04ish). But seriously, this video was awesome! I get it much better now!
Thanks a bunch!
How do we come to know about what terms are to be included in the bracket, while carrying out the power rule?like, at 29:50, while solving for 'v', we put 'a' outside the bracket, as a result, it is not multiplied by 2.So, that makes a huge difference.
If you have further questions on the material in the lectures, feel free to comment and I'll answer if I can!
+MU Physics and Astronomy where i can find examples with explanation
Thank U very much for this :))
Was excellent, please can we have that of calculus and integration?
thank you
I'm using principles of physics tenth edition but i'm struggling with questions of this book. I wanna know what are your thoughts about the book or should i just buy physics for engineers and scientists
If your point of origin is 1 on y axis and you are at 4 at point B then is your distance not 4 points but rather 3?
at 21:35 since t=1 we should be able to replace t with 1 and find out the answer would be 4,626 m/s ? am I right?
Tq sir for making this video.. Blessed from India🇮🇳
that is very good
Thank you.. you explain very well better than my current professor who just rushes during lecture and doesn't explain what letter means or what he did. Subscribed
Is there videos for chapter 6 and chapters ahead
Hello! I have a question!!
But before I ask, Thank you for the videos!! You're helping me more than my professor! But anyway, when writing out the equations for constant acceleration. you wrote 't' but added 'delta-t' after. I know you said they're the same but I wanted to ask if 'delta-t' means 't2-t1'? Like what you said for velocity = 'delta-x'/'delta-t'.
You are correct. delta-t = t2-t1
17:44 T1-T2 and D1-D2
Can u please help to derive this equation for me
20:15 into the video you subtracted 1 power from t^2. Is that because you are looking for the velocity at t=1 or are you just getting the derivative of 2,375t^2?
he is doing the derivation of the first equation to get the V.
Thank you so much. Really nice video. Helped me a lot (going straight into downloaded vid list). Only one thing i would like to point is that, shouldn't the 't^2-1' at 21:28. Be outside the bracket?? Coz, otherwise, it gets multiplied by 2.
What difference does it make even if it was outside brackets... It multiplication..... So no problem
U must be PRO now... Right??? 5 years is a looooong time....
Im buying this book now. Consider me as one of your virtual students. Ha Ha! :D
Thanks, helped me a lot!
Thank you. This was helpful. Only critical comment is you incorrectly referred to the power rule for derivatives as the product rule.
Thanks for catching that. I've added an annotation to clarify that. Silly Bubar...
it helps all kinds of students understanding
Is the solution completed at 22:17??
hey professor, im stuck on this question im trying to solve here i was wondering if you could help me out. what do i do if a question gives me 2 speed averages, and the total distance aswell, and its asking for the final speed average?
it gave me the first speed average which was for the time it took to get there and the second speed average was for how long it took to return and its asking for a final speed average
everything is awesome, but can you please write more faster?
cool video. but i have no ide which book you're referencing us too.
Blahblah ooo its in the description
What if I am not given the position function, and I'm only give the chart with time and position values; and the tangent line passing through points (x,y).
How can I find the instantaneous velocity?
If you aren't given a function and are given values you take the position and divide by the time at a particular instance to get the velocity.
@@ebubar1 very helpful, and very quick response!
Thank you so much professor. I an q college student fron California Lutheran University. I got stuck with this problem and I found your videos! Thank you again! 10/10
What's the programs used in this video please.?
Its Explain Everything - a virtual whiteboard application on ipad.
What book are you using?
I am using the following textbook. Its the lowest cost option that I could find that was pretty well written and clear enough for students to learn from! books.wwnorton.com/books/Physics-for-Engineers-and-Scientists/
@21:17 that save
can someone please explain to me where the 2 comes from @19:56
The 2 comes from the derivative, it's basically like the rate of change for displacement. The formula basically takes the exponent and multiplies by the value then subtract 1 from exponent. Phys 1411 btw?
When you say product rule you mean chain rule.
didn't u understand calculus method
*sakit sa ulo*
thank you
thank you