Jesus Christ THANK YOU !!!! I'm in a&p school rn took me 3 days of searching to find this video. hands down the BEST one I've seen . You drawing all over with the red boxes is exactly how my brain works!! thank you.
Tat was a great video. I had such a difficult time learning this in college. Your thorough approach was very easy to follow also I like the shortcut on the equivalent resistances. Thanks.
Thank you so much for this, this is really helping me through my electrical fundamentals for my diesel AAS! But I did have a question about the current, when you find all the currents for the parallel circuits, the resistors 1, 6, 7, and 12 world be 1.5 amps, correct? Because that current meets up after it passes through the parallel circuit?
Yes. The current leaving and entering the power supply must always be the same. If the current has only one path it will be the total current (1.5 A) and if the current has more than one path it will split up and the current entering a set of parallel resistors must equal 1.5 A and the same current will leave that set of parallel resistors. Also the highest currents will always flow in the lowest resistors.
NO! You can use 1/R = 1/R1 + 1/R2 or R = 1/(1/R1 +1/R2) both give the save results except for the first formula you must take the recipricol of 1/R to get R.
I typically use the electron flow convention (technically correct) in my lessons instead of the conventional current flow convention. In wires current (electron flow) actually moves from negative to positive and not the other way around. It really doesn't matter which method you use to analyze a circuit as long as you're consistent. www.allaboutcircuits.com/textbook/direct-current/chpt-1/conventional-versus-electron-flow/
Jesus Christ THANK YOU !!!! I'm in a&p school rn took me 3 days of searching to find this video. hands down the BEST one I've seen . You drawing all over with the red boxes is exactly how my brain works!! thank you.
Glad it helped!
Also used this for Basic Electric and airframe electric
Tat was a great video. I had such a difficult time learning this in college. Your thorough approach was very easy to follow also I like the shortcut on the equivalent resistances. Thanks.
Thanks Dorian for solving this circuit, without a single, stupid redraw!
Thank you so much for this video!!!!!!
Really good explanation just wish you could have color coded the final answers.
NICELY EXPLAINED!!
saving me for my physics test ❤❤❤
Thank you so much for this, this is really helping me through my electrical fundamentals for my diesel AAS! But I did have a question about the current, when you find all the currents for the parallel circuits, the resistors 1, 6, 7, and 12 world be 1.5 amps, correct? Because that current meets up after it passes through the parallel circuit?
Yes. The current leaving and entering the power supply must always be the same. If the current has only one path it will be the total current (1.5 A) and if the current has more than one path it will split up and the current entering a set of parallel resistors must equal 1.5 A and the same current will leave that set of parallel resistors. Also the highest currents will always flow in the lowest resistors.
There was something I didn't get after you did the parallel circuit and u have got resistance amount u just sum it all . Why is that ?
i wish u can make videos about electrical circuits(DC) appreciate it.Thanks for this! im ready for my quiz tommorow
Had this class for Calculations for the trades today and I’m hell bent on figuring out combined circuits and finding R V I P
Good learning example. What is the current through R8, R9, R10, R11?
.75 amps for all as shown at ruclips.net/video/EPt7RsLp54M/видео.html and ruclips.net/video/EPt7RsLp54M/видео.html
@@DorianMcIntire Thank you.
Thanks, thanks you so much! God Bless you. :)
Thank you so much
I had an easy understanding
This will help me prepare for part of my exam, thank you!
Thanks for commenting and sharing.
You saveth my life
Isn't it suppose to be 1/R=1/(1/R1 +1/R2) because it is stated in the law of series and parallel circuits???????
NO! You can use 1/R = 1/R1 + 1/R2 or R = 1/(1/R1 +1/R2) both give the save results except for the first formula you must take the recipricol of 1/R to get R.
Thank you for the video, very easy to understand
how can I know the current for R8 only?
7.5 volts/10 ohms (6 ohm + 4 ohm) = 0.75 amps which is also half the total current. You must go through the whole proess to find this value.
five 4-ohm resistors are connected so that their combined resistance will equal 5 ohms. How would you draw this circuit?
www.circuitlab.com/circuit/245n3uvnkh8c/connection-puzzle/
Hope this isn't homework. :-)
Just trying to figure it out..lol
Did you get the drawing link?
Yeah but I need to draw a series-parallel circuit. Kinda like the one in this video. I am not sure if understand the one in the link.
5 years ago... if you ever read this mister...
*I LOVE YOU*
Happy to help. Glad you found the video useful.
@@DorianMcIntire very useful video
you are just awesome
Thanks! Glad you enjoyed the video.
is this ac? is that why its flowing negative to positive?
I typically use the electron flow convention (technically correct) in my lessons instead of the conventional current flow convention. In wires current (electron flow) actually moves from negative to positive and not the other way around. It really doesn't matter which method you use to analyze a circuit as long as you're consistent.
www.allaboutcircuits.com/textbook/direct-current/chpt-1/conventional-versus-electron-flow/
You sure are one dank fellow my man
Danks - I mean - Thanks! Glad you enjoyed the video.
Amazing....great job...
Thanks! I really appreciate your comment :-)
Sir battery connection is rong no current flow
NO! The analysis is for electron flow as I explained in the video.
Noice!
This as to be the hardest exercise ever 😭😭😭
Saale Hindi Mai video banae kar
Guru wah!