Thermodynamic versus Kinetic Control

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  • Опубликовано: 24 дек 2024

Комментарии • 40

  • @sarahholland5980
    @sarahholland5980 4 года назад +4

    this made so much more sense than my professor or textbook. thank you!!!!

  • @vasanthakumarg4538
    @vasanthakumarg4538 4 года назад +5

    Crisp and clear explanation of concepts, well done and thank you

  • @jkpp.
    @jkpp. 10 лет назад +3

    Thank you so much. It's rare when I get that, "FUCK, I GET IT NOW" feeling. The clear explanation is much appreciated.

  • @joenyc
    @joenyc 13 лет назад +5

    you rock. thanks for the AMAZING explanation. i was clueless about the difference. now it all makes so much sense!

  • @sciencenerd8879
    @sciencenerd8879 8 лет назад +8

    Life makes sense again. Thank you!!!

  • @razasyed575
    @razasyed575 2 года назад

    my main man micheal evans coming to the rescue thank you!

  • @chiman3778
    @chiman3778 5 лет назад

    I just wanted to thank you for putting this together

  • @danielgladish2502
    @danielgladish2502 4 года назад +2

    Great explanation. What I don't understand is how the factor reaction time works? Like why does the kinetic product eventually convert into the thermodynamic product? No new energy is added to overcome the larger activation energy barrier of the thermodynamic product.
    Thanks!

    • @mevansthechemist
      @mevansthechemist  4 года назад +1

      Great question! You're absolutely right that no new energy is added, but keep in mind that the distribution of molecules in the reaction changes over time. It's all based on relative activation energies. Early in the reaction we have mostly the starting material (SM), which converts mostly into the kinetic product (KP) due to the lower activation energy leading to it. A little bit of thermodynamic product (TP) forms. Now, if we focus on the activation energies of the REVERSE reactions, we see that the KP reverts back to SM faster than TP. Thus, KP will eventually be funneled to TP due to its greater rate of reversion to the starting material.

  • @adosar7261
    @adosar7261 4 года назад

    If we change the temperature doesn't delta G of both reactions change? So how do we know that after changing the temperature p1 isn't more thermodynamicaly favorable than p2?

  • @oguzcangokce6959
    @oguzcangokce6959 2 года назад +1

    Thanks for the brief and clear explanation!

  • @jameelsahadath217
    @jameelsahadath217 9 лет назад

    how is kinetic control used to affect the outcome of a chemical reaction where several reaction paths are available

  • @panoskb9405
    @panoskb9405 7 лет назад +1

    If you have a reaction that A+B->C, and it is only reversible then the only conclusion that you can make is that is kinetically controlled right?

    • @mevansthechemist
      @mevansthechemist  7 лет назад +1

      If the reaction as a whole is reversible, it's thermodynamically controlled, not kinetically controlled. "Reversible" in essence means that the forward and reverse reactions are proceeding at equal rates; i.e., that the reaction system is in equilibrium (caveat: this is the organic chemist's "back of the envelope" definition. The definition in physical chemistry is more rigorous.)

  • @Hands4Surgery
    @Hands4Surgery 12 лет назад

    Is your activation energy correct? (0:20 - 0:25)
    I think activation energy is the whole value from the energy level of the starting material, all the way up to the peak of the transition state. Your second (right hand side) activation energy seems correct proceeding from left to right.

    • @mevansthechemist
      @mevansthechemist  7 лет назад +3

      Good question-for anyone still confused by this, note that the graph is showing two different reactions proceeding outward from the center. Thus, two separate activation energies are shown.

  • @Elevatone
    @Elevatone 11 лет назад

    What organic chemistry software is that? Link please?

  • @redarmuhammad1953
    @redarmuhammad1953 10 лет назад

    very nice explanation.. Thanks

  • @zaya421
    @zaya421 3 года назад

    I still can't get it.. 😢

  • @aoifewest
    @aoifewest 10 лет назад

    Great presentation. Thank you very much?

  • @sanadaltarawneh3550
    @sanadaltarawneh3550 Год назад

    Good stuff

  • @saritar8819
    @saritar8819 11 лет назад

    Thank you for simplifying it!

  • @RBaleog
    @RBaleog 13 лет назад

    Good explanation, thanks!

  • @ruthmasih9047
    @ruthmasih9047 2 года назад

    amazing! thanks so much.

  • @parkjane116
    @parkjane116 6 лет назад

    This helped a lot. Thank you so so much.

  • @TheBitili
    @TheBitili 14 лет назад

    Great,,,

  • @Aryan_sg
    @Aryan_sg Год назад

    Thanks bro 😉

  • @FatimaSayes-en5bc
    @FatimaSayes-en5bc 6 месяцев назад

    Finally i understood.

  • @jingyiang9786
    @jingyiang9786 5 лет назад +2

    CN2116

  • @davidbohadana8274
    @davidbohadana8274 10 лет назад

    Grate job!!!

  • @camichael74
    @camichael74 11 лет назад

    Thank you! great video.

  • @skyyward111
    @skyyward111 9 лет назад

    Thanks a lot! Very helpful!

  • @mmarycalvin6395
    @mmarycalvin6395 11 месяцев назад

    Thank you.

  • @arqumabdullah2462
    @arqumabdullah2462 3 года назад

    whose here from AAMC C/P SB #20

  • @anoopkumarsonar1001
    @anoopkumarsonar1001 8 лет назад

    Thanks Bro !

  • @LunaDanu1
    @LunaDanu1 8 лет назад

    thank you

  • @Ace0077
    @Ace0077 11 лет назад

    thanks, helped