Thq so much for a wonderful video...Tmrw i have to explain it and guide my frnds to perform it in laboratory...so this video helped me a lot...🥰 Thq so much
You provide us more and morer video which is very important for our laboratory work But........ I still waiting for analysis video of sugar percentage...... 🙏🏻🙏🏻🙏🏻
We already worked on Sugar percent but due to some unavoidable issues we are unable to complete the task. We will finish it as early as we can. Thanks for being with us.
when i did this experiment, i mixed 3.4g KOH+ 2ml distilled water+rest of ethanol to make upto 100 ml volume(0.5 N solution). I made this ethanolic KOH using directions I found on the web. Then I directly dissolved 1g oil sample in 50 ml of prepared mixture. It got clear only in 5 minutes. I prepared 0.5 N Hcl by adding 10ml in 250 ml water(37% Hcl). When I titrated, I was getting a very large saponification value(about 500). The formula I used is [(blank titre-sample titre)*56*normailty of KOH]/weight of sample. Can you tell me what am I doing wrong? And what is the purpose of the methods u have used like use of aluminium foil and initially boiling koh with ethanol?
Great video, can you explain what is function of reflux 1,67g KOH in 200mL absolute ethanol? Can we only use 6g KOH in 150mL absolute ethanol for preparing 4% ethanolic KOH? Thanks..
Reflux of ethanol with KOH followed by distillation is normally done to make the ethanol more active for this test. But you can just dissolve 6g in 150ml.
Hello. Thanks for the video. I just wanted to ask the importance of making a blank. And also, can distilled water together with the ethanolic potassium hydroxide solution be used as a blank?
1.How to find SAP value of solid state sample like alovera ? 2. Will the SAP value be same if I use sodium hydroxide? 3.Difference between KOH and NAOH? Please do reply
Good video! I got Dhatelo Seed Oil from Nepal. However, I am not able to find the SAP value. How can I use it for making soap without SAP value? Thanks.
Good work, keep it up. But how do you arrive at 4.1ml of HCl? I want to know its percentage purity and density and how you arrived at 4.1ml and must it be 0.5N? Can't 0.1N be used. Thanks as you reply
0.83ml HCl should be added to make 0.1N HCl solution and 4.1ml is added to make 0.5N HCl solution and make the final volume 100ml. Please watch our video for the preparation of 0.1N HCl. Video link: ruclips.net/video/lXzAB8woAd8/видео.html We used 37% HCl (fuming) of molecular weight: 36.46.
Some websites are showing this formula of saponificatio = 56.1×(A-B)×N÷W and some showing 28.05 ×(A-B)÷W I am confused, which is correct , what is difference.? Please reply
Both calculations are same. You will get the same result. Second equation, you mentioned, is simplified form of calculation. First mentioned calculation is the original calculation formula. You can use both.
We need to dissolve KOH in cold environment to prevent the vigorous reaction of KOH with ethanol which may lead to the loss of properties of KOH solution.
Martin Okyere, Thanks for your observations. You are right about error. We should use 100ml burette to avoid refilling. We have tried to refill it fast to avoid the error as we dont have 100ml burette.
When refluxing or heating the KOH and fat...the KOH disappears leaving something like a whitish powder. I then need to refill again with KOH. Why does this happen?
in the standard formula for SV, it uses the molecular weight of KOH (56.1g/mol), but in this method, it applies 28. 05? my question is what this number represents?
Mike Tyson, which standard formula are you talking about. In this test, we followed the AOAC 920.160 official method strictly. In AOAC 920.160 method, 28.05 is used in the equation, so we did.
@@MicroChemsExperiments This is because HCl concentration is 0.5 N. Basically the equation involved HCl concentration too. When it is 0.5 N Molecular wt of KOH is 56.1 which will eventually lead to the value of 28.05.
Ma’am .. as we are always taking 0.5 N HCl for saponification..then why we are getting different range of values for blank .Is there any range for blank value while using 0.5 N HCl .. pls reply
Sample flask contains sample, thats why during saponification, the concentration of KOH in sample is decreased, thus HCl is needed more in compared with blank.
Yes, because molecular weight decreases after hydrolysis & as the mol wt decreases SV in increase,so definitely SV of split fatty acid will be more than oil before hydrolysis.
@Goutam Gupta, this test method and calculation are strictly followed the AOAC 920.160 official method. AOAC given the calculation. The reason behind it is: Sample and blank are Titrated with the same concentration of HCl (0.5N), thats why 0.5 become minimized from each side of sample and blank.
@@amanueldaniel5342 You can prepare it without reflux but that can result in some error in the final result. The result will not be exact but can be considerable.
@@amanueldaniel5342 Just dissolve KOH pellets in absolute ethanol and skip the distillation step. Take help from this saponification video and just skip the distillation part and disoolve KOH in ethanol
You can prepare 0.5N HCl solution by followng our video: ruclips.net/video/lXzAB8woAd8/видео.html Just multiply the amount of HCl, needed to prepare 0.1N HCl, by 5. Then follow the whole procedure to standardize the solution.
@@MicroChemsExperiments Hi do you have any idea which tests are important for oil testing according to fssai? I mean on what parameters does fssai check the quality of oil, say mustard oil?
@@factxfact5549 To test an oil quality, you must go for the following tests: Peroxide value, iodine value, Free Fatty Acid and Acid Value, Rencidity, Saponification value, Unsaponifiable matter, RM value, Polensky Value, Moisture, Refrective Index, Density etc.
i have been looking for this for so long thank you so much
Mike tyson, It's pleasure. Stay with us
@@MicroChemsExperiments is it 28.05 or 28.5?? Where does it come from in the formula? Is it a factor??
Thq so much for a wonderful video...Tmrw i have to explain it and guide my frnds to perform it in laboratory...so this video helped me a lot...🥰 Thq so much
You are most welcome. Stay with us
thanks for your awesome tutorial.
But, How do I test the fats of snack items like chanachur/chips?
Waiting for this tutorials....
We already uploaded. video link for fat determination from chanachur: ruclips.net/video/24qWVLm7hhw/видео.html
thank you
Thanks
@@Biplob_BD.Officials Welcome
You provide us more and morer video which is very important for our laboratory work
But........
I still waiting for analysis video of sugar percentage......
🙏🏻🙏🏻🙏🏻
We already worked on Sugar percent but due to some unavoidable issues we are unable to complete the task. We will finish it as early as we can. Thanks for being with us.
Mam sample weight is 5gms, but u have concluded that xx mg ofKOH is required to saponify 1gm of fat or oil
Thank you for this vid. I just want to know, how do you handle these chemicals as waste after the analysis?
We take help from third party company who handle these waste chemicals to make it discardable to environment
Very perfect lab work👏👏👏
Thank you very much!
Thank you, I have one question, please what is 28.5 in the formula? thanks
Thank you.
You are welcome
Good work and great video. Can you do titre test for oil also?
We will try. Stay with us.
Thanks for your wonderful video and I wonder what the concentration of the NaOH that using to titration HCl 0,5N?
0.5N NaOH solution
when i did this experiment, i mixed 3.4g KOH+ 2ml distilled water+rest of ethanol to make upto 100 ml volume(0.5 N solution). I made this ethanolic KOH using directions I found on the web. Then I directly dissolved 1g oil sample in 50 ml of prepared mixture. It got clear only in 5 minutes. I prepared 0.5 N Hcl by adding 10ml in 250 ml water(37% Hcl). When I titrated, I was getting a very large saponification value(about 500). The formula I used is [(blank titre-sample titre)*56*normailty of KOH]/weight of sample. Can you tell me what am I doing wrong? And what is the purpose of the methods u have used like use of aluminium foil and initially boiling koh with ethanol?
Add 25 ml alcoholic KoH in each and heat both blank and sample for 1 hr you will got the best results
Thanks for the great video
Best channel
Thanks
Very informative video, now my all doubts regarding to this practical are clear.. thank you so much ❤️
Thank you. Stay with us.
Excellent explaination
Thanks
How are you video very helpful for us.
Can you make a video of P anisidine value. ( oxidation value)
Noted
Great video, can you explain what is function of reflux 1,67g KOH in 200mL absolute ethanol? Can we only use 6g KOH in 150mL absolute ethanol for preparing 4% ethanolic KOH? Thanks..
Reflux of ethanol with KOH followed by distillation is normally done to make the ethanol more active for this test.
But you can just dissolve 6g in 150ml.
Ok thanks a lot..
Great video plz make a video .how to check erucic acid in canola oil.
Hello. Thanks for the video. I just wanted to ask the importance of making a blank.
And also, can distilled water together with the ethanolic potassium hydroxide solution be used as a blank?
You must have to prepare blank as shown in this video
The reason for the blank is to account for any water present in the KOH.
@@billsmathers7787 Thanks
1.How to find SAP value of solid state sample like alovera ?
2. Will the SAP value be same if I use sodium hydroxide?
3.Difference between KOH and NAOH?
Please do reply
1. No idea about other sample but you can try this method
2. KOH use is mandatory as said by Reference method.
3. Please take help from other source
@@MicroChemsExperiments thank you for help
In formula how did this 28.05 came
Very helpful video,,,
Thanks
Can i use any other solvent like IPA or Methanol instead of Ethanol
THANKS YOUR TUTOR! HOW DETERMINE THE CONCENTRATION OF FLUORIDE AND CHLORIDE IONS FOUND IN GROUNDWATER ARGENTOMETRICALLY?
Noted the parameter. We will make video soon
Zero error practical....❤️❤️
Thank you.
Stay with us.
Good video! I got Dhatelo Seed Oil from Nepal. However, I am not able to find the SAP value. How can I use it for making soap without SAP value? Thanks.
Please take help from an expert of soap manufacturing company.
Thank you so much
You're welcome!
@@MicroChemsExperiments Your video contributed to me passing AP Chem with a “ college like” teacher 🫶🏼
Good work, keep it up. But how do you arrive at 4.1ml of HCl? I want to know its percentage purity and density and how you arrived at 4.1ml and must it be 0.5N? Can't 0.1N be used. Thanks as you reply
0.83ml HCl should be added to make 0.1N HCl solution and 4.1ml is added to make 0.5N HCl solution and make the final volume 100ml.
Please watch our video for the preparation of 0.1N HCl. Video link: ruclips.net/video/lXzAB8woAd8/видео.html
We used 37% HCl (fuming) of molecular weight: 36.46.
Thank you
You are welcome
Thanks mam..... For useful💐
Thanks
It's a good video with very few analytical errors
Thank you so much. We will try to avoid errors in our next videos.
I'm learning a lot from your videos.
More grease to your elbow
Thank you.
Thanks 👍❤️
You are welcome
Please make a video SAP value on solids also if possible
Okay.
I want to saponified xanthophyll esters .May I use isopropanol instead of absolute alcohol?
No. You should use ethanol
Kindly post sediment test video in Soyabean DOC
Anil Soni, Noted. We will work on your topic very soon. Stay with us.
Some websites are showing this formula of saponificatio = 56.1×(A-B)×N÷W
and some showing 28.05 ×(A-B)÷W
I am confused, which is correct , what is difference.?
Please reply
Both calculations are same. You will get the same result. Second equation, you mentioned, is simplified form of calculation. First mentioned calculation is the original calculation formula. You can use both.
@@MicroChemsExperiments thanks for reply
@@MicroChemsExperiments what is normality of alcohlic KOH solution you have prepared
@@aone9548 Please watch the video again.
Its my dream to use those gadgets of yours
Can please explain final calculation part of saponifications because my calculations is different when i done with same values hiw it's 187.88
May I know why we need to dissolve KOH for alcoholic KOH preparation in cold water?
We need to dissolve KOH in cold environment to prevent the vigorous reaction of KOH with ethanol which may lead to the loss of properties of KOH solution.
Hello! Is it okay to use 95% ethanol instead of 99% in saponification? Thank you
Yes. You can use
Please what is the value 28.05 used in the calculation
Refilling burrette may lead to analytical errors... Should have refilled before starting the titration
Martin Okyere, Thanks for your observations. You are right about error. We should use 100ml burette to avoid refilling. We have tried to refill it fast to avoid the error as we dont have 100ml burette.
Why do we still have to heat the blank if there's no sample to dissolve
make a video on tomato paste analysis and calculation
Please mention the test parameter of tomato paste
@@MicroChemsExperiments total energy
acidity salt sugar fats protine concentration coler measurement viscosity
reducing sugar biological analysisi
shelf life totsl solids
All set but in my calculation answer is 190.90 according to your formula nd what is this 28.05 in formula?
Calculation factor
@@MicroChemsExperiments how u make this factor?
28.05 is the multiplication of (concentration of HCl and the Molecular weight of KOH)
@@fabihajahan5798 okay gud
When refluxing or heating the KOH and fat...the KOH disappears leaving something like a whitish powder. I then need to refill again with KOH. Why does this happen?
Not sure about that. Never faced this kind of problem
Super tq
Thank you
in the standard formula for SV, it uses the molecular weight of KOH (56.1g/mol), but in this method, it applies 28. 05? my question is what this number represents?
Mike Tyson, which standard formula are you talking about.
In this test, we followed the AOAC 920.160 official method strictly. In AOAC 920.160 method, 28.05 is used in the equation, so we did.
@@MicroChemsExperiments This is because HCl concentration is 0.5 N. Basically the equation involved HCl concentration too. When it is 0.5 N Molecular wt of KOH is 56.1 which will eventually lead to the value of 28.05.
@@TridibSarma Thank you so much for the clear explanation.
@@TridibSarmaI don't understand calculations explain please.
56.1 x0.5N = 28.05
Love from Pakistan
Thank you so much. Stay with us. Help us to grow.
U r good btw
Thank you so much.
What should be the temperature for reflux in saponification of coconut oil ???
Same temperature
Ma’am .. as we are always taking 0.5 N HCl for saponification..then why we are getting different range of values for blank .Is there any range for blank value while using 0.5 N HCl .. pls reply
Sample flask contains sample, thats why during saponification, the concentration of KOH in sample is decreased, thus HCl is needed more in compared with blank.
Please search on google. You will get idea in details. Thank you.
Can we use potassium hydroxide flakes instead of pallets
No. You have to use KOH pallets.
Great and helpful video..👍😊 Can you make a video on FFA% or acid value of oil?
Already made: ruclips.net/video/TaN1CimEqfY/видео.html
From the calculation aspect, where is 28.05 gotten from???
It is a half of KOH molecular weight 56.11%2 = 28.05
Correct
Can you give me the "Determination of Oil Analysis" manual if I need it?
We do not provide any document
how do you say 187.88 mg of KOH required to saponify 1g of fat? you have taken 5 g of sample.
I divided the equation by the sample weight (5g) to convert the result for 1g of sample. Please take another look at the calculation.
👌👌
😊😊
Must And Should Use pipette
Not Use Measuring cylinder
Here you don't need accuracy at that much. You can also use measuring cylinder. But using pipette is best practice always
In the equation you put 28.05 and on calculating its become 28.5.
I would like to use this in a paper. What journal can I cite?
This procedure is not taken from any journal. It is collected from official method of AOAC 920.160.
Please cite the AOAC book
👍🏻
Thanks
Oil me insoluble impurities ka video banao
Noted.
what is the purpose aluminum foil for preparing ethanolic?
Samrawit Alebel, Thank you for your commemts.
Aluminum foil acts as a catalyst here and helps to carry out the reaction of KOH with ethanol faster.
How to prepare 05 N KOH as in how much quatity of KOH is added?
I m asking about ethanol
0.5N KOH is not needed for this test
what is the 28.05 in the equation? can u please clear my doubt on 15.00 time
It is a calculation factor
56.1(mol wt of KOH) *0.5( normality of HCl) = 28.05
Ma'am I'm looking process of determination of hydroxyl value of oil any videos or documents
Noted.
That test can we use Iso Propyl Alcohol
No. You have to use ethanol
Is the SV of Oil (in the form of triglycerides) less than the SV of the same oil after hydrolysis (free fatty acids after reaction - splitting)?
Yes, because molecular weight decreases after hydrolysis & as the mol wt decreases SV in increase,so definitely SV of split fatty acid will be more than oil before hydrolysis.
hello please share the relationship between sap no and saponifiable matter
Noted
For the calculation why we don't include the normally 0.5 N of the Hcl.
@Goutam Gupta, this test method and calculation are strictly followed the AOAC 920.160 official method. AOAC given the calculation. The reason behind it is: Sample and blank are Titrated with the same concentration of HCl (0.5N), thats why 0.5 become minimized from each side of sample and blank.
@@MicroChemsExperiments thanks for clearing doubt.
This channel is really very helpful for we student.keep on ❤️
@@goutamgupta8816 thanks for being with us.
SV= 56.1*N*(B-S)/w
Put Normality -: 0.5N in given equation then you will get SV = 28.05*(B-S)/w
Please perform the unsonparable matter in oil
Phool Khoshboo, Noted. We will work on it. Be with us.
Phool Khoshboo, we uploaded the video for Unsaponifiable Matter. Please check it out.
Link: ruclips.net/video/GLY-IYkkv40/видео.html
❤️
❤❤
Which oil you have used
Rice Bran Oil
Why calculate saponification =( (v blank - v sample)× N hcl × 56.11)/sample weight
I don't know difference calculate in video?
The calculation shown in this video is collected from AOAC method. So don't be confused.
Because we are titrating residual KOH by HCl
please do " determination of total fat matter" in soap..
We are already working on the parameter. Coming soon. Stay with us.
Where does the 28.05 came from? Thank you
Its a calculation factor given by AOAC official method.
@@MicroChemsExperiments it is also 56.11 g/mol (MW of KOH) divided by 2.
Determination of Saponification Value of Oil or Fat Sample_A Complete Procedure (AOAC 920.160)
You copied the title. What did you mean?
Same way please upload unsaponification matter which is USM
NUTHAKKI RAJESH, Okay we will upload USM soon. Please stay with us.
NUTHAKKI RAJESH, we uploaded the video for Unsaponifiable Matter. Please check it out.
Link: ruclips.net/video/GLY-IYkkv40/видео.html
If i got 148.5 as a sap value .. Which oil it may be mam ?
It is may be the oil extracted from almond butter.
Pungency test method please
Noted
28.05 was written in the first line but in the next line 28.5
In the calculation part
@@tarunkumar8841 Sorry, it was a mistake. 28.05 is the correct factor. So 28.05 should be written in second line also. But we wrote 28.5 by mistake.
FSSAI revised manual say preparation of Alcoholic KOH different method
Ok. We will check.
Why that 28.05 in the calculation part?
Calculate Factor given by AOAC
Bellier Turbidity Temperature Test (BTTT) oil test
Noted
how to prepare ethanolic potassium hydroxide solution in procedure
Preparation of ethanolic KOH is already given in this video. Please follow the step-1.
@@MicroChemsExperiments IS there any optional to prepare without reflux condenser
@@amanueldaniel5342 You can prepare it without reflux but that can result in some error in the final result. The result will not be exact but can be considerable.
@@MicroChemsExperiments how? please show in procedure
@@amanueldaniel5342 Just dissolve KOH pellets in absolute ethanol and skip the distillation step. Take help from this saponification video and just skip the distillation part and disoolve KOH in ethanol
What is initial value Vs??
Vs is the volume of 0.5N HCl which was needed during the titration of saponified sample.
hello sir oil and fat Ka FRA ki full Analysis
What did you mean by FRA?
How to make 0.5N hcl solution?
You can prepare 0.5N HCl solution by followng our video: ruclips.net/video/lXzAB8woAd8/видео.html
Just multiply the amount of HCl, needed to prepare 0.1N HCl, by 5. Then follow the whole procedure to standardize the solution.
@@MicroChemsExperiments Hi do you have any idea which tests are important for oil testing according to fssai? I mean on what parameters does fssai check the quality of oil, say mustard oil?
@@factxfact5549 To test an oil quality, you must go for the following tests: Peroxide value, iodine value, Free Fatty Acid and Acid Value, Rencidity, Saponification value, Unsaponifiable matter, RM value, Polensky Value, Moisture, Refrective Index, Density etc.
@@MicroChemsExperiments every test we have to do if we are manufacturing mustard oil?😳 There are more than 20 tests.
@@factxfact5549 Yes. You have to do all of those tests.
Where is the 0.5 N in formula ???
Not needed that value
Where come from 28.05
It is the calculation factor given by AOAC method of saponification value determonation.
Its nothing bus 56.1*0.5
Why say saponification of blank when there is no fat in blank...
We call it unofficially to make it easy to understand by all including unskilled lab analysts.
De arrr
Dee arrrr
Please write in English
Why that 28.05 in calculation
Calculation factor
hello sir oil and fat Ka moisture content
Already uploaded.
Link: ruclips.net/video/DtSH8n1jbyM/видео.html
This is link of my channel
What do you mean?
Please don't add background music
Thanks for you suggestion
Good video, but why does the narrator always talk with a fake accent? Removes the fun of watching the informative video
We have the limitation of talking and we are very sorry about that. In future we will develop our accent.