Solving an Unknown Organic Structure using NMR, IR, and MS

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  • Опубликовано: 3 янв 2025

Комментарии • 75

  • @user-be4yc2vr5c
    @user-be4yc2vr5c 5 лет назад +32

    Listen here, buddy. I have some choice words for you, pal. Firstly, thank you for contributing to the betterment of humanity by making such vital, informative and intriguing information free for all whom desire to posses it. Second, that's pretty awesome. So thanks again. Look forward to checking out the rest of your videos.

    • @ChemComplete
      @ChemComplete  5 лет назад +4

      Haha thanks! This summer I released a full course on how to tackle these, check it out, it also has more worked examples. It has way more detail. Just a former professor that saw too many others that did not know how to explain concepts. Thank you for the support!

  • @carmenbalogh5151
    @carmenbalogh5151 5 лет назад +18

    Thank you for teaching! This is the absolute best explanation I could get as a quick review before my exam tomorrow!

  • @eliefant6353
    @eliefant6353 6 лет назад +14

    was the best explanation ever, this as so helpful.

  • @nazninakhter2883
    @nazninakhter2883 6 лет назад +5

    Remarkable explanation for establishing the structure of unknown Organic Compound. I am so impressed. Thank you very much..........

  • @DodoKraun
    @DodoKraun Год назад

    Better than my professors in University of Naples "Federico II"!! Thanks so much

  • @evagonzalez3206
    @evagonzalez3206 5 лет назад +11

    This was so well explained, thank you!!!!

  • @akoifahnbulleh4475
    @akoifahnbulleh4475 2 года назад +2

    Highly prolific, thanks so much much for the knowledge impacted.

  • @donaldmarthins2325
    @donaldmarthins2325 3 года назад +2

    This is a masterpiece tutorial!!!

    • @ChemComplete
      @ChemComplete  3 года назад

      Thank you so much. I never expected it to be so popular, but spectroscopy is extremely challenging. I am happy it was of help.

  • @atheersalmanawadal-atawi1764
    @atheersalmanawadal-atawi1764 2 года назад

    prof you made my life easier I had tough time in organic Spectro module but not any more thank you

  • @kylekropf2416
    @kylekropf2416 5 лет назад +3

    Best explanation I've been able to find! Thank you!

  • @kemnwadei9456
    @kemnwadei9456 3 года назад +1

    I truly appreciate your help. I am finally beginning to understand!

  • @joshbuhr445
    @joshbuhr445 4 года назад +3

    actually perfect explanation

  • @mrkillua5037
    @mrkillua5037 5 лет назад +7

    Why are there so many few videos about this. Thanks dude!

  • @nurynzulaikhamazni5723
    @nurynzulaikhamazni5723 4 года назад +3

    Thankyou for the best explanation!! ✨

  • @brentwalton1352
    @brentwalton1352 3 года назад

    Thank you for showing how to use NMR, MS and FTIR together to identify the organic molecule. Brent Walton

  • @quyenle-px1rq
    @quyenle-px1rq 5 лет назад +3

    Thank you so much. I got stuck on this one, and I will have a NMR final exam next Tues. The thing is that in my NMR paper, my prof doesn't show the number of hydrogen on every peak of 1H NMR . So i mean I can find the neighbors but I don't know which peak is CH2 or CH3. Anyway, this video is very helpful. I'll share this for my friends. I'd really appreciate it.

  • @Fatooshie7
    @Fatooshie7 4 года назад +1

    Fantastic video! Thank you!

  • @njooroanthony7268
    @njooroanthony7268 3 года назад

    You are helpful,. you teach so well. Be blessed

  • @dylan-om2kc
    @dylan-om2kc 4 года назад +2

    Thank a bunch, Sir

  • @jeethugeorge3933
    @jeethugeorge3933 3 года назад +1

    Thanks a lot sir ...this helps me a lot to do more number of problems so easily 🤗💝👏🧚‍♀️ from India ❤

  • @sea5205
    @sea5205 5 лет назад +3

    This is a really helpful video, thanks so much!

  • @hadeerrashad5486
    @hadeerrashad5486 5 лет назад +1

    Thank you very much!!! your explanation is excellent!!!!!

  • @LisaSim-y4k
    @LisaSim-y4k Год назад

    Thank you so much. Actually amazing.

  • @YouMe-mf7ed
    @YouMe-mf7ed 6 лет назад +2

    I wish our teacher would teach like you. my professor teaches us ochem 1 like a PHD student and i hate it because i don't understand a think that he's saying and expect us to know what he's talking about. as much as i try to learn in his class i can't. He really makes me want to give up to become a med student :(

  • @teresasibongisanitshuma5240
    @teresasibongisanitshuma5240 3 года назад

    Thank you for the clear explanation was so blank on this stuff could not understand

  • @rockendude103
    @rockendude103 5 лет назад +14

    What if you arent given a formula in the Mass Spectrum?

    • @austintull5583
      @austintull5583 4 года назад +1

      I'm also wondering this @chemcomplete

    • @irie8409
      @irie8409 4 года назад

      @@austintull5583 are you given an element analysis? Like the percentage of masses of different elements

    • @marasmithson6218
      @marasmithson6218 4 года назад +1

      If you aren't given anything, you can guesstimate your Formula out of taking significant peaks from IR and combining them with MS:
      ruclips.net/video/T2pNUjHmiks/видео.html

    • @marasmithson6218
      @marasmithson6218 4 года назад

      you should be given your molecular mass+ peak then tho.. otherwise if it isn't visible you're pretty much fucked.. It is possible but a real guessing game then. You can find out pretty much exactly how many Cs there would be if you are given the correct Intensities tho of your m and m+1 (C13) peak (since c13 comes in 1,1% relation to c12)

    • @ChemComplete
      @ChemComplete  3 года назад +1

      If you aren't given the formula the problem will be slightly harder. You will need to analyze the MS for the parent peak, base peak, and any common fragments. I have several videos on this type of analysis, check the mass spec playlist for more details

  • @stephaniejackson9488
    @stephaniejackson9488 3 года назад

    excellent explanations. thank you so so much, this was incredibly helpful!

  • @AJITKUMAR-oq7sk
    @AJITKUMAR-oq7sk 3 года назад +1

    very very good and informative dear

  • @nurdagstanl9530
    @nurdagstanl9530 3 года назад

    İt İs really efficient video to make practice.thanks a lot

  • @bsavvy5450
    @bsavvy5450 7 лет назад +1

    Thank you for this it was so helpful!

  • @MrStaggerLeeee
    @MrStaggerLeeee Год назад

    I do this for a living but unfortunately now at days only occasionally. Remember in real life to use all information like is it a solid or liquid, does it have colour, where did you get the sample from, what is the retention time on the GC or LC etc. Solving these are the most fun you can have at work without getting into trouble with HR.

  • @vishnudass2789
    @vishnudass2789 6 лет назад

    Those protons in the aromatic ring are not magnetically equivalent as you are said at 21:27. The para disubstituted benzene ring will actually give an AA'BB' splitting pattern which is actually second order. In the HNMR spectrum given it is not 2 doublets instead it is a normal AA'BB' pattern,

  • @Xoro-t9j
    @Xoro-t9j 2 года назад

    Very well explained

  • @satarakhan6871
    @satarakhan6871 3 года назад

    SPECTROSCOPY MASTER!!!!!!

  • @jonathansanchez8802
    @jonathansanchez8802 4 года назад +1

    great video!

  • @anandu_5041
    @anandu_5041 3 месяца назад

    Can anyone suggest which text to refer to get more of these problems?

  • @lotfihabchi737
    @lotfihabchi737 5 лет назад +1

    thank you very much !!

  • @lokeshkumartripathi3817
    @lokeshkumartripathi3817 2 года назад

    Excellent 👌

  • @jonathanliu4636
    @jonathanliu4636 5 лет назад

    Thank you tons!

  • @abdulwahid-qp6uy
    @abdulwahid-qp6uy 4 года назад +1

    excellent

  • @Rhianuh
    @Rhianuh 3 года назад

    do you have one where you dont know the chemical formula? I cant understand how to find that!! :(

  • @jenswolf2116
    @jenswolf2116 3 года назад

    what do i do when im only given the mass spec without the formula, feels like im just guessing

  • @danishulman6371
    @danishulman6371 6 лет назад

    so helpful!!

  • @gugaracha1773
    @gugaracha1773 6 лет назад +1

    hello there , how can i contact you , have this problem i was wondering if i could assist me if i send a picture of it

  • @Lila-lc7wd
    @Lila-lc7wd 4 года назад +1

    ahhh thank u sm!!!

  • @angelmarg6238
    @angelmarg6238 6 лет назад +1

    thanks !

  • @mrwajpofc
    @mrwajpofc 7 лет назад +2

    How can one tell the integration number?

    • @ChemComplete
      @ChemComplete  7 лет назад +1

      The integration can be obtained in several ways. The first is if it is directly provided to you in the example. If not and you are working on an instrument, the software should allow you to integrate the peaks. If your instructor gives you an NMR and asks you to solve it without the integration numbers, you should look for the integration signs over the peaks. Measure them all (with a ruler). The ratio of these peaks represents the integration values.

  • @fabzy4L
    @fabzy4L 3 года назад

    Mass Spectrometry, though.

  • @sadiafiaz5057
    @sadiafiaz5057 5 лет назад +1

    Best

    • @ChemComplete
      @ChemComplete  5 лет назад

      Thanks, early July I will be releasing an entire series on how to do this with more examples!

  • @theak-1663
    @theak-1663 3 года назад +1

    you're lucky to get labeled IRs

    • @ChemComplete
      @ChemComplete  3 года назад +1

      Yes, I have seen instructors use unlabeled IR values before. In my guide I go over the various regions and vibration peak shapes. A lot of it becomes pattern identification. But yes, it is annoying to get unmarked spectra. Most instruments today automatically provide this, so it seems outdated to not provide it.

  • @aslit5314
    @aslit5314 3 года назад

    kral

  • @ani9514
    @ani9514 6 лет назад +4

    wtf, this is undergrad stuf?!?! Im learning this in IB year 2 lol

  • @지원-d5x
    @지원-d5x Год назад

    thanks for your very kind teaching! it was really helpful for me 🥹

  • @niloofarkh4779
    @niloofarkh4779 2 года назад

    thank u so much , perfect