Olympiad mathematics | indian math
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- Опубликовано: 10 июл 2024
- Olympiad mathematics | indian math
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If 99% of entrants failed this they never learned arithmetic.
I don't believe 99% would fail to find the 0 solution. You wouldn't clickbait, would you?
2 *sqrt(x) = x. One solution is zero. For the other, divide by sqrt(x) to get 2 = sqrt(x). That means x = 4, the other solution.
Dividing by 2 at the beginning was unnecessary.
If we divide by √x, we get 2=√x i.e. x=4. But the equation has one more solution (when division is invalid): x=0. (If x is negative, then √x is imaginary. More generally, if x is complex other than a positive real number, then angle of √x in polar coordinates can't be the same as the angle of x.)
We can also substitute y=√x; then we get y^2 - 2*y = 0, and that yields y*(y-2)=0, immediately giving the two solutions (a quadratic equation can't have more than two solutions).
x=4 and possibly imaginary values
No, no imaginary answers. But zero is also a solution.
@@JohnRandomness105 Yes I missed that one.
Nice calculating.
But how on earth are you writing the letter "x"?
I think they're using n, same concept.
@@FinetalPies The Thumbnail says "x", and "n" implies a natural number.
if we assume x =9 so =3.3 or 3/2 +3.3 or 3/2 = 9 so 9+9=9 so 18=9 so -x=9-18 , so -x=-9 .(-1) so x=9 easyest way for me to calculate it
But it's not 9? The square root of 9 is 3. 3 + 3 is not 9
What on Earth did you write? Since when is 9+9=9?
@@MikeRosoftJH no √9+√9=9 this can be calculate 3 varians x=0(0.0) x=4(2.2) x=9(3.3)
@@FinetalPies when u close the √ is x1 x2
and x3 they are all =9 and if u want to find x u must move x left site = and numbers other site of = (right) side
@@asdasdasdasd7628 √9+√9=9 - since when? √9 is not 4.5, it's 3. (By substitution of y=√x, we get y^2 - 2*y = 0, and it can be seen that the equation has exactly two solutions - a quadratic equation can't have more than two solutions.)