Italy - Math Olympiad Problem | Find all integer solutions

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  • Опубликовано: 21 июн 2024
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Комментарии • 23

  • @oliviervancantfort5327
    @oliviervancantfort5327 13 дней назад +12

    The method is wrong.
    There is no reason why x and y should still be integers as square roots were introduced in their definition. Therefore, decomposing 17 in prime factors is not a justified step.

    • @MajesticUC
      @MajesticUC 12 дней назад +2

      I agree

    • @hippopotamus_nr2587
      @hippopotamus_nr2587 12 дней назад

      can't that simply be fixed by saying (x+y) = c and (x-y) = 17/c for all c's element of ]-sqrt(17), 0[ union ]sqrt(17), +inf[
      and then giving an answer for x and y in terms of c
      might be wrong what i'm saying tho

    • @SG49478
      @SG49478 12 дней назад +2

      You are absolutely right. I don't know if this is the same person, but a few months ago the same problem was posted here on youtube with the exact same wrong method to solve it.
      The fact that he found one solution is simply pure luck. This method didn't even find the second solution, which is (18;1). Not even to mention that this method does not prove there aren't any more solutions.

    • @alimahmoudifar4772
      @alimahmoudifar4772 6 дней назад

      Yes

  • @qehn
    @qehn 12 дней назад +11

    Also (18, 1) and (1, -16)

  • @mauriziograndi1750
    @mauriziograndi1750 12 дней назад +3

    a=3 = b=4
    3^4=81 - 4^3=64
    81-64=17
    We appreciate the explanation but in this case the result was easily found by inspection.

  • @unebonnevie
    @unebonnevie 12 дней назад +2

    The question would be much harder to find all solutions for *a* and *b* such that they would satisfy the original equation. The video shows ONE solution.

  • @pidigi
    @pidigi 12 дней назад +2

    2:38 why x + y > x- y? It’a valid only for y>0

  • @donsena2013
    @donsena2013 11 дней назад

    With two unknowns defined by only one equation, there is going to be a family of solutions for a & b -- especially if we allow for non-integer values of a & b

  • @Itesh.R
    @Itesh.R 13 дней назад +3

    no
    a= 18 b= 1

  • @RealQuInnMallory
    @RealQuInnMallory 12 дней назад +1

    (1)^1 ➖ (17)^1 (b ➖ 17a+1)

  • @subudhitech1550
    @subudhitech1550 9 дней назад

    (18^1)-(1^18)

  • @unebonnevie
    @unebonnevie 12 дней назад

    I don't understand the logic/thinking of getting into the inequality of *(x + y) > (x - y)* and becoming two equations, *(x + y) = 17 and (x - y) = 1* . How is that allowed?

  • @brossolletpaul5905
    @brossolletpaul5905 12 дней назад +1

    Why x and y natural ?

  • @prithvichidri9634
    @prithvichidri9634 12 дней назад

    Guys who tried adding something to 17 to get a perfect square or perfect cube etc.🤙 and get the ans

  • @subudhitech1550
    @subudhitech1550 9 дней назад

    We can break the 17 to get 18^1-1^18

  • @raviyadav031
    @raviyadav031 8 дней назад

    India 🎉

  • @onkotonkoblu
    @onkotonkoblu 13 дней назад

    Hi, from Italy ❤🤍💚

  • @ReginaldCarey
    @ReginaldCarey 8 дней назад

    I can’t get past the horrible penmanship.

    • @enantiodromia
      @enantiodromia 7 дней назад

      Then superficiality prevents you from learning. What a pity.

    • @ReginaldCarey
      @ReginaldCarey 7 дней назад

      No, the answer was easy to compute - for me. If your handwriting is poor, then type. Don’t force your viewers/students to struggle unnecessarily. That’s not good teaching.