Hey, Just wanted to thank you,years ago i had seen your videos a night before my basic electrical engineering exam,your videos helped me clear the exam somehow. Thanks.
What if the voltages in those resistors were replaces with ohms and the current dependent current source was replaced by a voltage dependent voltage source? And also that 6 A is unknown
How does a resistive circuit element consume power? Everything I've seen says electric current moves extremely slowly, like a millimeter per hour. So, it's going to take many hours for a specific electron to get from one end of the RESISTOR to the other! This "drift velocity" seems more or less constant. I always assumed current flow occurred at a high enough speed that its speed wouldn't be any kind of issue. I see a simple circuit diagram and try to realize that the electrons that make up the current flow will take centuries to move around the circuit ONE TIME! Then, too, what is a "current waveform"?
The resistive element has many more scattering centres (impurities, lattice defects, etc.) than a less resistive one. Power is lost to the resistive element via inelastic scattering of the conduction electrons with these scattering centres. Look up Drude's theory of electrical conduction in metals.
@@StoneShards Hi Peter! I'm not here to teach or argue with you. Sorry if I gave you that impression. It was very tempting to answer your question! This is the first time I hear that current is conserved. I know that charge is conserved but never current. When current passes through a resistor we say ENERGY (or power to say it loosely) is comsumed, not current. My mental picture of an electric current is a rotating rubber belt driven by the car engine, the belt representing a chain of electrons and the current the rotation of the belt. Power is extracted from the belt through friction with a non rotating member. No electrons is lost due to the friction. Hope that makes sense to you.
Happy to engage with you too. You might care to go to my channel "Johan Arif" and watch some "tedious" videos on there on Thevenin and Norton's theorems.
Peter C the reason why it's done like that is because if you look at the final results and add up the different powers calculated, they come out to zero, which is what we want. Means that exactly as much power is being supplied to the circuit as is being used in the circuit.
Your explanation is not clear, u should explain its details too , u r just calculating and saying it should be calculate like this u didn’t say anything about how and why it should be calculated like that. 👎🏻
Hey, Just wanted to thank you,years ago i had seen your videos a night before my basic electrical engineering exam,your videos helped me clear the exam somehow. Thanks.
You explained this in a simple way and helped me understand since my professor sucks at explaining 🙏
Fantastic! Just what I was looking for, super clear explanation!
I’m grateful to you my friend 🙏🏻
how I know that where should I assign positive n negative for that dependent currenct source?
When finding p4, why did we use i=5A ?
Because that’s a dependent current source on the voltage source, so it depends on the original I
I got the last one by adding al the previous calculated data together and adding what would make zero. Seems like it works and it's a lot easier. xD
well then people couldn't learn how to find the power dissipated by the current source in more general applications.
thank you bro
What if the voltages in those resistors were replaces with ohms and the current dependent current source was replaced by a voltage dependent voltage source?
And also that 6 A is unknown
Sir why didn't you take the sign convention for when voltage is taken into picture
Thank you so much for such a great video!!!!
Thank you sir!🙌🏾
Thankyou so much sir, just exactly what I was looking for
How about the power delivered by the voltage source ?
hey man, I have an question for you. why did not we use 20 v for p4 instant of not using 8 v?
Because p3 and p4 are on the same node.
FANTASTIC SIR
very well explained
Dude thank you so much
How does a resistive circuit element consume power? Everything I've seen says electric current moves extremely slowly, like a millimeter per hour. So, it's going to take many hours for a specific electron to get from one end of the RESISTOR to the other! This "drift velocity" seems more or less constant. I always assumed current flow occurred at a high enough speed that its speed wouldn't be any kind of issue. I see a simple circuit diagram and try to realize that the electrons that make up the current flow will take centuries to move around the circuit ONE TIME! Then, too, what is a "current waveform"?
The resistive element has many more scattering centres (impurities, lattice defects, etc.) than a less resistive one. Power is lost to the resistive element via inelastic scattering of the conduction electrons with these scattering centres. Look up Drude's theory of electrical conduction in metals.
@@faizmalik9210
@@StoneShards Hi Peter! I'm not here to teach or argue with you. Sorry if I gave you that impression. It was very tempting to answer your question!
This is the first time I hear that current is conserved. I know that charge is conserved but never current. When current passes through a resistor we say ENERGY (or power to say it loosely) is comsumed, not current. My mental picture of an electric current is a rotating rubber belt driven by the car engine, the belt representing a chain of electrons and the current the rotation of the belt. Power is extracted from the belt through friction with a non rotating member. No electrons is lost due to the friction. Hope that makes sense to you.
@@faizmalik9210
Happy to engage with you too. You might care to go to my channel "Johan Arif" and watch some "tedious" videos on there on Thevenin and Norton's theorems.
Thank you :)
i thought if the current went out the positive battery it would be positive? why is it negative?
because we are finding power dissipated, but current source is supplying power hence negative sign before that. Same is the case with voltage source
Peter C the reason why it's done like that is because if you look at the final results and add up the different powers calculated, they come out to zero, which is what we want. Means that exactly as much power is being supplied to the circuit as is being used in the circuit.
I can't understand why current (-0.2 A) ?
Because it flows backwards than normal.. Which is from positive to negative.. I hope i helped you
Thank you sir!
Thank you, your way is too good 👍
Sources supply power, whereas resistors obsorb that power
Thank you!
i thought voltage in a parallel stayed the same.
Because by KVL, the sum of the voltage in a closed loop must equal to 0 and since P3 is 8v then P4 must be 8v too
isn't the power across a resistor found with I^2 x R ??
it's the same as 'V x I'
thnkx bro.......
Great video! Thank you!
thanks a lot
Thank you so much sir
Awesome
thanks 💐💐💐
Fuck yes. Thanks for the awesome swift explanation
Your explanation is not clear, u should explain its details too , u r just calculating and saying it should be calculate like this u didn’t say anything about how and why it should be calculated like that. 👎🏻
Thats because he is only explaining the power not how to analyze the circuit
Red does not sound good actually
Jonah Hill?