If x=1+a+a2+a3+... and y=1+b+b2+b3+...., then show that 1+ab+a2b2+a3b3+...=xy/x+y−1
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- Опубликовано: 25 дек 2023
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Q.If x=1+a+a2+a3+... and y=1+b+b2+b3+...., then show that 1+ab+a2b2+a3b3+...=xy/x+y−1
CH- (Geometric Progressions) | IMPORTANT QUESTIONS