Thank you for actually explaining why and not just showing us how to solve these problems. For some reason knowing why I’m doing something really cements the concepts better for me.
I can't reply to Earlyn's comment directly, so I'll just leave this right here. When you look for critical points, set the derivative of your function equal to 0. In this case, you will get y' = 4x^3 + 3x^2 + 6x. Factor your derivative and set both products equal to 0. Once you find the values of x that make your derivative equal 0, create a number line to check for the sign of the first derivative for all values to the left and right of your critical numbers (pick 1 number greater than your critical number and 1 number less than your critical number and plug them into your derivative). If there is a sign change, then you have found a critical point, but make sure you plug it into your original function to make sure that that critical point is defined.
integralCALC, how is -2 not in the domain? There is a left-hand portion of this function, and -2 is the max on the interval (infinity, 0). P.S. I love your explanations, they are concise and easy to follow. Keep up the good work.
Nathan Tonning I think she made a mistake. The domain for the original function is all real numbers except 0. You may plug in any number into x^1/3 and yield a real number while x^-2/3 turns into 1/(x^2/3) where the only value that makes this part of the equation undefined is 0.
jdcis2smart She probably meant the function has no absolute critical numbers. I thought of this after watching her video on identifying the extrema of a function. Thanks for the reply.
I am not understanding why negative numbers are not in the domain of the original equation. I understand that the graph can demonstrate this, but can anybody tell me how you could know that negative numbers are not in the domain without actually graphing the original equation?
Krista King I love your explanations, they are concise and easy to follow. But I have a doubt. how is -2 not in the domain? I think the domain is all real number except x=0, There is a left-hand portion of this function, and -2 is the max on the interval (infinity, 0). Could you please double check? Thank for your clarifying.
how about the equation y=x^4+x^3+3x^2-1 what is the critical points here. I am having a hard time solving for this problem and I don't know how to even get it
I have a question regarding 3 or 4 critical points how can there be 3 or 4 or 5 critical points . Please answer me . That will be your kindness Thankyou
There can be an infinite number of critical points. A critical point occurs every time the function changes direction from increasing to decreasing, or vice versa. Think about (and graph) the sine function sin(x). That function extends infinitely in both directions, and changes direction an infinite number of times, and each of those changes is a critical point.
Great video, but she never actually found the critical points of the function. Yes, there is no maximum but there is a minimum and she never solved for the point.
still confusing as balls. that being said, this kind of problem is good for a notecard as it incroparates multiple lessons into one. and at least it tests me on what i already know while helping me learn something new. other examples given by other tutors are too basic and dont really prepare me for the hellscape that is college calculus.
lol, how did you factor again? just Stop, this is what i hate on college profs and some youtubers on this because they assume I should know already, HEY if I know I wouold not be here. TRUST ME
Thank you for actually explaining why and not just showing us how to solve these problems. For some reason knowing why I’m doing something really cements the concepts better for me.
!god are you a great teacher or what
you can't imagine how desperate I was before I watched this lol
I'm so glad it could help! :)
Math Queen! Thx for your friendly explanation! You are really talented at teaching!
Thank you so much, Peto! :)
at 8:57 you have confused critical point with inflection point. Curvature is associated with the latter.
I can't reply to Earlyn's comment directly, so I'll just leave this right here. When you look for critical points, set the derivative of your function equal to 0. In this case, you will get y' = 4x^3 + 3x^2 + 6x. Factor your derivative and set both products equal to 0. Once you find the values of x that make your derivative equal 0, create a number line to check for the sign of the first derivative for all values to the left and right of your critical numbers (pick 1 number greater than your critical number and 1 number less than your critical number and plug them into your derivative). If there is a sign change, then you have found a critical point, but make sure you plug it into your original function to make sure that that critical point is defined.
integralCALC, how is -2 not in the domain? There is a left-hand portion of this function, and -2 is the max on the interval (infinity, 0).
P.S. I love your explanations, they are concise and easy to follow. Keep up the good work.
Nathan Tonning I think she made a mistake. The domain for the original function is all real numbers except 0. You may plug in any number into x^1/3 and yield a real number while x^-2/3 turns into 1/(x^2/3) where the only value that makes this part of the equation undefined is 0.
jdcis2smart She probably meant the function has no absolute critical numbers. I thought of this after watching her video on identifying the extrema of a function. Thanks for the reply.
Nathan Tonning, I agree with you. I also have the same doubt.
I am not understanding why negative numbers are not in the domain of the original equation. I understand that the graph can demonstrate this, but can anybody tell me how you could know that negative numbers are not in the domain without actually graphing the original equation?
Usually, only programming channels earn my sub, YOU ARE AN EXCEPTION :D
😀
Krista King I love your explanations, they are concise and easy to follow. But I have a doubt. how is -2 not in the domain? I think the domain is all real number except x=0, There is a left-hand portion of this function, and -2 is the max on the interval (infinity, 0). Could you please double check? Thank for your clarifying.
i got it now after some processing you have not not mentioned it any way thank you so much for explaining
how about the equation y=x^4+x^3+3x^2-1 what is the critical points here. I am having a hard time solving for this problem and I don't know how to even get it
still needed?
This function behaves as mad near a zero point, for example if x = -0.00000000000000000000001, it flies to - cosmos ..))
What is definition of the Critical point??
An interior point of the domain of a function f where f' is zero or undefined is called a critical point of f.
why is the graph "only defined for positive x values"?, wouldn't this be different since it's a cubed root?
the graph in the video doesn't represent the function.
I dont get it. the number droping from nowhere
I have a question regarding 3 or 4 critical points how can there be 3 or 4 or 5 critical points . Please answer me . That will be your kindness
Thankyou
There can be an infinite number of critical points. A critical point occurs every time the function changes direction from increasing to decreasing, or vice versa. Think about (and graph) the sine function sin(x). That function extends infinitely in both directions, and changes direction an infinite number of times, and each of those changes is a critical point.
cubicroot(x-7) find inflection point
Start by treating it as (x-7)^(1/3), and then finding the second derivative. :)
Great video, but she never actually found the critical points of the function. Yes, there is no maximum but there is a minimum and she never solved for the point.
I hate math so so so so so so so so so so much I couldn't even put it in words
woooow thank y very moch
If function is not DIFFIRENCIALBLE then how you gonna find extremums! I hate to write maths in English
still confusing as balls. that being said, this kind of problem is good for a notecard as it incroparates multiple lessons into one. and at least it tests me on what i already know while helping me learn something new. other examples given by other tutors are too basic and dont really prepare me for the hellscape that is college calculus.
i do not understand you please explain slowly with writing details
it was a nice example but how did you do ) 1+2x^-1
-1 exponent can also be rewritten as (-3/3). When you distribute the entire piece that is in the front, it will revert back to (2/3)x^-(5/3)
Thodi dhire English bolo kuch samaj ni aa ra
Usko bhi hindi samajh nhi aara 😂
Voice is low, it needs calm environment or phone with good speaker to be able to hear it.
Then don't watch the video, she actually did a really good job at teaching.
I love you. You are so nice>!!!!
Ok
lol, how did you factor again?
just Stop, this is what i hate on college profs and some youtubers on this because they assume I should know already, HEY if I know I wouold not be here. TRUST ME
Yes, you should be assumed to know how to factor before learning calculus
If you don't know how to factor then look up some videos on factoring and maybe look at some different methods on how to go about factoring.
@@wengeance8962 thank god you do!