Symmetric Tree - Leetcode 101 - Trees (Python)

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  • Опубликовано: 1 окт 2024
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Комментарии • 14

  • @GregHogg
    @GregHogg  2 месяца назад

    Master Data Structures & Algorithms For FREE at AlgoMap.io!

  • @servantofthelord8147
    @servantofthelord8147 3 месяца назад +1

    Wow. Such a beautiful solution. Excellent work as always Greg!

    • @GregHogg
      @GregHogg  3 месяца назад +1

      Thank you!

  • @DTsertsvadze
    @DTsertsvadze 3 месяца назад +1

    Hey Greg you rock dude! Big fan of your approach.. btw what app are you using for drawing?

    • @GregHogg
      @GregHogg  3 месяца назад

      Sorry for the slow reply! I use miro :)

  • @raymondchan3925
    @raymondchan3925 Месяц назад

    Question: Thanks for the instruction!! love it but one question though. If you call same(root, root) at he beginning, wouldn't you ends up with two identical call stacks and ends up with Time: O(2n) ? Why not do same(root.left, root.right) from the start? I understand you will have to do something to check the initial root and the first two children but the trade off is you have 50% improvement in time, right?

  • @viswanathvuppala4526
    @viswanathvuppala4526 3 месяца назад +1

    How about doing a level order traversal and check if every level is a Palindrome.

    • @GregHogg
      @GregHogg  3 месяца назад +2

      That's a cool solution

    • @viswanathvuppala4526
      @viswanathvuppala4526 3 месяца назад

      @@GregHogg Hey, thanks!

    • @etaidiary
      @etaidiary Месяц назад

      @@viswanathvuppala4526 tried that, they have a case that blocks that

  • @KRISHNASINGH-i2v
    @KRISHNASINGH-i2v 3 месяца назад

    Hey greg big fan
    From india
    Can you please put more binary tree questions already completed what you have posted on binary tree

  • @anmolacharya309
    @anmolacharya309 Месяц назад

    Great Animation

  • @ghost_7701
    @ghost_7701 3 месяца назад +1

    Dude Python is a pseudo code!😮

    • @GregHogg
      @GregHogg  3 месяца назад +1

      Haha pretty much yeah