Can thank you enough for taking the time to help us the students. I'm retaking calculus and will watch all your videos prior taking my next class. Thank you.
Bro thank you I’m planning to learn calculus next summer and you’re going to help me so much IM SO GRATEFUL TOWARDS U MAKING THIS SERIES TANK U SO MUCH 😭😭😭
23:51 shouldnt the 2 be because the coordinate for the first one (1, 1) and (2, 0) must be y2 - y1 /. x2 - x1 you get the gradient -1 then y = mx + b y - y1 = (-1)(x - x1) ?
Can thank you enough for taking the time to help us the students. I'm retaking calculus and will watch all your videos prior taking my next class. Thank you.
Thanks for taking time to put the entire book.
Book name bro
@@bragadeeshwaran6069 calculus 8th edition Stewart
Thank you so so much. You just made my life so much easier! Understanding your explanation of the book's content has become a breeze!
Bro thank you I’m planning to learn calculus next summer and you’re going to help me so much IM SO GRATEFUL TOWARDS U MAKING THIS SERIES TANK U SO MUCH 😭😭😭
I’m on my way to complete the book in 3, weeks thanks to you
can't thankyou enough, this means a lot for me as a student
I love this video series... this guy is great. I have the new edition, but these videos are a great companion.
Thank you this is the best video on functions and models .please make a video on graph plotting in detail...
23:51 shouldnt the 2 be because the coordinate for the first one (1, 1) and (2, 0) must be y2 - y1 /. x2 - x1 you get the gradient -1 then y = mx + b y - y1 = (-1)(x - x1) ?
Thank got your channel recommended from a friend
this series really helped me
Could you post more about solving problems and practicing together? Thank you
Thanks for saving life.
Sir can. You help me to solve Exercises sums ?
17:09 what kind of a function is example 6 B
It is a rational function.
will this work with 9th ed?
bruh this is literally my whole calc course.
Same bruhh🤩
You are a god send!
Than you so much.
Thank you
Wouldn't h(x) = 2x - x² be odd???
Why did you say it is neither even nor odd?
h(x) = 2x - x²
h(-x) = 2(-x) - (-x)²
h(-x) = -2x + x²
By PEMDAS, the exponent outside parenthesis must be applied to the minus sign in parenthesis before multiplication can occur, so h(-x) = -2x - x².
Sorry but u forgot something
@@navidcoolname2043 Nope, they are correct. (-x)^2=(-x)(-x)=+x^2.
thank you!!!
CLUTCH
Soa iter 💪
الله يهديك للإسلام اذا ما كنت مسلم
Thank you so so much