Finding Remainder using Binomial Theorem | Frequently asked Problems in JEE Exam | JEE Main 2023/24

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Join this JEE Turbo session where Bhoomika Ma’am guides you on how to find Remainder using Binomial Theorem. Further, Ma’am takes you through the frequently asked problems in the JEE Exam to strengthen your JEE Main 2023/24 exam preparation.
Bhoomika Ma’am discusses the following questions in this JEE live class:
1. Finding Remainder using Binomial Theorem
2. How to find Remainder?
3. Remainder problems
4. Finding Remainder
5. How to find the Remainder using the Binomial Theorem?
6. Remainder problems in the Binomial Theorem for JEE
7. Remainder questions in Binomial Theorem for JEE Mains
8. JEE Maths questions
9. JEE Main 2023 Maths preparation tips
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[@manjulapc2908]

Thank you so much mam, please start a yearwise lessonwise pyq series and make a playlist of that it will definitely be a mighty useful playlist

[@sarveshpandey147]

Nv sir ka method 😂 udaa liyA 🙂

[@ridul]

Anpd aakash Etna purana hen ki tere purkhe pedha nhi hue honge tauh bol Mt 😂😂😂😂 nv sir ne bhi khi se pda hoga 😂😂

[@dharinianchan3621]

this was really helpful. thank you so much.

[@flyingbeast9679]

I LOVE YOUR TRICKS MAM AS ALWAYS , YOU NEVER CEASE TO AMAZE ME

[@meetnoob6059]

Congruent modulo

[@swaggerbaba4404]

Tmkc bkl

[@shiveshpratapsingh3501]

Congruence modulo is very good method to find the remainders

[@RanaCreations4]

Thanks mam

[@jayantmoye5604]

good explanation mam

[@AkulaSuvarna-qe6nw]

Thank you so much mam I always follow your tricks. These tricks always helps me. Thank you so much mam

[@shoaibahmad3259]

Very much thank u mam

[@Aakash_JEE]

Most welcome 😊

[@motivational_bhaiyaji]

Thank you ma'am

[@Aakash_JEE]

Most welcome 😊

[@HarshSharma-nm8ft]

ans D

[@Am98765]

mam we can also solve it by using congruence of numbers

[@Yaara_1]

8

[@_vikasjain]

Same question came in 30 Jan 2nd shift 2023

[@Gamewithrishi2.0]

❤❤❤

[@Starshine_Swastika]

❤

[@usera-rv3fk]

Which college u are in now?

[@srijasri_pandi]

Why did we ignore that 9?

[@darsuhaib8900]

Bcz anything multiplied to that 9 wil give us a no. Which will be divisible 9 => remainder=0

[@PXO005]

Try expanding that binomial, you'll see all the terms which are multiples of 9 will give 0 remainder, except the term which is independent of 9, ie ncn(9^0) 2^n

[@theschoolboy8749]

It is trick.. 🤭

[@sumitjiola8405]

D

[@medhashree9652]

Ipmat aspirants: huh, this is a cup of tea for us 😅

[@_ishana.xd_]

But why are we ignoring 9
Pls tell

[@mrmaximus.]

Because that 9 multiple of something which and this no. Is divisible by 9. Thats why we can ignore 9 and solve with remainder.

[@_ishana.xd_]

@@mrmaximus. understood
Thanks a lot

[@hardilpatel9750]

How can we find remainder of (2021)^2022 +(2022)^2021 when divided by 7

[@PXO005]

@@hardilpatel9750 I'm not sure about this but I did like this:
2021= 7 x288 + 5, 2022= 7x288 +6
2021) ^2022 is then equivalent to (5^2022)
Which is (125)^674=(7x18 -1)^674 so remainder there is 1.
From the other bracket, (2022) ^2021,
We get (6) ^2021. 7
6=7-1, so remainder is -1.
Net remainder is -1+1=0

[@itachu.]

​@@PXO005man this is one confusing topic

[@NoOne0223]

337 or 37

[@vijayKumar-hv7nc]

mam how can be remainder negative is it a miracle!!

[@joe6245]

It's with respect to the nearest multiple of the divisor like when 17 is divided by 9, remainder is 8 but w.r.t 18(which is the nearest multiple of 9 to 17), it's -1.

[@AMAN__KA01]

It's an easy and oral questn

[@ayanA350]

IOQM aspirants laughing in the corner.

[@Manwithpatience8540]

meanwhile inmo qualifier laughing at this peasant who wrote this cmnt

[@rahul1yrago301]

Tera huya ioqm

[@ayanA350]

@@rahul1yrago301 yea

[@GaneshRam-ko1tu]

11 I can write 10+ 1 also right but y we are not using this

[@Cape-aep]

The question was based on divisibility of 9. So we write 11 in terms of 9 which is (9+2) and in the next step we ignore 9 as 9÷9 gives remainder 0.

[@in-abssappreview3456]

But why we can write 11 as only 9+2 ?🧐

[@BijayKumar-pl5pi]

As it contains 9 which will be divisible by the divisor

[@divyeshgaigol9035]

Abe ye kya hai😂😂

[@govinds8618]

Where is the binomial😂

[@lakitapatil2099]

9 ko ignore kyu? Aapko pasand nahi he kya 9??😂😂

[@Nowmylifeis.swee.like.cinnamon]

9 is divisible by 9 hence removing it is better, ultimately it will give remainder as zero when you expand it

[@user-zs9bk2xh2h]

Dimag ka bhosda ho gaya mam

[@atanupatra8016]

Thanks Mam

[@Aakash_JEE]

Most welcome 😊

[@creativeandamazingthoughts2672]

8

[@varshitamishra4679]

8