Finding Remainder using Binomial Theorem | Most Asked Problems in JEE Main 2022 | Bhoomika Ma'am

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Join this JEE live class on Finding Remainder using Binomial Theorem. In this Aakash BYJU’S 45-Day Crash Course Series, our Maths expert, Bhoomika Ma’am, takes you through the Most Asked Problems in JEE Main 2022 to boost your JEE Maths preparation for the JEE Main 2023 exam.
Further, Bhoomika Ma'am discusses the following topics in this class:
1. How to find Remainder using the Binomial Theorem?
2. Remainder questions Binomial Theorem
3. Most Asked Maths Problems in JEE Main 2022
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Solving Remainder problems for JEE Mains is crucial to improve your problem-solving for the JEE Main Maths section. Get your doubts resolved by asking in the live chat box below. At the end of this class, Ma’am takes a few moments to clear your queries.
Like, comment, and share this video with your friends and JEE droppers to help them practise JEE Mains Remainder questions to strengthen their JEE Maths preparation. Subscribe to the Aakash BYJU’S JEE channel to access chapter tests and mock tests to prepare excellently for the JEE Main & Advanced 2023 exams. Do not forget to hit the like button if you find this video beneficial.
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[@Aakash_JEE]

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[@jgyasu]

I always struggled with this topic and there is no other lecture on this topic on the entire internet that discusses this many variety. So, thank you very much! Grateful.

[@Aakash_JEE]

Glad it was helpful!

[@namitadlakha5963]

Go watch nv sir . He taught this method much earlier

[@asmatabassum1228]

Thanks mam it's help me lot..first i will fear with these types of questions.but now onward i am confident in remainder problems .thanks......

[@taraa282]

Thank you so much ma'am you have clarified my all doubts so simply and beautifully. I was struggling a lot in this part.

[@aabbc9393]

Thank you ma'am it was wonderful session . Pls take more sessions on repeated questions

[@arnav9681]

For the question of finding the remainder 1+3+3^2....3^2021 is divided by 50, we get (3^2022-1)/2.... can we write 3^2022 as (3^5)^404 x 3^2..... and then write 3^5 = 250-7.... and then solve?

[@Games_Era44]

HW answer 16

[@venkateshsrao448]

A very warm Teacher's Day greetings to you Bhoomika ma'am.
I have been viewing your sessions for sometime now.
You are a very dedicated and wonderful teacher.
I wish you many many more years of happy and successful teaching.❤

[@jyotirmaysingh1818]

Thank you mam for this wonderful conceptual clarity

[@pragati1202]

Mind-blowing session ma'am thankyou ❤❤❤❤

[@SillaStinu]

TQ mam I like it so much 😊😊❤❤

[@XAbdeVilliers]

Thank you mam🙏🏼🙏🏼
Mam please suggest me book, those book have this kind of problem and solution and theory .

[@Kuldeepgupta11707]

Thank you maam 🥰🥰🥰🥰🥰

[@SifiAs]

Now I learned how to solve such question ❤

[@dhruvvarshney3356]

Thankyou so much mam

[@ashlin_nit_c]

Super duper amazing session mam. Nycc trick. Had funn learning with u. Thank u mam :)

[@Aakash_JEE]

Glad to hear that

[@kartikmarwari9048]

Thank you ❤️

[@machchanarayanarao1088]

I like it soo much lovely mam

[@bhagyavardhan13]

ANSWER TO HOMEWORK QUESTION
{81^82/17}
According to the theorem, 81^16 when divided by 16, gives the remainder as 1
But 82 is not divisible by 16, the remainder comes as 2
So, take 81^2 common
We get 81^2 ( 81^80/ 17)
= 81^2 = 6561 /82
THE REMAINDER COMES AS 1

[@koshtubhtiwari6569]

Galat hai 🤧

[@shauryaaggarwal4966]

Thanku mam, I learnt this concept very well...👏👏👏👏👏👏👏👏

[@Aakash_JEE]

Most Welcome !!

[@shivamagrawaldz]

How can i download the pdf mam

[@karanonkar12]

6;40 start

[@abhishekcreation003]

6:50 starts

[@raghavyatgiri7529]

Best lecture on this topic❤

[@Aakash_JEE]

Glad to hear that

[@raghavyatgiri7529]

🎉🎉

[@abhishekcreation003]

Mam really love this session

[@Aakash_JEE]

Glad to hear that

[@vv_ryder2819]

Ma'am...u teach sooooo good ..deeply attracted by your teaching style .. byjus has done something very good

[@Aakash_JEE]

Thanks a lot

[@AnimeNotion5865]

Atleast

[@shubhamsupekar]

Class pdf please

[@Sunny-zv4dc]

343=342+1 not 342-1

[@vuvshaclasses9692]

9

[@Vion--]

GB sir💪

[@namerectified4041]

how to solve (2023)^2023 div by 35 with this method?

[@muhammadzedan9682]

break 35 into 5X7 then divide 2023 with 7 completely(thus the remainder we obtain RX7) then u will be left with 289(2023)^2022 /5 then u will be left with -1(-2)^2022/5 then 2 square is 4 so now we have -1(4)^1011 / 5 thus now we have 1/5 thus r=1 and now actual remainder is RX7 1X7 = 7.....

[@namerectified4041]

@@muhammadzedan9682 thank you

[@muhammadzedan9682]

No problem
All the best for ur exam..

[@VardhanShah-ex9sm]

27

[@cbse19]

Nishant vora copyright ©️ claim are madam jb pdana hi nahi atta toh copy kyo karte ho

[@kingshukghosh3967]

All teachers has started coping from Nishant Vora sir 😂

[@Jee_anthem]

What?

[@Shitalshaw2620]

@@Jee_anthem yes

[@ojasniva366]

I think this was better though.

[@Naveen14727]

Same prices nothing to copy .. everyone teaches the same but the way teaching is different

[@mathplusbyanandsir3293]

Ye method nishant vohra se v pahle tha

[@Aanchalshukla3006]

Hw answer 16

[@mabrurchoudhury2546]

Ma'am the way you solve questions and teach us Is literally FLAWLESS 🔥❤
Bhoomika Ma'am - Goddess of Maths

[@Aakash_JEE]

Thanks a ton

[@jeeoriented]

Thnks mam helped a lot 😅😅❤

[@Aakash_JEE]

Glad it was helpful !!

[@bharaththonukunuri3532]

31:11 😂

[@Anjal-jo2xi]

Better explanation on remainder theorem thanks mam your are a great 🙏🙏

[@Aakash_JEE]

Most welcome 😊

[@bb4385]

Jee 2023 April meh dekhna ma'am bhar bhar ke remainder ke sawaal aayenge

[@Shogun507]

Oh is it? Well, might as well solve those questions for practice then