This method does work for any number... but if you use a random number generator, it might involve some uncomfortably big prime numbers. My advice is to artificially create examples to work with, just like they do in GCSE maths. Mix up a selection of primes to create a composite, if you're a teacher, or looking to try the method out. Then extract your primes (what a surprise, they are the same ones you mixed up in the first place), then apply the method and see what ALL the factors of this number are. Then, if you're like me, go to an online factor finder and see what it says. Be delighted that you got the same set of factors for your number.
@amelia christie I DO wish you good luck. Do you have a test coming up? Hope you ACE it! If you plan to use this method, please make sure you've done a bunch of practice first, and you are completely comfortable using it. I'd hate for you to have an 'Oh no, what next?' moment in a test.
This method looks great. But I would love if you made a video writing the step by step algorithm you use to combine and multiply the primes. It's a bit confusing.
4x81 =324, and that's included at the end when you list in ascending order. To be honest, mostly questions are concerned with finding the prime factors, which is no problem. This is for those annoying times when they want you to list ALL the factors of a number. I came up with this method as a self-help method, because when I use any other method, I generally miss a couple of factors. I find that annoying. This is my way for me to be rigorous. It might help other people too.
Currently teaching my child about this. I tried to follow the method for the number 600, but couldn't make it work to a) identify all of the factors; b) got some answers that were not factors of 600. It may be my application of the theory. Can anyone sense check this for me? I eventually worked it out manually - there should be 24 factors in total: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 25, 30, 40, 50, 60, 75, 100, 120, 150, 200, 300, 600. Any help or guidance is greatly appreciated
If this is first contact with this kind of problem, it’ll be more manageable to think about this differently, through tables knowledge. Maybe start with 60. Use either the factor rainbow type of layout, or linear approach on the page and when factors converge very close together, you know you’ve found them all. So 1x60 2x30 3x20 4x15 5x12 6x10 When listing them, read and list down left hand (low values in ascending order, then read and list up right hand, greater values in order to write them all in ascending order. Always best to take math in little easy steps. If it seems easy, a learner will engage. If it seems complex and dense, the block goes up. Don’t let that happen. Easy = engagement, engagement leads to success, or just needing a bit of help. Successful math practice certainly leads to happy kid and happy teacher/parent. 😃
You're most welcome 😊. When I thought this approach up it seemed so obvious, I wondered why I'd never seen this taught. At least I can share it now with anyone who wants a way to succeed at this sort of question without sweating it. Guess-and-check takes SO long, it's just awful. It makes the person doing it feel like they've got something wrong with them. Or maybe it's just me that doesn't enjoy feeling like I'm randomly trying stuff in maths, wasting time and not getting a result. I like this approach very much, it works!
God bless you! this is so good and I really needed this because it was very detailed and very fast I can't believe it I'm in grade six and all these days I haven't found a video and now I have thank ! now u are my favorite math channel u have a new subscriber!
I learned about this in my GCSE Maths tonight, and it was fun. I watched your videos and tried some of my own. I used a random generator to use a 5 digit number and the very first number was 74299. I used all the rules of divisability between 2-12 and I cannot do it, can you help?
+WhatsMyHand Hi there - really quickly may I compliment you on seriously giving it a crack? Next I want to say this... GCSE maths is not going to give you massively unsolvable numbers. Why don't you artificially create some, like I do in my examples. I select numbers by choosing a set of primes and mixing them up to create some tough looking composite number which is actually workable. It has to be something that a 16 yr old can reasonably do the prime factorization for. So I would mix up a batch of primes featuring 2, 3, 5, 7, 11, 13 and maybe 17. That should give you enough scope to start with. Then once you've got the hang of it you can chuck in a larger 2-digit prime for laughs. Steer clear of auto number generators. It sounds like a good idea but when they involve a 3-digit prime or higher, it is not doing you any favours and you are not going to get anything like that on a GCSE paper.
Hi there, thanks for your question. I can't do 2x4 because the 2x2 combine to make the 4. There isn't an unused 2 here. 2x4=8, and 8 is not a factor of 324. You can check it: 324÷8 =40.5 Does that help?
@@LetsDoMath Yes, thanks. I understand now. I have found it easier to work out when I find combinations using all the prime factors, every time. For example, 2 x 2 = 4, then multiply this with the remaining factors to get 4 x 81 as two factors
Hi again. So, we are seeing here that auto number generators are not the way to go. GCSE maths is not going to do that to you. You could look up past GCSE maths questions on finding all the factors for some real examples of the type you will get. This will build confidence. Just view past papers and read through till you get to those questions. Have a go at it, then consult an online factor finder and see how you did. If there are any typos in this... sorry. I'm beat and I was on my way to bed. Checked for notes first and can't leave yours unanswered. Hope this helps. 👍🤔😃
Even though this is a year old, I'll still help. 3245364763524/546 can be done using long division or....a calculator. Technically you just do what you do for something like 2500/10.
@@ut_fan8787 yeah, long division but then the numbers are too big. I think its a troll. but if its not then how do u divide all then numbers by 546? youll need to know the multiples of it, but its too big a number that someone would actually memorise.
Looks like my reply did not arrive - or it’s just not showing on my phone for some reason. Yes, follow the method. All possible combinations. If you combine all 4 primes you get your value of 140.
@@yasanagis Did you get it? Once you THINK you’ve done it, you can always check with an online factor finder. In fact, that’s a great idea as you are getting used to this method. If you miss one, it’ll alert you. You will then go through and find your mistake and then next time, you probably won’t make the same omission. It’s all about learning and practice. Just give it your best shot. You can do it!! 😃🤗😎😉💕
Did you see the first video? That shows what's going on clearly - it's easier to see because all the primes are different.. This vid relies on you having that groundwork. This is the way computer programs do it, to get all the factors of a number. This is just my 'on-paper' alternative to a computer. On the first line of calculations with the primes, I work out the 'prime x itself' combos: 2x2 and 3x3... 9, 3x3x3...27 and 3x3x3x3... 81 On the next line down I combine 2 x the 3 combos and then the line after that 2x2 (or 4 times) the 3 combos. After you've combined the primes, you combine the composites. That's what gets you the full set of possible combinations.
I made a different method with this, as I tried to figure out what I'd do with repeating primes, lmao. I just added the repeating primes with powers, and it this hypothetical method kinda works.
I have to be honest ma’am, you just saved my maths solving career; thank you so much and God bless, I am really grateful.
It's my pleasure! Glad to help out.
This method does work for any number... but if you use a random number generator, it might involve some uncomfortably big prime numbers. My advice is to artificially create examples to work with, just like they do in GCSE maths. Mix up a selection of primes to create a composite, if you're a teacher, or looking to try the method out. Then extract your primes (what a surprise, they are the same ones you mixed up in the first place), then apply the method and see what ALL the factors of this number are. Then, if you're like me, go to an online factor finder and see what it says. Be delighted that you got the same set of factors for your number.
@amelia christie I DO wish you good luck. Do you have a test coming up? Hope you ACE it! If you plan to use this method, please make sure you've done a bunch of practice first, and you are completely comfortable using it. I'd hate for you to have an 'Oh no, what next?' moment in a test.
BEST!
Thanks very much. Glad to help.
This method looks great. But I would love if you made a video writing the step by step algorithm you use to combine and multiply the primes. It's a bit confusing.
That's the good spirits 🎉😂😮😊😊
Hi
Why did you stop with 4 × 27 and u did not do 4× 81.thanks ma'am
Why didn't you multiply 4 x 81? Very confusing multiplying the prime combinations. Isn't there an easier way to do the prime combinations?
4x81 =324, and that's included at the end when you list in ascending order.
To be honest, mostly questions are concerned with finding the prime factors, which is no problem. This is for those annoying times when they want you to list ALL the factors of a number. I came up with this method as a self-help method, because when I use any other method, I generally miss a couple of factors. I find that annoying. This is my way for me to be rigorous. It might help other people too.
@@LetsDoMath thx for explaining, really helpful.
Currently teaching my child about this. I tried to follow the method for the number 600, but couldn't make it work to a) identify all of the factors; b) got some answers that were not factors of 600. It may be my application of the theory. Can anyone sense check this for me? I eventually worked it out manually - there should be 24 factors in total: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 25, 30, 40, 50, 60, 75, 100, 120, 150, 200, 300, 600. Any help or guidance is greatly appreciated
If this is first contact with this kind of problem, it’ll be more manageable to think about this differently, through tables knowledge. Maybe start with 60. Use either the factor rainbow type of layout, or linear approach on the page and when factors converge very close together, you know you’ve found them all.
So
1x60
2x30
3x20
4x15
5x12
6x10
When listing them, read and list down left hand (low values in ascending order, then read and list up right hand, greater values in order to write them all in ascending order.
Always best to take math in little easy steps. If it seems easy, a learner will engage. If it seems complex and dense, the block goes up. Don’t let that happen. Easy = engagement, engagement leads to success, or just needing a bit of help. Successful math practice certainly leads to happy kid and happy teacher/parent. 😃
This was really helpful
Why didn't you use the 4 to multiply the 162
Thank you so much ma'am, you are a genius.
You're most welcome 😊. When I thought this approach up it seemed so obvious, I wondered why I'd never seen this taught. At least I can share it now with anyone who wants a way to succeed at this sort of question without sweating it. Guess-and-check takes SO long, it's just awful. It makes the person doing it feel like they've got something wrong with them. Or maybe it's just me that doesn't enjoy feeling like I'm randomly trying stuff in maths, wasting time and not getting a result. I like this approach very much, it works!
But how do you if you’re done?
God bless you! this is so good and I really needed this because it was very detailed and very fast I can't believe it I'm in grade six and all these days I haven't found a video and now I have thank ! now u are my favorite math channel u have a new subscriber!
You're so welcome! I'm glad to help, and I hope you now ace that homework! Thanks for subscribing. I appreciate that , very much.
I learned about this in my GCSE Maths tonight, and it was fun. I watched your videos and tried some of my own. I used a random generator to use a 5 digit number and the very first number was 74299. I used all the rules of divisability between 2-12 and I cannot do it, can you help?
+WhatsMyHand
Hi there - really quickly may I compliment you on seriously giving it a crack?
Next I want to say this... GCSE maths is not going to give you massively unsolvable numbers.
Why don't you artificially create some, like I do in my examples. I select numbers by choosing a set of primes and mixing them up to create some tough looking composite number which is actually workable. It has to be something that a 16 yr old can reasonably do the prime factorization for. So I would mix up a batch of primes featuring 2, 3, 5, 7, 11, 13 and maybe 17. That should give you enough scope to start with. Then once you've got the hang of it you can chuck in a larger 2-digit prime for laughs. Steer clear of auto number generators. It sounds like a good idea but when they involve a 3-digit prime or higher, it is not doing you any favours and you are not going to get anything like that on a GCSE paper.
Why not 2 times 4 there?
At the end it said that i got it but i dont get my question
The method is really interesting. But why don’t you do 2 x 4? Isn’t that a combination too
Hi there, thanks for your question. I can't do 2x4 because the 2x2 combine to make the 4. There isn't an unused 2 here.
2x4=8, and 8 is not a factor of 324. You can check it: 324÷8 =40.5
Does that help?
@@LetsDoMath Yes, thanks. I understand now. I have found it easier to work out when I find combinations using all the prime factors, every time. For example, 2 x 2 = 4, then multiply this with the remaining factors to get 4 x 81 as two factors
Tysm 😊
It was difficult to grasp. But I finally got it. Thank you.
It’s fiddly with repeating primes. Well done for sticking with it! 😃😎
The next number 82438. I divided by 2 and came to 41219, and that is how far as I could go.
Hi again. So, we are seeing here that auto number generators are not the way to go. GCSE maths is not going to do that to you. You could look up past GCSE maths questions on finding all the factors for some real examples of the type you will get. This will build confidence. Just view past papers and read through till you get to those questions. Have a go at it, then consult an online factor finder and see how you did.
If there are any typos in this... sorry. I'm beat and I was on my way to bed. Checked for notes first and can't leave yours unanswered.
Hope this helps.
👍🤔😃
Hello I am stuck on how to do 3245364763524 divided by 546 its a question in my math test
Even though this is a year old, I'll still help. 3245364763524/546 can be done using long division or....a calculator. Technically you just do what you do for something like 2500/10.
@@ut_fan8787 yeah, long division but then the numbers are too big.
I think its a troll.
but if its not then how do u divide all then numbers by 546? youll need to know the multiples of it, but its too big a number that someone would actually memorise.
You’re spot on, this is a troll for sure. 👿 What teacher gives THAT in a test?!?!
what if i get 2,2,5,7 would u still multiply them in combinations of 3?
Looks like my reply did not arrive - or it’s just not showing on my phone for some reason.
Yes, follow the method. All possible combinations. If you combine all 4 primes you get your value of 140.
@@LetsDoMath okay thankyou so muchh
@@jewelleescalona2128 My pleasure.
I need to find the factors of 2,400
I got 2,2,2,2,2,3,5,5 as the prime numbers and i’m a bit confused on which number do i multiply 3 with
Set it out like I do in the vid, follow step for step. Hit pause on the vid while you do the same on paper.
Trust the method. 😃🤗😉💕
@@LetsDoMath Thank you!❤️
@@yasanagis Did you get it? Once you THINK you’ve done it, you can always check with an online factor finder. In fact, that’s a great idea as you are getting used to this method. If you miss one, it’ll alert you. You will then go through and find your mistake and then next time, you probably won’t make the same omission. It’s all about learning and practice. Just give it your best shot. You can do it!! 😃🤗😎😉💕
Wow it’s good trick ..
Thanks Estella. I was pretty happy when I came up with it. 🤗😃😎😉
How to do it for 120 I am confused how we get 60 using multiplication
Hi there. I have just come in from shovelling ice and snow... and seen this note. 60 is half of 120, so 2x60 = 120. Does that help?
Why don’t you use the three to times the rest of the numbers as well?
Did you see the first video? That shows what's going on clearly - it's easier to see because all the primes are different.. This vid relies on you having that groundwork.
This is the way computer programs do it, to get all the factors of a number. This is just my 'on-paper' alternative to a computer.
On the first line of calculations with the primes, I work out the 'prime x itself' combos: 2x2 and 3x3... 9, 3x3x3...27 and 3x3x3x3... 81
On the next line down I combine 2 x the 3 combos and then the line after that 2x2 (or 4 times) the 3 combos.
After you've combined the primes, you combine the composites. That's what gets you the full set of possible combinations.
It's really hard. Very confusing what to multiply and what to not!
It's not for the faint of heart, or if you haven't done a TON of prime factorizations. Once you have though, you can get your head around it.
@@LetsDoMathwould it be better to do practice questions including prime factorization then come back and review both videos?
Not sure this video will help me factoring RSA-896 😟
I did not understand it
I made a different method with this, as I tried to figure out what I'd do with repeating primes, lmao. I just added the repeating primes with powers, and it this hypothetical method kinda works.
Please help
film