Mechanics of Materials-Lecture-08-Generalized Hooke's Law

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  • Опубликовано: 5 ноя 2024

Комментарии • 20

  • @agnidhroganguly2116
    @agnidhroganguly2116 4 года назад +1

    A great video which is very easy to follow and understand . This video will be very helpful for beginners . I had just started learning Solid Mechanics and this video helped me in clearing the concept of Generalised Hookes Law. Thanks a lot Sir . GOD bless you.

  • @aymericzambo345
    @aymericzambo345 6 лет назад +1

    THank you sir for the explanation. I have been trying to figure out for over 15 minutes where they got that expression for Ex, Ey and Ez and now it is so clear. This has been of much help to me . Thank you again

  • @aimanal-akwaa110
    @aimanal-akwaa110 8 лет назад

    man - you are good. ill share it with my class mates.

  • @DesireeLekamge
    @DesireeLekamge Год назад

    me about to cry becasue this is so much better than my lectures( still grateful for both tho)

  • @vilivont4436
    @vilivont4436 10 месяцев назад

    Really great lecture, thank you a lot.

  • @Leonanas
    @Leonanas 4 года назад

    easy to follow and concise! thank you for this video (:

  • @alirezakarimi4977
    @alirezakarimi4977 3 года назад

    Excuse me Sir,I think in the second example let's say in 21:00 ,you made a miscalculation for epsilon z.I checked it with 2 different ways and I found it only 10^-4.Is it possible for you to check it ?

  • @mojojojo6967
    @mojojojo6967 8 лет назад

    Thank you for the video!
    A little comment: the letter ''ν'' is Greek and it is pronounced ''nee''.

    • @mbarkey.mechanics
      @mbarkey.mechanics  8 лет назад +1

      Thanks for the comment. I am sure there are more ways than one to pronounce the various Greek letters and these things can change with region and in time. This is the pronunciation that I have always known: www.oxfordlearnersdictionaries.com/definition/english/nu and is the way it is commonly pronounced in US engineering schools. :cheers:

    • @mojojojo6967
      @mojojojo6967 8 лет назад

      As a native Greek speaker, I was not aware of that.
      Cheers!

  • @druzzee
    @druzzee 7 лет назад

    Hello, thanks for the video! Could you explain maybe how to express Sigma x, Sigma y and Sigma z through Epsilon x Epsilon y and Epsilon z. You somehow sum these Epsilons and you get Sigmax=(E/(1+nu)(1-2nu))*((1-nu)epsilonx +nu(epsy+epsz))

    • @mbarkey.mechanics
      @mbarkey.mechanics  7 лет назад

      What I showed at 22:11 was how to get sigma_x and sigma_y in terms of eps_x and eps_y (with sigma_z = 0, i.e. two equations and two unknowns ). For the most general case of all three equations and three unknowns, you have a system of equations that you need to invert. When written in this form, the algebra is terrible, but it can be done with a substitution and reduction method. Alternatively, you can use some tricks from linear algebra (matrix inversion). The easiest way though is to write the elastic constants in terms of Lame' coefficients and use index notation, as is usually done in Theory of Elasticity see: en.wikipedia.org/wiki/Lam%C3%A9_parameters. Perhaps I can find time to do the algrebra for those methods some day, but not this day!

    • @druzzee
      @druzzee 7 лет назад

      Well I'm supposed to solve it without using Lames coefficients, only through eps x, eps y and eps z.
      Thank you anyways and thanks for the quick response!

  • @mrvk699
    @mrvk699 6 лет назад

    Why have you reversed the terms in the poission's ratio?
    Isn't it supposed to be the Ratio of the Lateral strain to the Axial strain?

    • @mbarkey.mechanics
      @mbarkey.mechanics  6 лет назад +1

      Can you provide the minute mark of the video for me to review?

    • @mrvk699
      @mrvk699 6 лет назад

      Mechanics Channel by Mark Barkey Actually It turns out, the Formula written in the textbook i was using was having Wrong formula, and There was a reprint issued for the same the following year, for the correction of same.
      You have a Legit video!

    • @mbarkey.mechanics
      @mbarkey.mechanics  6 лет назад +1

      Thanks Vishal. I certainly make my share of mistakes so stay vigilant :)