For the bicycle problem Vi=10m/s D=780m A= 0.1m/s^2 and T= 60s. I get different final velocities depending on the formula used. For D=1/2(vi+vf)t I get 19.33, but for vf=vi+at and vf^2=Vi^2+2ad I get 16. What am I doing wrong?
I think the answer should be 16 cause Vf for driver 1 is the Vo for 2. So if you just find that then you can calculate for the Vf for driver 2. Then you can just plug everything in the formula Vf = Vo +at, Vf = 10 + 0.1*60, Vf = 16
I thought maybe for the part where the trains are travelling in same direction , we should say time to catch the slower train is found by using only speed of faster train and distance apart
sir which chapters do i need to know from physics 1 to do physics 2?.. i use the book (physics for scientists and engineers with modern physics 8th).. do i need to know all 23 chapters form physics 1 respectively in order to do physics 2 or just a small bunch of it?
there is a mistake on the second question i think you forgot to square the time because the equation is such that s=ut+1/2(a)(t)^2
Yessssss u ryt onkarabile
definitely, thank you for confirming my confusion
hello teacher I. think that the ans in min 16:57 should have been 26.1. because the d=0.5at but t should be squared
I agree, if you plug it into the other formula as well the answer comes out to 26.1
my answer is 26.1 too. I thought i was wrong until i read your comment
why he didnt use the formula s: equals d/t
he forgot th square
@@haveacupacapuccino4834 I think he used d=1/2(v0+vf)t formula
There's a mistake with the second question in the second part
It's supposed to be d=a(t×t)÷2
for question 2 you have t^2 so it should be 26.1m if that's right ?
Yeah since he forgot the power 2 on the original equation so 1/2at^2 giving 26.071 approx 26.1
I like the way your voice sounds
thank you for the lovely video too btw. just wanted to mention ^
what is the relative velocity thing you did for problem 6 ? I dont get it.
In 34:47 its should be t = 4 hours.
That's why you need to put your units.
@@dumlaogideonashleyq.6277 you are right
For the bicycle problem Vi=10m/s D=780m A= 0.1m/s^2 and T= 60s. I get different final velocities depending on the formula used. For D=1/2(vi+vf)t I get 19.33, but for vf=vi+at and vf^2=Vi^2+2ad I get 16. What am I doing wrong?
I was looking for the speed of the initial rider btw.
I think the answer should be 16 cause Vf for driver 1 is the Vo for 2. So if you just find that then you can calculate for the Vf for driver 2. Then you can just plug everything in the formula Vf = Vo +at, Vf = 10 + 0.1*60, Vf = 16
I got the same answer as well.
I thought maybe for the part where the trains are travelling in same direction , we should say time to catch the slower train is found by using only speed of faster train and distance apart
sir which chapters do i need to know from physics 1 to do physics 2?.. i use the book (physics for scientists and engineers with modern physics 8th).. do i need to know all 23 chapters form physics 1 respectively in order to do physics 2 or just a small bunch of it?
for the bus and car problem, the bus has constant speed not acceleration, so should be d=vt
Is not it that the trains meet after 4 hours?
In the second Question the time must be squared and the correct formula is
s = ut + (1/2)at²
i love this explanation its help me every time
For problem 2 can you use d=1/2(Vo+Vf)t as the equation instead?
I discovered that it is actually easier and you won't make the same mistakes he did
Hello, I would like to Collab with you sir
Great but at some point the questions are not visible i mean like being blurred
You know your stuff❤❤
This train problem at 34min... two trains that are 600 miles apart? really 4s? they mu st be worlds fastest two trains
he meant 4 hr
21:00 the acceleration is not constant so we cant use the formula Vf_Vi = 2ad
Because we are calculating the final velocity for segment one, the acceleration is constant.
i don't understand the last question it's not clear like the other ones but great job
great help,thank you
Life saver😊
bruhhh r u fr in the second question??? 4.5 meters in a span of 5seconds???????
4s I thought should be in 4h
Great help
What is this subject?😵
@etgsuryoutube8476 lmao
mistake in second question