U3 L4.3 | 3 Bit Asynchronous Counter | MOD-8 counter | Mod 8 Asynchronous counter using T Flip Flop

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  • Опубликовано: 30 ноя 2024

Комментарии • 16

  • @gayathrigayu4741
    @gayathrigayu4741 6 месяцев назад +1

    Mam can you explain in video about asynchronous mod8 down counter using jk flip flop.

    • @TechnoTutorials2783
      @TechnoTutorials2783  6 месяцев назад +1

      ruclips.net/video/yZkozx-g_Ho/видео.html
      Refer above video all will be same only use JK FF in place of T

    • @gayathrigayu4741
      @gayathrigayu4741 6 месяцев назад +1

      @@TechnoTutorials2783 tq mam 👍

  • @daishakpatel224
    @daishakpatel224 Год назад +2

    Thank you mam for making this video.

  • @SerishaAwale
    @SerishaAwale 3 месяца назад

    why didnt u use nand gate???
    when should we use nand gate???

    • @TechnoTutorials2783
      @TechnoTutorials2783  3 месяца назад

      In this case max count value is 7 and by using 3 binary digit we can represent 0 to 7
      If 3 bit counter will count less than 7 like 4 or 5 then we will use nand

  • @shivamnirmalkar6251
    @shivamnirmalkar6251 Год назад +2

    Thank you Mam

  • @nmn00
    @nmn00 3 месяца назад

    Thank you maam

  • @Vaibhavshot
    @Vaibhavshot Год назад

    Mam mod 6,7,8 asynchronous counter will same

    • @TechnoTutorials2783
      @TechnoTutorials2783  Год назад

      Yes for 6 and 7
      Only input for nand gate will be different
      In case of mod 8 nand gate not required only 3 flip flop

    • @Vaibhavshot
      @Vaibhavshot Год назад

      @@TechnoTutorials2783 can u please tell the reason for mod 8 asynchronous counter why don't we use nand gate?

    • @TechnoTutorials2783
      @TechnoTutorials2783  Год назад

      @@Vaibhavshot because for mod 8 only 3 flip flop required
      Mod 8 will count 0 to 7
      By 3 flip flop max value is 111
      Hence nand gate not required
      8 =1000
      If u rbusing 4 ff for mod 8 then nand required
      But we caount using 3 ff

    • @Vaibhavshot
      @Vaibhavshot Год назад +1

      @@TechnoTutorials2783 ok ma'am thanks 😊