DO LIKE THE COMMENT IF I HELPED YOU! LECT STARTS AT 10:00 AREA OF TRIANGLE 22:05 AREA OF QUADR. 26:20 SLOPE OF LINE 34:51 iNTERCEPTS 34:30 EQUATIONS OF STRAIGHT LINES 52:32 Normal/ perpendicular form 01:08:05 Angle between 2 straight lines 01:31:18 5 Imp things about triangles 2:23:54 locus of point 3:09:36 Lenght of perpendicular 3:24:35 Parametric eqn of straight line 3:45:34 Position of point wrt to line 3:53:43 Concurrency of 3 lines 4:00:48 Family of st lines 4:07:11 Optics based questions 4:45:20 Pair of st lines 5:22:09 Homogenisation 5:44:00
16:08 (pyq) 18:53(pyq) 31:21(pyq) 47:02(collinearity check by determinant method) 49:01 1:17:25(imp note for normal form of line is that:P ka value hmesha +ve hi hoga, since P is distance. So we have to adjust theta according to it) 1:20:13(pyq) 1:24:02(pyq,bisceting ,we can use mid pt formula) 1:27:42(pyq) 1:50:54(PYQ) 2:28:40(key step to find circumcentre) 2:38:04(finding orthocentre) 2:44:02(spcl case:right triangle) 2:46:21(case of equilateral triangle) 2:49:23(ortho,centroid,circumcentre are collinear and ratio wala cheez hmesha right angle triangle se yaad rkhna) 2:50:50(pyq) 2:56:449(pyq) 3:01:26[pyq, isme as circumcentre is also the origin, thus assume points as (Rcosa,Rsina) (Rcosb,Rsinb)and (Rcosy,Rsiny) kuki sbhi centre se R hi ke distance pe honge] 3:10:40(Working rule for finding Locus) 3:14:18 3:18:00(Imp case of A stick lying against coord axes: The middle pt of stick moves in a circle,with radius =Length of stick/2) 3:29:40(pyq) 3:34:49(adv,20) 3:45:30(Parametric form of St line, kab aur kese lagate h) 3:49:18(pyq on Parametric form of St line) 3:57:39(pyq) 4:02:02(condition for concurrency of 3 lines) 4:03:13 4:07:47(fam of St line ka eqn tbhi lagana ,jab ek line ka eqn pche ,jo intersection of L1 and L2 se pass krrha hoga) 4:18:02(fam of St line de dia ho, to wha se eqn ko split krke L1 and L2 split krnaa ana chahiye) 4:40:35(if coeff of eq of fam of line are in AP , then finding fix pt) 4:43:43(pyq) 4:51:43[img of pt (a,b) abt the line y=x is (b,a)] 4:52:23(reflecting line problems) 4:55:03(pyq) 4:59:27(adv,19) 5:11:46(problem on angle bisector of two lines) 5:14:36(after making constants+ve...jo bhi a1a2 + b1b2 ka sign milega ,whi sign hoga obtuse bisector ka) 5:16:04(working rule for bisctor containing origin: just make constant+ve & +ve sign wla hmesha containing origin) 5:19:09(if a1a2 +b1b2=0 ,then both are perpendicular angle bisector) 5:29:52[pair of St line passing thru origin have eqn: ax²+2hxy +by²=0 and h²-ab≥0(discriminant≥0)] 5:31:52(way to solve eqn of pair of St line passing thru origin, just put y=mx) 5:36:49(spcl cases for pair of St lines),5:44:35(homogenisation : kab aur kese lgaenge) 5:46:48(eg of homogenisation) 5:57:30(adv,21)
18:53(pyq), 31:21(pyq), 47:02(collinearity check by determinant method), 49:01, 1:17:25(imp note for normal form of line is that: P ka value hmesha +ve hi hoga, since P is distance. So we have to adjust theta according to it), 1:20:13(pyq), 1:24:02(pyq,bisceting ,we can use mid pt formula)1:27:42(pyq),1:50:54(PYQ),2:28:40(key step to find circumcentre),2:38:04(finding orthocentre),2:44:02(spcl case:right triangle),2:46:21(case of equilateral triangle),2:49:23(ortho,centroid,circumcentre are collinear and ratio wala cheez hmesha right angle triangle se yaad rkhna),2:50:50(pyq),2:56:449(pyq),3:01:26[pyq, isme as circumcentre is also the origin, thus assume points as (Rcosa,Rsina) (Rcosb,Rsinb)and (Rcosy,Rsiny) kuki sbhi centre se R hi ke distance pe honge], 3:10:40(Working rule for finding Locus), 3:14:18, 3:18:00(Imp case of A stick lying against coord axes: The middle pt of stick moves in a circle,with radius =Length of stick/2),3:29:40(pyq), 3:34:49(adv,20), 3:45:30(Parametric form of St line, kab aur kese lagate h), 3:49:18(pyq on Parametric form of St line), 3:57:39(pyq), 4:02:02(condition for concurrency of 3 lines), 4:03:13, 4:07:47(fam of St line ka eqn tbhi lagana ,jab ek line ka eqn pche ,jo intersection of L1 and L2 se pass krrha hoga), 4:18:02(fam of St line de dia ho, to wha se eqn ko split krke L1 and L2 split krnaa ana chahiye), 4:40:35(if coeff of eq of fam of line are in AP , then finding fix pt), 4:43:43(pyq), 4:51:43[img of pt (a,b) abt the line y=x is (b,a)], 4:52:23(reflecting line problems), 4:55:03(pyq), 4:59:27(adv,19), 5:11:46(problem on angle bisector of two lines), 5:14:36(after making constants+ve...jo bhi a1a2 + b1b2 ka sign milega ,whi sign hoga obtuse bisector ka), 5:16:04(working rule for bisctor containing origin: just make constant+ve & +ve sign wla hmesha containing origin), 5:19:09(if a1a2 +b1b2=0 ,then both are perpendicular angle bisector), 5:29:52[pair of St line passing thru origin have eqn: ax²+2hxy +by²=0 and h²-ab≥0(discriminant≥0)], 5:31:52(way to solve eqn of pair of St line passing thru origin, just put y=mx), 5:36:49(spcl cases for pair of St lines),5:44:35(homogenisation : kab aur kese lgaenge), 5:46:48(eg of homogenisation), 5:57:30(adv,21)
Introduction 9:41 Cartesian coordinate system 09:41 Distance formula 12:30 Section formula 14:25 Area of triangle 22:10 Area of quad 26:30 Slope of line 34:46 Intercept 38:30 Collinearity of three points 46:28 Equation of straight line in various forms 52:28 Angle between two straight lines 1:31:17 Break 1:57:54 5 IMP point on triangle 2:23:03 Special cases 2:43:22 Locus of a point 3:09:18 Length of perpendicular 2:23:41 Distance between 2 parallel line 3:28:02 Parametric equation of straight line 3:44:26 Position of point wrt straight line 3:55:35 Concurency of 3 lines 4:00:43 Family of straight lines 4:07:05 Break 4:22:10 Optics based problems 4:45:17 Equation of angle bisector 5:05:15 Homogenation 5:43:48 THE END 6:08:22
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1)34:55 slope of a line 2)38:33 intercept 3)46:52 collinearity of three points 4)52:38 equation of st line in various form i)53:44 point slope form ii)55:13 two point form iv)59:45 intercept form v) normal form 1:08:13
Introduction 9:41 Cartesian coordinate system 09:41 Distance formula 12:30 Section formula 14:25 Area of triangle 22:10 Area of quad 26:30 Slope of line 34:46 Intercept 38:30 Collinearity of three points 46:28 Equation of straight line in various forms 52:28 Angle between two straight lines 1:31:17 Break 1:57:54 5 IMP point on triangle 2:23:03 Special cases 2:43:22 Locus of a point 3:09:18 Length of perpendicular 3:23:41 Distance between 2 parallel line 3:28:02 Parametric equation of straight line 3:44:26 Position of point wrt straight line 3:55:35 Concurency of 3 lines 4:00:43 Family of straight lines 4:07:05 Break 4:22:10 Optics based problems 4:45:17 Equation of angle bisector 5:05:15 Homogenation 5:43:48 THE END 6:08:22
At 1:30:50 your answer and option is not matching because there we have to take angle between normal and x+y=0 as 60° from other side. Then angle between normal and X-axis will become 75°. And we will get option 4.
@@vasusingh1126 I guess, as you can see there are two possibilities of getting answers, so here we have to consider both the cases and we have to write the answer which is in option.
Introduction 9:41 -- -- Cartesian coordinate system 9:4118:5331:21 Distance formula 12:3047:0249:01 Section formula 14:251:17:25 1:20:13 Area of triangle 22:101:24:02 1:27:42 Area of quad 26:301:50:54 2:28:40 Slope of line 34:462:38:04 2:44:02 Intercept 38:302:46:21 2:49:23 Collinearity of three points 46:282:50:50 2:56:49 Equation of straight line in various forms 52:283:01:26 3:10:40 Angle between two straight lines 1:31:17 3:14:18 3:18:00 Locus of a point 3:09:18 3:29:40 3:34:49 Length of perpendicular 3:23:41 3:45:30 3:49:18 Distance between 2 parallel line 3:28:02 3:57:39 4:02:02 Parametric equation of straight line 3:44:26 4:03:13 4:07:47 Position of point wrt straight line 3:55:35 4:18:02 4:40:35 Concurency of 3 lines 4:00:43 4:43:43 4:51:43 Family of straight lines 4:07:05 4:55:03 4:59:27 Optics based problems Foot of perpendicular or image of point 4:45:17 Reflection problems 4:53:02 Equcation of angle bisector 5:05:14 angle of bisector of acute and obtuse - 5:10:58 5:11:46 5:14:36 Equation of angle bisector 5:05:15 ange bisector of containing origin and not containing origin 5:16:00 pyq 5:19:09 5:22:06 pair of straight line 5:34:18 angle of pair of straight line though origin 5:39:05bisector of the line represented by ' ax^2+2hxy+by^2 = 0 Homogenation 5:43:48 5:29:52 5:31:52 THE END 6:08:22 5:36:49 5:57:30:29:52
LECT STARTS AT 10:00 AREA OF TRIANGLE 22:05 AREA OF QUADR. 26:20 SLOPE OF LINE 34:51 iNTERCEPTS 34:30 EQUATIONS OF STRAIGHT LINES 52:32 Normal/ perpendicular form 01:08:05 Angle between 2 straight lines 01:31:18 5 Imp things about triangles 2:23:54 locus of point 3:09:36 Lenght of perpendicular 3:24:35 Parametric eqn of straight line 3:45:34 Position of point wrt to line 3:53:43 Concurrency of 3 lines 4:00:48 Family of st lines 4:07:11 Optics based questions 4:45:20 Pair of st lines 5:22:09 Homogenisation 5:44:00
Sir i was going offline ccg for last 3-4 months ; but belv me what i have understood in this 6hr session is more than in coaching apart from doubt solving✨✨
Time stamps 9:38 -Basics of Coordinate (Cartesian Coordinates System ; Distance formula; Section Formula; Area of traingle & Quadrilateral) 34:41 Slope of a line 46:26 -Collinearity of 3 points 52:25- Equation of Straight Lines in Various Forms 1:31:16 : Angle Between Two lines 2:23:19 : Break end & Five Centres of a triangle Starts 3:44:18 : Parametric Form of Equation of a Line 4:00:47 : Concurrency of 3 lines 4:07:05 :Family of Straight Lines
Introduction 9:41 Cartesian coordinate system 09:41 Distance formula 12:30 Section formula 14:25 Area of triangle 22:10 Area of quad 26:30 Slope of line 34:46 Intercept 38:30 Collinearity of three points 46:28 Equation of straight line in various forms 52:28 Angle between two straight lines 1:31:17 5 IMP point on triangle 2:23:03 Special cases 2:43:22 Length of perpendicular 3:23:41 Distance between 2 parallel line 3:28:02 Concurency of 3 lines 4:00:43
At 1:54:30 we can also use distance formula between P and perpendicular bisector and between Q and perpendicular distance and equate both the equations by doing that we can find the value of k
3:01:15 two imp question of jee mains 3:43:50 4:20:00 4:39:00 - *imp* 4:59:00 5:05:01 - *imp* 5:11:45 - *imp example for a1a2+b1b2* 3:24:00 *Length of perpendicular distance from a point* (imp)
1:04:43 , sir we can use the point slope form also , it is given that the intercepts are equal in magnitude and opposite in signs so the slope must be m = 1
1:43:49(Angle bw lines and mod),1:20:58(Language),2:56:13(nature of triangle {right angle or equilateral by side lenghts}),2:59:58(Prop of circumcircle),3:3:30(unique and language),3:42:18(adv Geometry),4:0:32 (KS INEQUALITY USE),4:44:48(PROP OF VARIABLE LINE),5:04:50( Heavy geometry)
*DOUBTS* 51:30 tan graph (that means how many times the line of -√2 cuts the lines of tan graphs until 2π on y axis becs the coordinate given is y axis)
Plz raise ur hand ✋ those r coming here to end this chapter to less time ,becz now ur feeling enzite,me too ,Best leacture 🔥🔥🔥🔥🔥❤️❤️🔥🔥 ever, Lot's of love and thanks ❤️
At 1:30:41,it should be specified in Q'S whether the angle is taken in anticlockwise direction or clockwise coz both are giving diff values of Phi.... basically the clockwise one is giving 15° and the a.c is giving 75°....
Bro I have just go through the provided link and they don't have such notes Can you please tell me what to do after going to that website Please bro it'll be a help for me from your side
STRAIGHT LINES ------------------------------------------------------------ Cartesian Coordinate System Q1 19:00 Q2 31:23 ------------------------------------------------------------ Slope of a Line ------------------------------------------------------------ Intercepts ------------------------------------------------------------ Collinearity of three points Q3 49:03 ------------------------------------------------------------ Equation of Straight Lines Q4 1:03:20 Q5 1:17:20 Q6 1:20:12 Q7 1:27:38 ------------------------------------------------------------ Angle between Two SL Q8 1:39:36 ------------------------------------------------------------ Five imp points wrt Triangle Q9 3:01:14 ------------------------------------------------------------ Locus of a point Q10 3:14:20 ------------------------------------------------------------ Length of Perpn Q11 3:34:47 ------------------------------------------------------------ Parametric Eqn of SL Q12 3:49:15 ------------------------------------------------------------ Position of Point wrt SL Q13 3:57:37 ------------------------------------------------------------ Concurrency of 3 lines Q14 4:03:07 ------------------------------------------------------------ Family of SL Q15 4:39:55 Q16 4:43:43 ------------------------------------------------------------ Optics Based Problems Q17 4:55:05
@@YugantSahu-x4t bhai impques likhey hain maine apne liye, saare ques ni likhey hain abhi jb lec poora ho jaayega toh baaki ke bhi edit krke daal doonga
34:30 Wale question me triangle ka third unknown vertex...yani point P ( x', y') Ka Co ordinate kya ham nikal sakte hai kisi tarike se ki kya hoga... Mere paas 2 equation hai.. Pehla jo triangle ke area se equate karke solve karke aaya Or dusra wo equation jo diya hua hai jispe point lie kar raha hai... Dono ko solve karne pe x or y cancel ho ja rahe hai.. Or bas lambda ka value nikal jaa raha hai.. Joki answer hai... Par aisa kyo ho raha hai.. Agar hamare paas 2 equation hai to Cartesian coordinate me dono ko solve karne pe unka intersection co ordinate milna chahiye).. Please koi explain kar do 🙏
@Fun 4 u bro nothing is sufficient for advanced This lecture is enough to build your concept But for advanved many things matter Self confidence , crtical thinking, problem solving skills This all will come if you atleast try to solve every problem you come up with Dheere dheere hi sahi manjil milengi 🎉
Area of quadrilateral shortcut is partially wrong. 28:00 it doesn't applies in every question Let A( -3,2 ), B(7, -6) C (-5, -4), D(5 , 4) Ans : 80 sq unit But using this shortcut directly I'm getting 16 sq unit. Sir you should have mentioned that Before Assuming ABCD we need to make sure sequence of points are according to quadrant. BTW love your lectures💙 #nvstyle
@@tinashe9967 that's what I'm saying. we can't simply assume the given points as ABCD if points are given randomly. We need to arrange the points quadrant wise in order to get area of quad. ABCD
2:56:16 That line will not only bisect BC but it will also be perpendicular to BC because the line is joining the Circumcentre of the triangle to the midpoint of the side BC... And as we know that Circumcentre is the point of intersection of perpendicular bisector of sides.... So we can draw the inference from that... I calculate slope using that and my answer was also correct.... ✋😁😁
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Where can i get pdf of this lecture ?
@@tanmayasahoo4326 hey did you get the pdf of this lecture , if yes then please share it
@@ushakiran497 naah . Not yet 😞
@@tanmayasahoo4326 hii if you have pdf of straight line then pls send me
@@mamtasingh1843don't have it 😅
DO LIKE THE COMMENT IF I HELPED YOU!
LECT STARTS AT 10:00
AREA OF TRIANGLE 22:05
AREA OF QUADR. 26:20
SLOPE OF LINE 34:51
iNTERCEPTS 34:30
EQUATIONS OF STRAIGHT LINES 52:32
Normal/ perpendicular form 01:08:05
Angle between 2 straight lines 01:31:18
5 Imp things about triangles 2:23:54
locus of point 3:09:36
Lenght of perpendicular 3:24:35
Parametric eqn of straight line 3:45:34
Position of point wrt to line 3:53:43
Concurrency of 3 lines 4:00:48
Family of st lines 4:07:11
Optics based questions 4:45:20
Pair of st lines 5:22:09
Homogenisation 5:44:00
thankq
Thanks bro
Sir ka time stamp to alag hi hai
@@toxictalks2140 hn determinant wala daal diya galti se unhone
1:29:00 ka soln galat hai wo d option 3-1 hi rhega sir ne glt angle liya hai
@@toxictalks2140 chup kr bsdk
16:08 (pyq)
18:53(pyq)
31:21(pyq)
47:02(collinearity check by determinant method)
49:01
1:17:25(imp note for normal form of line is that:P ka value hmesha +ve hi hoga, since P is distance. So we have to adjust theta according to it)
1:20:13(pyq)
1:24:02(pyq,bisceting ,we can use mid pt formula)
1:27:42(pyq)
1:50:54(PYQ)
2:28:40(key step to find circumcentre)
2:38:04(finding orthocentre)
2:44:02(spcl case:right triangle)
2:46:21(case of equilateral triangle)
2:49:23(ortho,centroid,circumcentre are collinear and ratio wala cheez hmesha right angle triangle se yaad rkhna)
2:50:50(pyq)
2:56:449(pyq)
3:01:26[pyq, isme as circumcentre is also the origin, thus assume points as (Rcosa,Rsina) (Rcosb,Rsinb)and (Rcosy,Rsiny) kuki sbhi centre se R hi ke distance pe honge]
3:10:40(Working rule for finding Locus)
3:14:18
3:18:00(Imp case of A stick lying against coord axes: The middle pt of stick moves in a circle,with radius =Length of stick/2)
3:29:40(pyq)
3:34:49(adv,20)
3:45:30(Parametric form of St line, kab aur kese lagate h)
3:49:18(pyq on Parametric form of St line)
3:57:39(pyq)
4:02:02(condition for concurrency of 3 lines)
4:03:13
4:07:47(fam of St line ka eqn tbhi lagana ,jab ek line ka eqn pche ,jo intersection of L1 and L2 se pass krrha hoga)
4:18:02(fam of St line de dia ho, to wha se eqn ko split krke L1 and L2 split krnaa ana chahiye)
4:40:35(if coeff of eq of fam of line are in AP , then finding fix pt)
4:43:43(pyq)
4:51:43[img of pt (a,b) abt the line y=x is (b,a)]
4:52:23(reflecting line problems)
4:55:03(pyq)
4:59:27(adv,19)
5:11:46(problem on angle bisector of two lines)
5:14:36(after making constants+ve...jo bhi a1a2 + b1b2 ka sign milega ,whi sign hoga obtuse bisector ka)
5:16:04(working rule for bisctor containing origin: just make constant+ve & +ve sign wla hmesha containing origin)
5:19:09(if a1a2 +b1b2=0 ,then both are perpendicular angle bisector)
5:29:52[pair of St line passing thru origin have eqn: ax²+2hxy +by²=0 and h²-ab≥0(discriminant≥0)]
5:31:52(way to solve eqn of pair of St line passing thru origin, just put y=mx)
5:36:49(spcl cases for pair of St lines),5:44:35(homogenisation : kab aur kese lgaenge)
5:46:48(eg of homogenisation)
5:57:30(adv,21)
Thank you
Hey if you have pdf of this lecture then please share it
Hey if u have the pdf of class schare me
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18:53(pyq), 31:21(pyq), 47:02(collinearity check by determinant method), 49:01, 1:17:25(imp note for normal form of line is that: P ka value hmesha +ve hi hoga, since P is distance. So we have to adjust theta according to it), 1:20:13(pyq), 1:24:02(pyq,bisceting ,we can use mid pt formula)1:27:42(pyq),1:50:54(PYQ),2:28:40(key step to find circumcentre),2:38:04(finding orthocentre),2:44:02(spcl case:right triangle),2:46:21(case of equilateral triangle),2:49:23(ortho,centroid,circumcentre are collinear and ratio wala cheez hmesha right angle triangle se yaad rkhna),2:50:50(pyq),2:56:449(pyq),3:01:26[pyq, isme as circumcentre is also the origin, thus assume points as (Rcosa,Rsina) (Rcosb,Rsinb)and (Rcosy,Rsiny) kuki sbhi centre se R hi ke distance pe honge], 3:10:40(Working rule for finding Locus), 3:14:18, 3:18:00(Imp case of A stick lying against coord axes: The middle pt of stick moves in a circle,with radius =Length of stick/2),3:29:40(pyq), 3:34:49(adv,20), 3:45:30(Parametric form of St line, kab aur kese lagate h), 3:49:18(pyq on Parametric form of St line), 3:57:39(pyq), 4:02:02(condition for concurrency of 3 lines), 4:03:13, 4:07:47(fam of St line ka eqn tbhi lagana ,jab ek line ka eqn pche ,jo intersection of L1 and L2 se pass krrha hoga), 4:18:02(fam of St line de dia ho, to wha se eqn ko split krke L1 and L2 split krnaa ana chahiye), 4:40:35(if coeff of eq of fam of line are in AP , then finding fix pt), 4:43:43(pyq), 4:51:43[img of pt (a,b) abt the line y=x is (b,a)], 4:52:23(reflecting line problems), 4:55:03(pyq), 4:59:27(adv,19), 5:11:46(problem on angle bisector of two lines), 5:14:36(after making constants+ve...jo bhi a1a2 + b1b2 ka sign milega ,whi sign hoga obtuse bisector ka), 5:16:04(working rule for bisctor containing origin: just make constant+ve & +ve sign wla hmesha containing origin), 5:19:09(if a1a2 +b1b2=0 ,then both are perpendicular angle bisector), 5:29:52[pair of St line passing thru origin have eqn: ax²+2hxy +by²=0 and h²-ab≥0(discriminant≥0)], 5:31:52(way to solve eqn of pair of St line passing thru origin, just put y=mx), 5:36:49(spcl cases for pair of St lines),5:44:35(homogenisation : kab aur kese lgaenge), 5:46:48(eg of homogenisation), 5:57:30(adv,21)
bruh
Bhai itni mehenat kon krta h
bro u hve its notes pdf please share then
@@Ishasarwaan12 iitian
Hua iit me ?
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Introduction 9:41
Cartesian coordinate system 09:41
Distance formula 12:30
Section formula 14:25
Area of triangle 22:10
Area of quad 26:30
Slope of line 34:46
Intercept 38:30
Collinearity of three points 46:28
Equation of straight line in various forms 52:28
Angle between two straight lines 1:31:17
Break 1:57:54
5 IMP point on triangle 2:23:03
Special cases 2:43:22
Locus of a point 3:09:18
Length of perpendicular 2:23:41
Distance between 2 parallel line 3:28:02
Parametric equation of straight line 3:44:26
Position of point wrt straight line 3:55:35
Concurency of 3 lines 4:00:43
Family of straight lines 4:07:05
Break 4:22:10
Optics based problems 4:45:17
Equation of angle bisector 5:05:15
Homogenation 5:43:48
THE END 6:08:22
Notes kha hai bro, description baale open nahi ho rahe .?
JEE Complete Notes and Lectures - Atoms
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timestamps wildin'
@@wannabefighterpilotyh😅😂
Notes nahi mil rahe es lec ke
Notes nahi mil pa rha h
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1)34:55 slope of a line
2)38:33 intercept
3)46:52 collinearity of three points
4)52:38 equation of st line in various form
i)53:44 point slope form
ii)55:13 two point form
iv)59:45 intercept form
v) normal form 1:08:13
bhai pura likh dete.......
Thanks btw *heart emoji*
TRIANGLE WALA MISS KAR DIYE
Whose 1 shot should i watch.....sameer sir or NV sir ....please someone tell
@@Pw_insider07 NV sir's
Sir aapne Diwali ke din bhi class liya yeh batata hai aapka aur mam ka dedication god gifted hai
❤️❤️❤️❤️ yes 👍👍👍👍
Really
IITIANs spirit ❤️❤️😀😀
@@SHIVAM_VARSHNEY01 Tu harami hai saale
sir's dedication level is infinity
It doesn't exist 😂😂
@@stewiegriffin2486 🤣🤣🤣
seeing for jee 2025, likhe if you are also
Mee tooo. 😅
Bro this lecture is enough bcoz I'm first time studying that chapter
@@Asr_Harsh_YtAre bhai ek didi ne ye dekh ke kuch 850 rank layi form vora classes
@@PrashikMeshram-vc nahi me yeah padha nahi hai coaching me na isliye puch Raha tha
@@Asr_Harsh_Yt ohk
Ache one shots hai vaise ye
Sir Kitni baar dil jitoge, ek hi dil ha humara ...❤️❤️
Taking class even on Festival .Hats off too Your dedication sir..💯☺️
Kahe तू sir k mal hayy ka
@@thedon1844 naa eee sir ka DHRAM PATNI hai 😜
@Aditya Gupta yes bro🤜
@@thedon1844 atthi hoga b to , tumar kia jaa rha to
Introduction 9:41
Cartesian coordinate system 09:41
Distance formula 12:30
Section formula 14:25
Area of triangle 22:10
Area of quad 26:30
Slope of line 34:46
Intercept 38:30
Collinearity of three points 46:28
Equation of straight line in various forms 52:28
Angle between two straight lines 1:31:17
Break 1:57:54
5 IMP point on triangle 2:23:03
Special cases 2:43:22
Locus of a point 3:09:18
Length of perpendicular 3:23:41
Distance between 2 parallel line 3:28:02
Parametric equation of straight line 3:44:26
Position of point wrt straight line 3:55:35
Concurency of 3 lines 4:00:43
Family of straight lines 4:07:05
Break 4:22:10
Optics based problems 4:45:17
Equation of angle bisector 5:05:15
Homogenation 5:43:48
THE END 6:08:22
At 1:30:50 your answer and option is not matching because there we have to take angle between normal and x+y=0 as 60° from other side. Then angle between normal and X-axis will become 75°. And we will get option 4.
Yeah you are correct. But i got one question, how do we know from where we have to take the angle?
@@vasusingh1126 I guess, as you can see there are two possibilities of getting answers, so here we have to consider both the cases and we have to write the answer which is in option.
He is explaining so smoothly, Thank you sir . Love from Nepal 🇳🇵
Concise and appropriate.
Except this just do "excenter, transformation of cartesian and polar coordinates, shifting of origin and rotation of axis "
Did he not do this? And has he included the slides of the lectures which he taught on the Unacademy JEE channel?
Yes these are the some topics from the basics of coordinate geometry
Are these in 2024-2025 syllabus?
@@Beast63000 yes
Break 1:58:20
Start 2:23:20
Break 2 - 4:23:00
Start 4:39:19
Yeh badiya tha guru
Best comment so far
Diwali ke din bhi 6 hr+ class...
I have No words to describe ur DEDICATION LEVEL.
Hats off 🔥
pr aaj to holi h🤣🤣👍
@@shivamsingh-1101 4 month ago ka hai
@preparation with me ptaa h bhi aese hi khaa tha🙌😭😭😞😞
@@shivamsingh-1101 🤣🤣🤣
L0
Introduction 9:41 -- --
Cartesian coordinate system 9:41 18:53 31:21
Distance formula 12:30 47:02 49:01
Section formula 14:25 1:17:25 1:20:13
Area of triangle 22:10 1:24:02 1:27:42
Area of quad 26:30 1:50:54 2:28:40
Slope of line 34:46 2:38:04 2:44:02
Intercept 38:30 2:46:21 2:49:23
Collinearity of three points 46:28 2:50:50 2:56:49
Equation of straight line in various forms 52:28 3:01:26 3:10:40
Angle between two straight lines 1:31:17 3:14:18 3:18:00
Locus of a point 3:09:18 3:29:40 3:34:49
Length of perpendicular 3:23:41 3:45:30 3:49:18
Distance between 2 parallel line 3:28:02 3:57:39 4:02:02
Parametric equation of straight line 3:44:26 4:03:13 4:07:47
Position of point wrt straight line 3:55:35 4:18:02 4:40:35
Concurency of 3 lines 4:00:43 4:43:43 4:51:43
Family of straight lines 4:07:05 4:55:03 4:59:27
Optics based problems
Foot of perpendicular or image of point 4:45:17
Reflection problems 4:53:02
Equcation of angle bisector 5:05:14
angle of bisector of acute and obtuse - 5:10:58
5:11:46 5:14:36
Equation of angle bisector 5:05:15
ange bisector of containing origin and not containing origin 5:16:00
pyq 5:19:09
5:22:06 pair of straight line
5:34:18 angle of pair of straight line
though origin
5:39:05bisector of the line represented by ' ax^2+2hxy+by^2 = 0
Homogenation 5:43:48 5:29:52 5:31:52
THE END 6:08:22 5:36:49 5:57:30:29:52
At 3:13:44 distance formula toh x2-x1+y2-y1 hota h pr sir se x1-x2+y1-y2 kyu kiya h plz reply
Where can i get pdf bro?
@@fantasyandmotivationalshor6408 bro x2-x1 kro ya x1- x2 kro ans same aayega kyukiii uska square krna h like -1 ka sq v 1 hoga aur 1 ka sq v 1 hota..
The only man who can can help you with maths at the last moment
Can't thank youu enough sir!! THANKYOUU FOR EVERYTHING YOU DO FOR US. You deserve the world sir! Thankyouu😭❤️
Deserve the whole multiverse...not just world...
Hua iit me ?
Whose 1 shot should i watch.....sameer sir or NV sir ....please someone tell
@@Pw_insider07 bhai dono ka ek ek baae dekh jinka samjh aaye
Aur jinse padhke question solve hone lage unhe follow karo❤
satyam
LECT STARTS AT 10:00
AREA OF TRIANGLE 22:05
AREA OF QUADR. 26:20
SLOPE OF LINE 34:51
iNTERCEPTS 34:30
EQUATIONS OF STRAIGHT LINES 52:32
Normal/ perpendicular form 01:08:05
Angle between 2 straight lines 01:31:18
5 Imp things about triangles 2:23:54
locus of point 3:09:36
Lenght of perpendicular 3:24:35
Parametric eqn of straight line 3:45:34
Position of point wrt to line 3:53:43
Concurrency of 3 lines 4:00:48
Family of st lines 4:07:11
Optics based questions 4:45:20
Pair of st lines 5:22:09
Homogenisation 5:44:00
It was amazing session sir ❤️❤️❤️
I STUDY IN FIITJEE, AND LITERALLY I HAVE UNDERSTOOD THIS TOPIC ONLY FROM YOU DEAR SIR, YOU R D BEST❤️
me in south delhi.. u?
giving aits?
@@webfreelancer5680 Only Attempted Jee Mains Aits 2023 🤧....Me in East Delhi
Me from allen kota ,
Still learning by his lectures
Sir is literally 2nd God of mathematics after VK Bansal sir
@@sumitsawaria7529 seriously lol
Bhai literally bohot teacher h india me
Aise direct mt bolo 2nd 😂
@@techusupport6965 remember the legend mohit tyagi sir too😉
Any jee aspirants 2024 here??
Haan bhai
Yohh
Yo bro
Yup
ye
Sir i was going offline ccg for last 3-4 months ; but belv me what i have understood in this 6hr session is more than in coaching apart from doubt solving✨✨
Time stamps
9:38 -Basics of Coordinate (Cartesian Coordinates System ; Distance formula; Section Formula; Area of traingle & Quadrilateral)
34:41 Slope of a line
46:26 -Collinearity of 3 points
52:25- Equation of Straight
Lines in Various Forms
1:31:16 : Angle Between Two lines
2:23:19 : Break end & Five Centres of a triangle Starts
3:44:18 : Parametric Form of Equation of a Line
4:00:47 : Concurrency of 3 lines
4:07:05 :Family of Straight Lines
Hey if you have pdf of this lecture then please share it
Guruji ek hi toh dil hai,kitni baar jeetoge❤️❤️
Agli diwali iit wali
🥺🥺🥺
@@akshatgupta8787 he he
Same profile pic
Good
🌬️ m also waiting for this diwali.. 🌿
Can anyone suggest me which subtopics should I do in straight lines to understand conic sections perfectly for jee ...PLEASE ???😖
Introduction 9:41
Cartesian coordinate system 09:41
Distance formula 12:30
Section formula 14:25
Area of triangle 22:10
Area of quad 26:30
Slope of line 34:46
Intercept 38:30
Collinearity of three points 46:28
Equation of straight line in various forms 52:28
Angle between two straight lines 1:31:17
5 IMP point on triangle 2:23:03
Special cases 2:43:22
Length of perpendicular 3:23:41
Distance between 2 parallel line 3:28:02
Concurency of 3 lines 4:00:43
At 1:54:30 we can also use distance formula between P and perpendicular bisector and between Q and perpendicular distance and equate both the equations by doing that we can find the value of k
Sir your dedication is next level 🙏🙏 We always support you and ma'am . Love you sir ❤️❤️
3:01:15
two imp question of jee mains
3:43:50
4:20:00
4:39:00 - *imp*
4:59:00
5:05:01 - *imp*
5:11:45 - *imp example for a1a2+b1b2*
3:24:00 *Length of perpendicular distance from a point* (imp)
1:04:43 , sir we can use the point slope form also , it is given that the intercepts are equal in magnitude and opposite in signs so the slope must be m = 1
bro I also used that
3:08:00 ma H is the origin (H is circumcentre).
Therefore, H, G, O is from down to Up .(sir marked from up to down)
At 5:26:50 nice trick to learn pair of Straight line
"" All Honest Girl Having BF Go For College"".
1:43:49(Angle bw lines and mod),1:20:58(Language),2:56:13(nature of triangle {right angle or equilateral by side lenghts}),2:59:58(Prop of circumcircle),3:3:30(unique and language),3:42:18(adv Geometry),4:0:32 (KS INEQUALITY USE),4:44:48(PROP OF VARIABLE LINE),5:04:50( Heavy geometry)
3:42:45(Paramatric form)
Thanks for giving us this amazing series❤️❤️❤️❤️❤️❤️❤️
*DOUBTS* 51:30 tan graph (that means how many times the line of -√2 cuts the lines of tan graphs until 2π on y axis becs the coordinate given is y axis)
Hii broo we are watching at the same time lol
Yes in the range of 0 to 2𝝅
It cuts the tan graph at points hence the no. of solutions is 2
@@Soham.69 lmaoo
You are not alone
H.W Ans.. of last adv question :-
77.1
Yes i have also got the same answer 👍
🤩🤩😊
🎀🤟
77.142 aaya mera to
540/7
Slope of line -34:45
Intercept -38:33
Subsribers 69k and watched by 62K
this shows how dedicated to jee this channel /students / teacher is🙏🙏🙏🙏🙏
okk
Watched by 1.1 million by now!
2:49:34 not for equilateral triangles.
Not 2:1
Thank you Sir...:)
love u sir .......no words for u itna pyar se aap padhaye ho kasam se sir love ho aap hamare
4:10:00 Family of straight line
4:22:00 brak 2
1:30:44. Jee mains 2019 question,have you checked the options correctly because x is getting multiplied by √3+1 but in the option it's √3-1
Plz raise ur hand ✋ those r coming here to end this chapter to less time ,becz now ur feeling enzite,me too ,Best leacture 🔥🔥🔥🔥🔥❤️❤️🔥🔥 ever,
Lot's of love and thanks ❤️
got 12 marks in jee advanced 2023 with this one shot thanks for nv sir ,
ab kha ho bhaii
@@utkarshtomar8268 ab iit dholakpur me hai vo
@@Anonymous-wi1ke
Ye unacademy walon ne timestamps bidi pi kar lagai h kya
For personal use only
Determinant fatlu
2.43 is not imp
3:24:00
Koi hai jo sidha one shot dekh rha hai bina iss chapter ke lectures dekhe ??
Hm
Hmm
Done ✅
Just woahh 😍
Tq sir ❤😊
At 1:30:41,it should be specified in Q'S whether the angle is taken in anticlockwise direction or clockwise coz both are giving diff values of Phi.... basically the clockwise one is giving 15° and the a.c is giving 75°....
and we hd to check for both as in option 15deg 's ans was not there ans sir marked we would get by 75deg but sir changed options
yes 75 deg option d is actually correct with no changes
btw it isnt specified in the q so not our fault
at 3:48:53, what if its not going up or down(if its going parallel to the x-axis) ...then what do we have to take positive or negative for 'r'?
U can still find sin theta and cos theta if it’s parallel to x axis. Slope will be zero. Therefore perp side =0 and and base =1
@@manavbhutani5115 thank you
Ques after each concept is best thing about this lec
Very Nicely Presented! 🙂
OHH SIR ...... BIG FAN
Is everything covered here ?
@@mysteriousopxdchannel2882 Yes. From basics to advance level, NV sir ne sab padhaya hai 😄
@@srinidhisoundarrajan5884 Tnx Sri
Best lecture for straight line ....❤🎉
Where can we find pdf of this session can you please tell me brother is
@@KrishnaSharma-wg6rc check description....click on Complete notes and lecture link...
Bro I have just go through the provided link and they don't have such notes
Can you please tell me what to do after going to that website
Please bro it'll be a help for me from your side
@@KrishnaSharma-wg6rc website is not working...
It is the best lecture on straight lines. Thank you Sir. #NVstyle❤️💗
Iska pdf notes kaise kre download
2:35:16 x = -6/7 & y = 2/7.
Dil jeet liya sir apne
6:08:00 ANS D=77.14
At 5:01:10 shouldn't points A and it's reflection B at same side of the line??(just like it was in last question).
haan bhyii both are on same side (dono points ek hi side me hone chahiye - dono upar ya fir dono niche)
43:54
50:00
1:18:00
1:20:00
1:26:00
1:29:00
23:59 q
27:15 quad
27:19 q
The answer of the second part of the last question from jee adv 2021 is 77.14
Nice bro ❤️
Mera bhi ans same aa raha hai but sahi h ya galat pta nhi
@@SHAKIBRAJAA haa sahi hai..maine pyq ke answer check kiya tha
a.homogenisation
b.Reflection Problems
4:19:22 Ans: (2,-1).
5 imp things about ∆s
Locus of point
JEE ADV. Q. 3:35:14
Then start from eq. of Angle bisector
5:26:05 nemonic was insane 😂😂😂
😂😂
Mnemonic*
STRAIGHT LINES
------------------------------------------------------------
Cartesian Coordinate System
Q1 19:00
Q2 31:23
------------------------------------------------------------
Slope of a Line
------------------------------------------------------------
Intercepts
------------------------------------------------------------
Collinearity of three points
Q3 49:03
------------------------------------------------------------
Equation of Straight Lines
Q4 1:03:20
Q5 1:17:20
Q6 1:20:12
Q7 1:27:38
------------------------------------------------------------
Angle between Two SL
Q8 1:39:36
------------------------------------------------------------
Five imp points wrt Triangle
Q9 3:01:14
------------------------------------------------------------
Locus of a point
Q10 3:14:20
------------------------------------------------------------
Length of Perpn
Q11 3:34:47
------------------------------------------------------------
Parametric Eqn of SL
Q12 3:49:15
------------------------------------------------------------
Position of Point wrt SL
Q13 3:57:37
------------------------------------------------------------
Concurrency of 3 lines
Q14 4:03:07
------------------------------------------------------------
Family of SL
Q15 4:39:55
Q16 4:43:43
------------------------------------------------------------
Optics Based Problems
Q17 4:55:05
Iske Baad Ka
@@YugantSahu-x4t bhai impques likhey hain maine apne liye, saare ques ni likhey hain
abhi jb lec poora ho jaayega toh baaki ke bhi edit krke daal doonga
@@sureyeah4146 Ok
Happy Diwali sir ♥️. You are an inspiration for millions of people on earth 🌎
Revision ✅✅✅✅
20:00
46:00
1:50:00
1:35:00
2:25:00
3:45:00
4:00:00
4:12:00
🎉4:18:30
4:46:00
4:51:00
বাহ: সত্যি আপনাকে দেখে মুগ্ধ হয়ে যাই ❤
আমিও
Agli Diwali
IITwali
আমিও আপনি কোথায়ে থাকেন
@@oxygen632 kolkata
34:30
Wale question me triangle ka third unknown vertex...yani point P ( x', y') Ka Co ordinate kya ham nikal sakte hai kisi tarike se ki kya hoga...
Mere paas 2 equation hai.. Pehla jo triangle ke area se equate karke solve karke aaya Or dusra wo equation jo diya hua hai jispe point lie kar raha hai... Dono ko solve karne pe x or y cancel ho ja rahe hai.. Or bas lambda ka value nikal jaa raha hai.. Joki answer hai...
Par aisa kyo ho raha hai.. Agar hamare paas 2 equation hai to Cartesian coordinate me dono ko solve karne pe unka intersection co ordinate milna chahiye)..
Please koi explain kar do 🙏
सर आपके one shot lectures For revision के लिए काफी फायदेमंद है😀😃
Revision ke liye hi nahi bhai
Jo first time padh rhaa hai uskey liye bhi more than enough hai
@@abhipanwar303 abhi tum college mai ho ya school mai
@@erlakshyajain4692 job karta hu bhai
@@abhipanwar303 😂
@@abhipanwar303 ???
very good and crystal clear explanation
God of one shot hatss off sir this is my first time watching ur one shot and it's totally up to the point ❤️
Sir what a motivation, in the starting of the lecture
Really live you sir 🙏🏻 ❤
Agli diwali iit wali 🪔 🪔
Hua kya iit mein
5:35:29 theta = tan^-1(8/19).
The most underrated teacher,, He almost made me zero to adv level in st lines and many more chapters too, and that #nvstyle had a separate fanbase🤭🤭
@Fun 4 u bro nothing is sufficient for advanced
This lecture is enough to build your concept
But for advanved many things matter
Self confidence , crtical thinking, problem solving skills
This all will come if you atleast try to solve every problem you come up with
Dheere dheere hi sahi manjil milengi
🎉
Which College are You Studying Currently???❤
3:34:00 always remember to make coefficient of x y same before applying formula
3:35:38 Q ADV Circles
1:04:49 here we can easily apply point slope form and slope is as shown is 1
Sir please permutations and combinations kara dejiye
Sir at 1:04:50 sir wah direct m=+1 put krke slope point form lagake equation easily find out kr skte h 👍👍
haa
Area of quadrilateral shortcut is partially wrong. 28:00 it doesn't applies in every question
Let A( -3,2 ), B(7, -6)
C (-5, -4), D(5 , 4)
Ans : 80 sq unit
But using this shortcut directly I'm getting 16 sq unit.
Sir you should have mentioned that Before Assuming ABCD we need to make sure sequence of points are according to quadrant.
BTW love your lectures💙
#nvstyle
You took wrong points, the quadrilateral isn't ABCD in your case
@@tinashe9967 that's what I'm saying. we can't simply assume the given points as ABCD if points are given randomly. We need to arrange the points quadrant wise in order to get area of quad. ABCD
2:56:16
That line will not only bisect BC but it will also be perpendicular to BC because the line is joining the Circumcentre of the triangle to the midpoint of the side BC... And as we know that Circumcentre is the point of intersection of perpendicular bisector of sides.... So we can draw the inference from that...
I calculate slope using that and my answer was also correct.... ✋😁😁
Revision Done ✅❤
JEE2025
is it an issue with me or the timelines of this lecture is really of matrices and detrminants?
yeah all bounce back got this problem due to some person who manages channel
maja aa gyya sir class kar ke mast class kiye phir puja ..... :)
NV sir aap bahut badhiya padhate ho... greatest of all time.....💯💯💯
Sir please upload the lecture notes.
Really thank you so much sir fr this series of one-shot, I am doing all chap from here sir
Thanks sir for ur diwali gift🥰🥰🥰🥰 love u sir❤️