@equifish That is a very good question! The answer is no, and the reason is that f(x) = (x^2 -9)/(x-3) is a different function than x+3. Its only different at 1 single point, when x=3, but all the same its a different function. On the other hand that is exactly the technique we will use to find the limit of this function. There is a theorem that says if two functions differ at just a single point then they have the same limits. See: 1.5 Solving Limits (Factoring) in my calculus playlist
Thanks buddy you were the one who perfectly put up to me what limits actually are.Hey I've got a question. What device are you using to write on the screen.
![1.3 Limits that Fail to Exist [01] - |x|/x](http://i.ytimg.com/vi/fU7JNYBxiaY/mqdefault.jpg)
![1.3 Limits that Fail to Exist [01] - |x|/x](/img/tr.png)
@equifish That is a very good question! The answer is no, and the reason is that f(x) = (x^2 -9)/(x-3) is a different function than x+3. Its only different at 1 single point, when x=3, but all the same its a different function.
On the other hand that is exactly the technique we will use to find the limit of this function. There is a theorem that says if two functions differ at just a single point then they have the same limits.
See: 1.5 Solving Limits (Factoring) in my calculus playlist
love your videos so far…..thank you
Thanks buddy you were the one who perfectly put up to me what limits actually are.Hey I've got a question. What device are you using to write on the screen.
Thanks for make me realize why i have to manipulate that algebra when i learn limit
I do love your videos, buddy ❤️ thank you so much
so 6 is the limit?
how is there so few thumb ups :( this is great:D
nice one!
❤️❤️
too good,
u rock!
thanks!:D
Ide pay to watch this video
🤔🤔👎👎👎👎🙄