Implicit Differentiation Second Derivative Trig Functions & Examples- Calculus
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- Опубликовано: 9 сен 2024
- This calculus video tutorial explains how to calculate the first and second derivative using implicit differentiation. This video contains plenty of examples that include trig functions.
Derivatives - Fast Review: • Calculus 1 - Derivatives
Derivatives - The Product Rule - f*g:
• Product Rule For Deriv...
Derivatives - The Quotient Rule:
• Quotient Rule For Deri...
Derivatives - The Chain Rule:
• Chain Rule For Finding...
Derivatives - Composite Functions:
• Derivatives of Composi...
__________________________________
Implicit Differentiation:
• Implicit Differentiation
Derivatives of Inverse Trig Functions:
• Derivatives of Inverse...
Derivatives of Exponential Functions:
• Derivatives of Exponen...
Derivatives of Logarithmic Functions:
• Derivative of Logarith...
Logarithmic Differentiation:
• Introduction to Logari...
___________________________________
Derivatives - Using Logarithms:
• Finding Derivatives Us...
Derivatives of Inverse Functions:
• Derivatives of Inverse...
Derivatives - Differentiation Rules:
• Basic Differentiation ...
Derivatives - Function Notations:
• dy/dx, d/dx, and dy/dt...
Derivatives - The Reciprocal Rule:
• The Reciprocal Rule an...
_________________________________
Final Exams and Video Playlists:
www.video-tuto...
Full-Length Videos and Worksheets:
/ collections
Derivatives - Formula Sheet:
bit.ly/4dThzf1
Derivatives - Formula Sheet: bit.ly/4dThzf1
Final Exams and Video Playlists: www.video-tutor.net/
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Thank you, you're such a lifesaver! I'm confused at the part where you have to plug in the first derivative for y' and simplify it. My teacher said that if you don't know this part then you are literally "dumb" and she never showed us how to simplify it in class. I feel like I understand it much better now after watching your video.
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THANK YOU SO MUCH! i have been struggling to understand how to diiferatiate the trig functions. At 20:00 min you explained it very well!
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You do a great job. However, I'm not sure how often you notice you say to use the product rule, when in fact you're using the chain rule. I've seen it on this video and one other so far. Listen to the example at about 21:30 to see if I'm missing something. Thank you again.
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@ 5:17 shouldn't you have cancelled the y^2 in both terms since they are added? so you would get (2xy+2x^2)(-x^2/y) or am I thinking wrong?
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Note that the term, dx/dx, "cancels" and seemingly disappears(@1:20) from our computation. However absent from the page, its prior appearance is merely hidden, or implied...thus implicit differentiation. We must make apparent, or explicit, dy/dx when working with a second variable, such as y. Thus, explicit differentiation. Please correct me if I am in error. Thanks.
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"If you wanna find the devivaviv..." sorry man, you are making this topic easier and at the same time funnier cause of how you pronounce derivative
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will you go over things like partial integration or even differential equations
Maybe.
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Sir please can you workout this math for me. DY/DX of 1/2πr(96-r^)
Thank you very much for this simple explanation, but I have a question if I can shorten between 2x / y ^ 2 * y ^ 2 from where y came to multiply the numerator and denominator * y
هو جابها من عنده علمود يخلي الY في المقام تروح..
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why do we need to write the dy/dx again in 8:28?
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are you ever required to substitute y into the soln hence at 19:00
y’ =9/sqrt(x) -1 instead of sqrt(y/x)
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I'm quite mad that he was not able to continue working on the problem at 12:17
excuse me sir... just asking about equation no.2 in which x^3 - xy + y^2 = 4 is derived to 3x^2 - y - x(dy/dx) + 2y(dy/dx) = 0 and the dy/dx are isolated, why is that it became 2y(dy/dx) - x(dy/dx) = y - 3x^2? why is that you switched both terms on both sides instead of -x(dy/dx) + 2y(dy/dx) = -3x^2 + y?
he made it only to have the positive side/terms first then the negative side/terms the second. For simplicity. But in all cases it will not differ. The result will be the same
Thank you👊
at 4:58 why did he replace dy/dx with -x^2/y^2? I'm so confused there
The term implicit differentiation somehow doesn't click with me. Implicit for me is dx/dx which usually is omitted. But dy/dx looks very explicit :)
2y dy/dx for y^2 with respect to x
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But the power does not attached to y
How do you know which side to leave dy/dx?
first 90 seconds is all i needed....
I understood the whole thing except the last problem 🥲
Use the chain rule
d[ sin(x+y) ] /dx
Let w = sin(u) where u = x+y
Then dw/dx = dw/du du/dx = cos(u) * [ 1 + dy/dx ] = cos(x+y) * (1+dy/dx)
Is it permissible to use negative exponents on the fraction, then use the product rule instead of the quotient rule?
yeah bro totally, i prefer to do that in most cases
12:35 Yeah I see what you mean lol after simplifying it.
Why do we find the second derivative?
I was once in this class
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21:00
it was a good tutorial.. unfortunately.... during the triginometric part... he wasn't able to take the second derivative
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28:54
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