The average particle speed in a Maxwell-Boltzmann distribution

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  • Опубликовано: 4 янв 2025

Комментарии • 13

  • @DeadPeople1000
    @DeadPeople1000 2 года назад +6

    Bruh, I feel so called out: "I left some room in the recording right there in case anybody had to groan out loud" 💀 Thanks for the help with this one!

    • @jacmac225
      @jacmac225 8 месяцев назад

      so real. soooo so so real.

  • @ArunKumar-fi1wv
    @ArunKumar-fi1wv 4 года назад +3

    you are a good man .. my exams were coming and i was terribly scared, you saved my life .. hope you dont get corona

  • @chronikuru
    @chronikuru 3 года назад +1

    You just saved my life on my calc homework dude, I totally missed that substitution before the integration by parts and I was in hell. Thanks for putting this up!

  • @MrDeyvid34
    @MrDeyvid34 2 года назад

    Holy, thanks brother, just what i needed

  • @justincain4634
    @justincain4634 Год назад

    It would be helpful if there was a video on how to integrate v^2 and the maxwell-boltzmann distribution since root mean square velocity is equal to the square root[average of v^2]. Gaussian techniques need to be used, apparently, and there are no examples on the Internet.

  • @arturzych138
    @arturzych138 4 года назад

    beautifully explained

  • @johnr1875
    @johnr1875 6 лет назад +1

    i get why multiplying by v makes it a big difference. But why are we multiplying by v? Ive never taken stats.

    • @luisgaposadas
      @luisgaposadas 4 года назад +2

      Its not stats, it is a theorem of calculus, the average value of a function f(x) over a range (a,b) is equal to the integral of the function multiplied by x { f(x) . x } from a to b.

    • @longvu-kb4ue
      @longvu-kb4ue Год назад

      its because there is something in stats called the expected value of a function or mean of a function and when the function is a probability density function like it is here the expected value will be the integral from -ve infinity to +ve infinity of xf(x) dx
      Here's the source it'll be under "Random variables with density":en.wikipedia.org/wiki/Expected_value

  • @let6062
    @let6062 3 года назад

    Can you explain how to get the most probable velocity?

    • @brenobarbosa7254
      @brenobarbosa7254 2 года назад

      You just take the first derivation of the Maxwell distribution and make it equal to zero (because it is the top of the distribution).