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x^3log4+4^logx=10x^log4=t(x>0, t>0)t^3+t-10=0(t-2)(t^2+2t+5)=0t>0, t=2x^log4=4^logx=2logx=1/2x=rt10
Is it really Oxford test ? Easily can be resolved in brain...I would use 10, not 4, for the basis...😂
I have a question: you said b ^ log a = a ^log b. When you had x ^ log 4^3 why not switch it at the beginning of the video to 4^log x^3?
If you do so you'll violate power rule. Be careful when dealing with rules of exponentiation 💯💖✅💕
x^3log4+4^logx=10
x^log4=t
(x>0, t>0)
t^3+t-10=0
(t-2)(t^2+2t+5)=0
t>0, t=2
x^log4=4^logx=2
logx=1/2
x=rt10
Is it really Oxford test ? Easily can be resolved in brain...I would use 10, not 4, for the basis...😂
I have a question: you said b ^ log a = a ^log b. When you had x ^ log 4^3 why not switch it at the beginning of the video to 4^log x^3?
If you do so you'll violate power rule. Be careful when dealing with rules of exponentiation 💯💖✅💕