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x^2 = 3(x^2-3x+3)-(2x-3)(x-3)Why in this way because we can split into two integrals In first we cancel numerator with denominator Second integral we can calculate by partsYou recorded this integral earlier Somethiing wrong is with that video ?
x^2 = 3(x^2-3x+3)-(2x-3)(x-3)
Why in this way because we can split into two integrals
In first we cancel numerator with denominator
Second integral we can calculate by parts
You recorded this integral earlier
Somethiing wrong is with that video ?