Can you Pass Stanford University Admission Test ? Final Solution may Surprise You✍️🖋️📘💙

[@srinivasch-re2oq]

I think we need lot of practice to solve such complex roots.

[@НеллиПшено]

Решаем методом устного счета.
Используем свойства логарифмов.
log(m^1/3×m^1/2)=log(1/3)^3+log2
m^5/6=(1/3)^3
+log2
m=(1/27+log2)^
6/5
Good luck!

[@saifsawafi2773]

I think you have taken very long path to find X. If it was me, then below is the path that I would have taken;
1. Y = (-1/3+✔3/3)
2. Y^2= (-1/3+✔3/3)^2 = (4/9-2✔3/9)
3. Y^4= (Y^2)^2 = (4/9-2✔3/9)^2 = (28/81-16✔3/81)
4. Y^6= (Y^2 * Y^4) = (208/729-120✔3/729) = (208-120✔3)/729 = X

[@superacademy247]

Thanks for sharing your method and brief approach ✅🙏🥂

[@saifsawafi2773]

You are welcome.
Alternative is as below steps :
Rearrange ∛m+√m=2/27 to 27∛m+27√m=2
1).Find portion of 2 that equates to 27∛m and 27√m.
2).27∛m+27√m = 2r + 2(1- r) r= ratio
3).27∛m=2r & 27√m=2(1- r)
4).m=( 2r/27)^3 & m=[ 2(1- r)/27]^2
5).(2r/27)^3=[ 2(1- r)/27]^2 and expand.
6).(8r^3-108r^2+216r-108)=0
7).4(2r^3-27r^2+54r-27)=0
8).4(2r^3-3r^2-24r^2+36r+18r-27)=0
9).4[r^2(2r-3)-12r(2r-3)+9(2r-3)]=0
10).(2r-3)(r^2-12r+9)=0
11).r1=( 3/ 2), r2= (6+3√3), r3= (6-3√3), hence r3 is the answer
12).m=[ (2(6-3√3))/27]^3 & m=[ 2(1-(6-3√3))/27]^2

[@mariateresasatta]

Your shadow covers the text... very annoying :(

[@thierrygermain5182]

Quelle accumulation de redondances, de maladresses et d'inaudibles détails !!! Si vous voulez réussir, commencez par chasser les efforts inutiles ! Cela demande de REFLECHIR avant d'ECRIRE !

[@thierrygermain5182]

Je peux vous communiquer une solution rédigée qui RIDICULISE celle-ci...

[@superacademy247]

We're waiting for your perspective 🙏💕. This community needs more approaches!