Thank you very much. I have really understood organ pipe’s problems. I have had a lecture on it today which I kinda couldn’t understand but with you I did it. Thanks once again!
The examples are good but some background on why the formulas are the way they are (why can n only be odd for closed pipes, etc) would have been helpful.
But sir I thought for a close and open pipe fundamental frequency is :f is velocity divided by 4length because the first overtone is half so we multiply half by half na
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Alberto Aponte 331 m/s is the experimental velocity of sound in air at 0°c.so for 15°c he multiplies it by 0.6 and adds to the initial value to get approx velocity of sound at 15°c
where to get the v=331m/s + 0.6T with the answer of 340 m/s? like... the 331 and 0.6 comes from where? and why do we have to use the equation to get v? can you explain to me please.... i have exam in less than 48 hours... :')
Because velocity changes with different mediums (solid> liquid>Gas) and in Gas, the temperature can change the velocity so you’d need the temperature to calculate the velocity of sound in the air. and its usually 340 or 343 m/s.
@@petereziagor4604 It's not at all constant. It's 331 m/s in air at 0 degrees C, but the speed will increase with the temperature in said air since sound waves are a form of kinetic energy and kinetic energy is dependant on temperature. Therefore, at 100 degrees Celsius, the speed of sound in the air will be 386.6 m/s. Or are you talking about 0.6? That IS a constant. But 331 m/s certainly is not.
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Thank you very much. I have really understood organ pipe’s problems. I have had a lecture on it today which I kinda couldn’t understand but with you I did it. Thanks once again!
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wait so what is n
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The examples are good but some background on why the formulas are the way they are (why can n only be odd for closed pipes, etc) would have been helpful.
But sir I thought for a close and open pipe fundamental frequency is :f is velocity divided by 4length because the first overtone is half so we multiply half by half na
Where did you get this veloicty equation from, it was 343 +0.06(t) ?
That is the equation to find velocity with temperature. It’s v=331+.6 (temp.)
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@Noel Bisuku He meant 3rd view, probably.
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Sir where do uh get the 0.6
I don't know where you got 331 m/s and 0.6T. Can you tell me where it's from please?
Alberto Aponte 331 m/s is the experimental velocity of sound in air at 0°c.so for 15°c he multiplies it by 0.6 and adds to the initial value to get approx velocity of sound at 15°c
@Noel Bisuku but.. why do we add 0.6?
@Noel Bisuku Why do we need to add 0.6T??
where to get the v=331m/s + 0.6T with the answer of 340 m/s? like... the 331 and 0.6 comes from where? and why do we have to use the equation to get v? can you explain to me please.... i have exam in less than 48 hours... :')
Because velocity changes with different mediums (solid> liquid>Gas) and in Gas, the temperature can change the velocity so you’d need the temperature to calculate the velocity of sound in the air. and its usually 340 or 343 m/s.
6:55 what is meant by OT?? I wonder.
Overtone
You will actually learn it all from the 3hrs video 😁
the last example was poor. where is the thumbnail
How did you get 331 m/s?
Thats the velocity of sound in air
It's constant 😁
They could say calculate the speed of a sound wave at 100°c
Then it's going to be 331 + 0.6(100)
@@petereziagor4604 It's not at all constant. It's 331 m/s in air at 0 degrees C, but the speed will increase with the temperature in said air since sound waves are a form of kinetic energy and kinetic energy is dependant on temperature. Therefore, at 100 degrees Celsius, the speed of sound in the air will be 386.6 m/s. Or are you talking about 0.6? That IS a constant. But 331 m/s certainly is not.
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