I’m preparing for the PE exam and I find your videos the fittest teaching style for me. I had these classes 17 years ago. I was a good student but I skipped classes. Now I can’t believe preferring your videos over the textbooks. Thank you. ❤
Thanks! Yeah, self-locking or irreversible worm gears cannot be driven backwards, that's true. And the power efficiency for the ones that can would be terrible.
@@LessBoringLectures 13:46 Hello ! Can I know why you did not take into account the tangential force in the xy plane to calculate the reactions of the supports please? We should normally have the moment of force which is equal to Wwg*r (with r = radius of the wheel) at the center point of the wheel ! thank you in advance 🙏🙏🙏🙏👏
Hi ! while determining the Rby why didn't you add Wwga*r_wheel to the expression sum of moment about A, as you calculated in example 2 with bevel gears ? Thanks 😊
13:46 Hi ! Can someone explain to me why the tangential force in the xy plane is not taken into account to calculate the reactions of the supports, please? We should normally have the moment of force which is equal to Wwg*r (with r = radius of the wheel) at the center point of the wheel !?🙏🙏🙏🙏👏👏👏
Hi ! while determining the Rby I would add Wwga*r_wheel to the expression sum of moment about A. That's how he calculated in example 2 with bevel gears. I hope the autor would answer us :)
At 00:56 I presume the worm is right hand, as given also rotating anticlockwise based on its axis. what doesn't make sense is why is the worm gear rotating anticlockwise and not clockwise?
Yeah, this is hard to see in a 2D sketch. I will be adding short 3D videos of animations for these. But what is explained here is in indeed correct: right hand worm rotating counterclockwise from above will make the gear rotate counterclockwise from the front.
The tangential forces on each side would be equal to each other (in magnitude), and added up and multiplied by the radius of the worm gear, equal to the driving torque. Draw a free body diagram of the worm gear to see this.
I’m preparing for the PE exam and I find your videos the fittest teaching style for me. I had these classes 17 years ago. I was a good student but I skipped classes. Now I can’t believe preferring your videos over the textbooks. Thank you. ❤
This was one of the best lectures I’ve ever seen on this subject. Kudos
Thank you so much! Best lecture and clearest step by step lecture I've ever seen. This helped me so much with my components and design class!
I've never seen a worm gear drive a worm due to rotation resistance. I like the video.
Thanks! Yeah, self-locking or irreversible worm gears cannot be driven backwards, that's true. And the power efficiency for the ones that can would be terrible.
thx for clearing all my doubts
Amazing Illustration. Excellent Job
In machine design right now, this channel is incredible!
Hocamızda sizden öğreniyor. Teşekkür ederiz.
kdkdkd. teşekkür ederim!
@@LessBoringLectures 13:46 Hello ! Can I know why you did not take into account the tangential force in the xy plane to calculate the reactions of the supports please? We should normally have the moment of force which is equal to Wwg*r (with r = radius of the wheel) at the center point of the wheel ! thank you in advance 🙏🙏🙏🙏👏
Hello, do you have sources for any of these calculations you are doing?
Hi ! while determining the Rby why didn't you add Wwga*r_wheel to the expression sum of moment about A, as you calculated in example 2 with bevel gears ?
Thanks 😊
Are the pressure angle and lead angle the same ?
13:46 Hi ! Can someone explain to me why the tangential force in the xy plane is not taken into account to calculate the reactions of the supports, please? We should normally have the moment of force which is equal to Wwg*r (with r = radius of the wheel) at the center point of the wheel !?🙏🙏🙏🙏👏👏👏
Hi ! while determining the Rby I would add Wwga*r_wheel to the expression sum of moment about A. That's how he calculated in example 2 with bevel gears. I hope the autor would answer us :)
In the example the Tb is calculated with zero friction?
How does this differ if there are two worm gears acting on it?
At 00:56 I presume the worm is right hand, as given also rotating anticlockwise based on its axis. what doesn't make sense is why is the worm gear rotating anticlockwise and not clockwise?
Yeah, this is hard to see in a 2D sketch. I will be adding short 3D videos of animations for these. But what is explained here is in indeed correct: right hand worm rotating counterclockwise from above will make the gear rotate counterclockwise from the front.
what software do you use? i want to use it too
Isn't that left hand worm in example on minute 10.59?
what would happen to tangential forces on the worm gear if the worm gear was sandwiched between two spurs?
The tangential forces on each side would be equal to each other (in magnitude), and added up and multiplied by the radius of the worm gear, equal to the driving torque. Draw a free body diagram of the worm gear to see this.
is the pressure angle normal pressure angle?
Relent .