At 16:29 Correct solution is given below lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) 1. Find the derivatives of the numerator and denominator: f(x) = x^4 - 81 g(x) = 2x^2 - 5x - 3 f'(x) = 4x^3 g'(x) = 4x - 5 2. Evaluate the limit of the ratio of the derivatives: lim (x -> 3) (f'(x) / g'(x)) = 108 / 7 3. If the limit of the ratio exists and is finite, then the original limit is the same: lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7 Therefore, lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7.
Sir at 17:57 u wrote that 0/0 is 0 , which is wrong ❌ since Enything divided by 0 is not defined till now... I don't think I'll get attention, but still m writing this for my self satisfaction 😂
53:46 Sir in this ques, we have to find the value at which limit exist But you have not found the values rather you solve it normally plz pay attention towards this ques But at the end your explanation are fabulous and amazing 😊😊
Bhai Har jagah exist karega limit except zero kyuki tum koi aur no. Lo let 1 to x→1+ ya x→1- dono me ek hi answer aaega ek hi value diya hai na Ise questions me bas intervals change jaha hote hai wahi pe check kiya jata hai
53:56 sir answer is wrong, it asked "For what value does limit exist" pls see it and upload a shorts or something on it,giving correct answer, pls sirr
24:40 Sir prerajulisation means that it is a mental purification process that involves training a subject to lose all fears of the mind and body Farhan nitrate is Fh(NO3)2 Sir these words have meaning. In the movie they just show like this but in real they are words
Hi sir, in 32:21 there is no need to change the question, all we have to do is rearrange we can take (x+1) as y and add +1 and - 1 to the denominator such that it would look as so, [(x+1)^5 -1]/[(x+1)-1] and after using the formula (x^n-a^n)/(x-a) = na^(n-1) and we would eventually get the answer as 5 [pls correct me if I'm wrong]
There may be some calculative errors.. ofcourse we can correct it during practicing the question...But the simplicity with which sir taught the chapter .... Awesome..... Concepts CLEAR.....Great lecture 😊😊😊😊😊😊🎉❤😊😊😊
Nhi abhi jo sir ne peeche slide mai 3rd wala cos ka formula lagaya tha 1-cosx/x = 0 woh put Kara hai yaha pe isliye yeh final answer hai aur 0/0 form nhi bani isme answer sirf 0 hai
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You are the teacher for making the future of today's children that are in 11 standard you are the teacher not for destroy the future of today's children
Sir I have a doubt our school teacher has told us to not use tan theta formula direct in the question beacause it is in a form of question in the ncert example 4 so we can not use the formula direct please reply sir it’s a humble request ❤🙏🏻🙏🏻🙏🏻
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ruclips.net/video/pDa6IMoo6dE/видео.htmlsi=OJwFiEogOLM-oRqe
Link of derivative topic
Thanks sir
sir aap accha padhate ho, par bhout blind mistake bhe karte ho aap
kahan ki mistake@@pragya-l6d
@@pragya-l6d kaha he mistake 😅😅
Mujhe
mistake found in x⁴-81/2x²-5x-3
Sir in x+3
3+3 = 6 not 9
Haa bhai sahi bola
Yesss bro I also noticed this problem instantly
Hi bro
H the correct answer is 108/7 16:26
No it is 16:45
16:26 Dear Ushank sir with respect
Sir,x+3=6 hoga so final answer will be 108/7 not 162/7 . Please pay attention
Thankyou Sir
Sahi baat Hai
Thanks and plz share
@@gwsatyam2779 aye chup re...idhar Tera formal letter writing nai chal raha😂
😂😂😂😂 dubara kar
Scrolling comments for answer like this checking I am wrong 😂😂 or not
16:28 Sir, apne 18×9 kar diye he, par question me toh 18×6 hona chahiye
(x²+9) (x+3)
(3²+9) (3+3)
(9+9) (6) = 108
Toh uska answer *108/7* hona chahiye
yes sir he is right
Right bro
right brother
Correct
👍
4 ghante baad exam h... 2 lecture dekhna h... 😎😎
Ncert karna h...
Confidence exosphere me h... 😎
Kvian...
Annual exam tha ?
At 16:29 Correct solution is given below lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3)
1. Find the derivatives of the numerator and denominator:
f(x) = x^4 - 81
g(x) = 2x^2 - 5x - 3
f'(x) = 4x^3
g'(x) = 4x - 5
2. Evaluate the limit of the ratio of the derivatives:
lim (x -> 3) (f'(x) / g'(x)) = 108 / 7
3. If the limit of the ratio exists and is finite, then the original limit is the same:
lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7
Therefore, lim (x -> 3) (x^4 - 81) / (2x^2 - 5x - 3) = 108 / 7.
both ways are correct
@@ConceptHelper no
Why @@primanftw
34:00 also, break x^10 - 1 => (x^5 + 1)(x^5 -1) , x^15 -1 => (x^5)^3 - 1^3, then apply rule.
You teaching style is very nice 👍.VOTE for derivatives 😅
sir Your teaching style is very nice 👍...
Yeah . I agree. Me maantha hu
12th class students clearing backlog ☠️
Attendance here🫂
Meanwhile 11 class students 🎃👺
BCA student clearing backlog ☠ ☠ ☠ ☠ ☠
@@x-PHOBOSbhai baca karna tha kuch samjha de bro
@@Idn721 12th kar liya ?
Haa@@x-PHOBOS
34:00 mistake found
Answer is 5 and not 3/2.
If we reduce both equations we will get
x^5-1/x-1
= 5(1)^4
= 5 ans.
Same ans as in ncert
Bro Answer is 3/2 not 5
Anyone in November watch 😅😅
Me ,on 19
Sir at 17:57 u wrote that 0/0 is 0 , which is wrong ❌ since Enything divided by 0 is not defined till now...
I don't think I'll get attention, but still m writing this for my self satisfaction 😂
Enything nahi anything hota h 🚬sir ko sikhane se phele khud toh seekhle 🤣
Heyy r u kvian?? Delhi se????
53:46 Sir in this ques, we have to find the value at which limit exist
But you have not found the values rather you solve it normally plz pay attention towards this ques
But at the end your explanation are fabulous and amazing 😊😊
Bhai Har jagah exist karega limit except zero kyuki tum koi aur no. Lo let 1 to x→1+ ya x→1- dono me ek hi answer aaega ek hi value diya hai na
Ise questions me bas intervals change jaha hote hai wahi pe check kiya jata hai
53:56 sir answer is wrong, it asked "For what value does limit exist" pls see it and upload a shorts or something on it,giving correct answer, pls sirr
16:20 Sir 3+3=6 hoga and answer 108/7 ayega [KOI NI HOJATA HAI]
Correct ✅
24:40 Sir prerajulisation means that it is a mental purification process that involves training a subject to lose all fears of the mind and body
Farhan nitrate is Fh(NO3)2
Sir these words have meaning. In the movie they just show like this but in real they are words
💀💀 i dont know where you read this from but it is wrong. Those words does not exist in real life.
Hi sir, in 32:21 there is no need to change the question, all we have to do is rearrange we can take (x+1) as y and add +1 and - 1 to the denominator such that it would look as so,
[(x+1)^5 -1]/[(x+1)-1] and after using the formula (x^n-a^n)/(x-a) = na^(n-1) and we would eventually get the answer as 5 [pls correct me if I'm wrong]
Cosec (0) = not defined sir ! Not zero 28:41
Can't believe there aren't any more comments saying this!
At 49:51 there is two questions first the value of limit x - 0 and limit x-1
There may be some calculative errors.. ofcourse we can correct it during practicing the question...But the simplicity with which sir taught the chapter .... Awesome..... Concepts CLEAR.....Great lecture 😊😊😊😊😊😊🎉❤😊😊😊
Kisne 11th class mai limits and derivatives nhi padha tha jo aab vapas aaya h 12th mai ye video dekhne😂😂
Its me... Hiee🥲✌
@@Sheison1 hello🥲🤭
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@@AnkitBharti-sd2so tum snap pr ho?
@@AnkitBharti-sd2so btaoo kya h snap id
Sir aapne formula me limx-->0 sinx/x=1 kraya😢 so jab question krenge toh usme lim ax--->0 aana chahiye na sir 23:29
Bhai x→0 hoga to directly ax→0 hoga
Bhai basic Formula hota hai 0×any no. = 0 aur yah a ek constant hi hai
Es video ke mistakes
16:28
53:56
26:04
Sir 29:43 in the solution 1-cos x / x h Cos x b 1 hota h to 1-1 =0 and upon m x h to ye to 0/0 form hui na
yess
Formula
Nhi abhi jo sir ne peeche slide mai 3rd wala cos ka formula lagaya tha 1-cosx/x = 0 woh put Kara hai yaha pe isliye yeh final answer hai aur 0/0 form nhi bani isme answer sirf 0 hai
Exam se 1 ghanta pehle dekh raha hu 😂😂
Me too
To padh le comment kr raha hai😂😂
Waa bro
Video hi 1 ghante ki hai
16:26 sir 3+3=6 not 9
Bro's calculation is faster than any super car....!! Dyaaaaam...!! 😭🤌
16:26 mai (x+3) ha our x=3 so answer 6 hai 9 nahi sir ❤
16:22 pr mistake hai 3+3 is not equal to 9 (3+3=6)
Sir pls check the answer of the que x⁴-81/2x²-5x-3 the final ans is 108/7
yess mera bhi wahi aa raha hai
Hey bro actually your answer is wrong
Your teaching style is same as Ashu sir 😂
*At **17:57** 0/0 is undefined not 0*
Sir you look like Faf-Du Plessis 😂
😂,,,😂😂😂
My ki baat chhin li
Bhai kitna IPL dekhoge😂😂😂
lim
x tends to faf du plessis
Ha bhaiya sach mei ekdum faf du plesis leg rehe he sir
29:39 pr undefined hi bn tha hai...upon me x hai to. Ans zero kaise hua .. 1hoga again 1_cosx /x vala
13:00 we can take x+or- (opposite singh of a) will be problem creator
in 28:41 sir sin0=0 so cosc0 is not 0 rather it is undefined
lim x -> 0 (xcos x - sin x)/(x ^ 2sin x)
Sir ye question solve kar dijiye please 🙏. without using L hospital rule
Ek question ka answer 108/7 correct tha toh aapne 162/7 nikala 😂😂😂😂😂
ha
🤣🤣
@@notopupgamer5141 another brilliant 😂
16:21 sir ans 18 ayega kyuki upar 3+3=6 hoga aap 9 likh diye ho galti se
man gaya yrr aaj to , kasam se maza aagaya aaj ki class mein , sala ye channel pehle dekha hota to class ka topper hota ....... i am now fully devoted member of SCIENCE AND FUN !!!!!!! ❤❤❤❤❤❤❤❤
15:59 3+3=9 kar diya
2023 2024 attendence here
Aa toh krna kya hai😂
@@Editsz_555 kab hai exam
🤣🤣@@Editsz_555
@@divyanshusingh001327th ko 😂😂
@@luckyff6794 dav???
Kis kisko lagta hai ki.....ye ashu sir ka judwa hai😂😂😂😂😂😂😂
Mereko 😂
Judwa hi h
Abe Bhai dono sir sage bhai hai ❤
Na mereko nahi lagte😂
Woi lagte hai😂
sir 16:21 pe 3+3 = 6 hoga
Han bhai
Ye faf du plessis jaise lagte h 😅
16:24 I think Aapka Answer galat hai sir (x+3) so x=3 then 3+3=6 hoga na aapne 9 likha hai
16:20 wrong answer sir
29:37 sir , ye question mein final ans 0/0 ki form mein hai toh aage toh solve karna padega na.aapne direct 0 answer likh Diya hai galti se
There is a identity na, limx tends to 0 1-cosx/x=0 that's why directly 0 has been written there..
29:33 mtlb kaise bhi answer la Dena hai bs😐....rule left the chat✅
Sirr tomorrow is my exam.. thank you so much for uploading this ❤
53:53 sir ncert mein peeche answer is given - limit exists for all a≠0 so kindly correct your answer.
19:23 yaad rkhoge toh achi baat hai nhi rkhoge toh bohot achi baat h
Vote for all maths important questions gor class 11 ( NCERT )
42:01 For Personal Reference.
26:06 how??
Same
You are the teacher for making the future of today's children that are in 11 standard you are the teacher not for destroy the future of today's children
22:09 here another way is just to take a/b common then evaluate
at 37:16,, can we multiply and divided the f(x) with the pie
Sir ek bus aap hi hai jiski wajeh se mera yeh chapter crystal clear huya hai ...apka mai thankyou 🥹 kese kur skti hu🫠😭✋🏻
👀🤧
Kuch jyada hi overacting ho gyi 😂
26:04 sir apne yha par 2 common kaise lia ...bta dijiye plz ....
(2cos²x-1)-1
In this -1-1 will become -2
Is liye aap esse 2cos²x-2 likh sakte hai aur 2 ko common le sakte hai
sir to be honest continuity bahut fast krwaya uske chakkar me smjh nhi aaya bilkul bhi pta nhi kab kya ho rha tha
16:26 x+3=6 not nine
16:27
sir x+3 its 6 not 9 . because lim. is 3 .
sandwich theorem -19:27
31:10
continuty - 42:00
53:25 Sir it was just a half part of that question😊😊
Sir at 29:42 Cosec 0 = infinity and cot 0 aslo = infinity so can we do ( infinty - infinity ) = 0
Infinity tak ko approach krte hai dono, asliyat me value defined nhi hai , toh 2 undefined value ko kaise zero mann skte hai ?
28:01 Sir yahan aapne sinx ko x se divide kar diya or into kar diya lekin sin0 ki value toh 0 hi hoti hai.
Thanks you sir❤ 17:24
16:12 sir x+3 9 nhi 6 aayega 🙏🙏🙏🙏
Sir roman number ke saath 'th' nhi lagate
It cannot be XIth
It is just XI
😱😱😱😱😱😨😨😨😨😱😱😱😱😨😨😥😥🤯🤯🤯🤯🤯🤯🤯🤯🤯🤯🤯🤯🤯🤯🤯🤯🤯🤯😱😱😨😨🙏🙏🙏😭😭🙏🙏🙏
Sir I have a doubt our school teacher has told us to not use tan theta formula direct in the question beacause it is in a form of question in the ncert example 4 so we can not use the formula direct please reply sir it’s a humble request ❤🙏🏻🙏🏻🙏🏻
42:32 leaving a timestamp to start again after practice
after watching all the videos on this topic now i got the best video for this topic and easy understandable tricks
14:28 why we can't factorise as 2x²-2x-3x-3 please anyone help😢
Same problem Hui mere saath 😅
kyunki -2x and -3x ka product +6x2 dega aur hame -6x2 chahiye
16:16 mistake
16:20 sir (3+3)=9
kbse hone laga 😅
49:50 sir iss question may answer 3 and 6 hai
One day before annual exam😂😂😂
1 hr before dekha maine 😂😂😂😂
16:28 it should be 18(6)instead of that
Sir dil khush krr diya 🥲🥲🥲
Bahut wait kiya iske liye
Valuable and very helpful for competitive exams 😊
26:17 pr 2common kaise aaya??? please reply
😢
25:19 how sir pls explain?
Trigonometry function of multiple
Double angle
meri toh supplementry lag gyi🤡🤡🤡
Meri bhi back aa gyi 🤡 8 ko paper hai 😂
Hmri bhi bhai
Konse class m ho
@@hazarikaakshay784d bhai ab tho 12th me aa gya 🦁
Waah main engg mein hu 2nd year
Sir it's x+3 = 3+3 = 6 and answer is 108/7
Thanks for mentioning,,,I'm searching for it.....:))))
suggestion:- Never should distracted by someone ...😃
Bhai kisko ya nhi lagta hai ki ye Ashu sir ka judwa bhai hai
2:00 class start
16:23 sir ans 108/7 hoga
26:08 -1 kaha gaya? And kaise 2 common?
Yar pta chala sir ne kaise common liya 2?
Bhai samajh agaya numerator me dhyan se dekho minus aur minus 1 milke minus 2 hogaya fir sir ne common liya 😂
@@Abhi-kj5vt thanku sir 🤣😅🙏
Your teaching skills are toooooo good 💯
2024 attendance for half yearly exam 😂
16:32 sir 18*3/7 and answer will be 108/7
16:50 16:51 16:51 16:51 16:51
24:39🔥
You are great sir ❤❤😊
30:56 ma guestion.ha (x+1)5 power _1 x not x +1
sir 5:17 mein forms ke baad kya likha hai aapne?
Ma kasam jis jis se like or subscribe nhi kiya wo pakka exam mak fail😢
Maa Kasam agar tune yeh chutiyap band nhi Kiya toh tuh pakka fail ho jayega
Ok bhai karba de
Mai ho gya 😢
Sir 16:28 apna mistakely galat kia ha right side pa jab apna (x+3) kia 🤔
Sir aap se pehle baar pdha maine
Bahut accha lga or samajh me bhi aaya 😊 Thank you