DC to DC Boost Converter Circuit Using XL6019

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  • Опубликовано: 26 авг 2024

Комментарии • 20

  • @neilthompson6713
    @neilthompson6713 Месяц назад

    When I graduated from school some years before the dawn of the Internet, I thought that I could do anything. Give me an electrical engineering problem, and I could solve it. Hardware, software, everything. How naive I was. Back then I knew the fundamentals; nothing else. Every time I watch this man’s videos, I see a real expert. I hope that everyone watching appreciates the quality of these works.

  • @eerrfanshayyestehh2069
    @eerrfanshayyestehh2069 Месяц назад

    Hi my friend; all your products is the best
    Good luck

  • @mauriciorodrigues9991
    @mauriciorodrigues9991 Месяц назад

    another good project.

  • @MyVanitar
    @MyVanitar  Месяц назад +1

    DC to DC Boost Converter Circuit Using XL6019

  • @chathurangaheenkenda7259
    @chathurangaheenkenda7259 Месяц назад

    sir good job.

  • @hp2073
    @hp2073 Месяц назад

    To answer your question, I think the shield of the USB should not be connected to the ground

  • @hp2073
    @hp2073 Месяц назад +1

    I have a power bank which can be used with this circuit 😊

    • @MyVanitar
      @MyVanitar  Месяц назад

      go ahead and build it

  • @SKElectronics
    @SKElectronics Месяц назад

    with usb type c why don't you also try to make pd trigger board with let say dip switch to select output voltage then will have a wide range of selectable output voltage.

    • @MyVanitar
      @MyVanitar  Месяц назад

      if you want other output voltages, simply change the feedback resistors. also, be careful about the voltage rating of the output capacitors

    • @SKElectronics
      @SKElectronics Месяц назад

      @@MyVanitar yes I understood.

  • @jacekkarczewski8821
    @jacekkarczewski8821 Месяц назад

    What happens when you short the output?

    • @MyVanitar
      @MyVanitar  Месяц назад

      These chips are all protected against short circuit

    • @jacekkarczewski8821
      @jacekkarczewski8821 Месяц назад

      @@MyVanitar Not true. Look at the schematic. When output voltage is lower than input (short circuit condition) there is direct current path through inductor and diode. It should have at least a fuse on input power line to avoid major disaster.

    • @MyVanitar
      @MyVanitar  Месяц назад

      it depends on your input supply. also when the input drops below 5V, the chip turns off. Maybe the EN pin can also help, but for my case and purpose of this circuit, disaster never gonna happen