10.Fluid Dynamics: Euler's Equations of Motion for inviscid flow-II| UPSC CSE| IFoS| Shivraj Gurjar
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- Опубликовано: 6 сен 2024
- Questions based on Euler's Equations of Motion for inviscid flow are expalained, including CSE PYQ 2006.
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#EulerEquationsOfMotion#MechanicsAndFluidDynamics#MathematicsOptional
Thank you sir
Such a great patience in solving complex problem. Thank you sir
🔥❤️ thank you sir
Welcome, Anuj :)
Thank you so much Sir
Most welcome, Nikita :)
@@Mathocrat Sir please Statics and Dynamics bhi cover krwa dena..aapke lectures se interest bna h in topics me..
yes, i plan to do that :)
@@Mathocrat Ok sir..Thanks :)
22:57 sir at this point can't we convert u into forms of dr/dt because it's very lengthy to calculate first in terms of u then integrate 2nd time dr/dt 🥲🥲. I completed the complete solution then this doubt came up
u is dR/dt
@@Mathocrat OK sir, thank you for the lecture
Thank you sir 👌👌
Welcome, dear :)
Sir, at 25:30, why we are integrating for the limits a to R, to calculate the time from infinity to the initial boundary?, r tends to infinity at terminal point, so won't the limits be a to infinity?
we are getting U as function of R
Why R is in negative sign at 30:44?
velocity is in the direction of R decreasing
sir at 27:44 how is the value of c taken to be 2pia/rhow we have calculated it to be pi/rhow
That c is different actually. See at 16:57
Keep it up... God bless you
:)
sir the second question that you have done was very lengthy , is upsc asked these type of question in exam?
Yes, but less frequent
@@Mathocrat oki sir thank you🙏
Sir, when internal cylinder is annihilated, is the velocity inside the cavity also zero or is velocity zero only at the boundary? Similarly, is pressure zero only on the boundary or inside the cavity also?
at t=0 , velocity is zero, as liquid will be released radially once cavity is formed.Pressure will be zero inside the cavity here , Aman
@@Mathocrat Thank You Sir !!
Respect for your dedication and efforts sir...thank you again. How many lectures are required to cover the remaining parts of this topic?? It will be very helpful if you can provide some rough idea about this.
Welcome Ratnesh.. I think 10 or so lectures will be needed.. More than half the syllabus of this topic is already covered.
Okay sir...looking for those lectures.
Hello sir.... @28:19 i think one 'a' along with 3*(a2-R2) is missed.Please correct me if wrong?
Yes, corrected later on
Sir in 2 problem, you say small r and t are independent in fluid but capital R is function of t on cavity and find velocity =dR/dt how?
r nd t are independent variable, but R is changing with time ie it is functiin of time
@@Mathocrat but r and R represent same thing at distance r and R from centre
@@rajeshjaiswal3194 No, please re-watch
Sir 1st question main theta ke along flow kyun nahi ho sakta ? radial kaise mana hai sir ye samajh nahi aaya
The pressure on fluid is along the radius , so if we remove fluid from inside then the balance fluid will move radially
Sir it's my humble request ..... could u plssss explain why velocity is zero at both the surfaces (at R1 and R2)?
Sir at free surfaces velocity is always zero?
Yes, generally, Madhu.
3:25 ro constant kiu liya sir?
Fluid is assumed incompressible.
👍👍
sir please could you tell the value of ' F ' ( Force per unit mass) in the ques i am writing below and a hint of how we got that value also.... ........ A mass of gravitating fluid is at rest under its own attraction only , the free surface is a sphere of radius 'b' and the inner surface a rigid concentric shell of radius 'a' . Show that if the shell suddenly disappears, the initial pressure at any point of the fluid at distance 'r' from the centre is .........
thats simply g na?
@@Mathocrat yes sir it is 'g' , but could you please write the value of 'F' and give me hint of how it came , it would be very thankful of you!!
@@Mathocrat Sir in the book they have written F= 4πG(rho) (r'^3-r^3) /r'^3, where G is the constant of gravitation, r' is the distance of fluid, r is the radius of cavity at any time 't'.
Sir i was not able to understand how this came!!
@@Karanveer-ii5vg Thats formula g=Gm/r^2 only
use mass m=rho*volume of liquid
Ok , Thanku sir..🙂
sir, having difficulty in understanding direction of flow ki kab konsa hoga
What is the issue exactly? you would get it with practise.
@@Mathocrat sir like by 1st problem how can we know that there will be no other velocity apart from radial i.e how q theta and along z will not be there?
@@praveenjangid829 okay. It is due to that shape of anhilitated part. This part will be field by the fluid. It will move radially as radial push was keeping that liquid away.
sir, kisi kisi question me boundary condition smjh nahi aate , why u= zero or pressure =0 in cavity cases while annihilation , if time permits such common boundary conditions kisi video me bata dete ?
okay, tanmay :)
I could also not understand why velocity would be 0 in case of annihilation. Even pressure should not be 0 as there should be some pressure from liquid in outer cylinder
@@iknowinfinity as liquid has been annihilated so there will be sort of cavity, No pressure. For velocity part, note that the liquid will be released radially once the inner part liquid annihilated, so it has to be zero at t=0. Also , note that generally velocity at infinity will be zero, unless given otherwise.