3 hours until my last ever math exam and i can't wait for it to be over. thank your for all your help these past couple of years ! i wouldn't have managed self-studying a levels without your channel. all the best !
The very final questions you said air resistance was a limitation but the question says 'other than air resistance'. What would be another answer? Could you say the balls are massless, you assume they collide, they both have the same mass, they are thrown with equal force??
I said wind which would be a correct answer here, as wind and air resistance technically aren't exactly the same thing! To mention anything about mass would be incorrect here, because the model does not need to account for it. Why? Because acceleration due to gravity is always g, no matter the mass of an object. In terms of the collision: The model is valid up until the point at which they collide, so it doesn't care about the collision, only the motion before it. Again to talk about forces isn't really what they're after either. Yes, an initial force would be required to launch the balls, and for a given initial velocity the higher the mass of the ball the more force would be required, but this question doesn't care. We're told the initial velocity and that's all that we need to worry about. All of the maths in the question would be valid no matter what the initial forces were. What they're after is more about the _shape_ of the balls: The classic assumption is that they're particles (essentially treated as a single point), but in reality they have a shape and size, they can spin around etc., all of which will affect the motion. They'd also throw you a mark here for saying in reality g isn't exactly equal to 9.8 😊
Wind is different from air resistance. Wind is an external factor whereas air resistance is the friction of an object with regards to moving through the air.
for question 3 mechanics in part a i found acceleration in terms of T from my second equation (3mg-T=3ma) and substituted it into the first equation (T-2mg=2ma) this doesnt give me the right answer and i dont understand why. can anyone help pls?
i did it this way and it does get the right answer. Add these 2 equations together and you get mg=5ma which means g/5 =a. Sub the value of a in and you get the right answer
Im confused about question 4 for mechanics. Why isn't there a horizontal component of 20g and why is it taken as just 20g when it's not acting perpendicular? I'm really lost lol
As the point is where the centre of mass of the plank is acting through, rather than a reaction force from an object. When using up=down there's no angle as it is straight, but when using left=right or up the slope=down the slope you'd need to take respective components. Good luck tomorrow :)
question 4 for mechanics. Why isn't there a horizontal component of 20g and why is it taken as just 20g when it's not acting perpendicular? I'm really lost lol
At 1:53:53, I meant 29 degrees! Too much mechanics can make someone's head go funny...
Could you do walkthroughs for 2020 2021 and 2022 or maybe a predicted paper pleaseeee
This channel deserves more recognition you put so much effort into them thank you very much
Really appreciate that man! 🙏
channel's dead now lol
@@chunkplunk 😪
3 hours until my last ever math exam and i can't wait for it to be over. thank your for all your help these past couple of years ! i wouldn't have managed self-studying a levels without your channel. all the best !
@@andrewjg_ hi! it went well :) got a b and I'm now studying psychology at uni. best of luck!
This guy is so helpful! I hope he continues to upload vids for all the maths pprs!!
got my paper 3 tomorrow this is awesome
lmao same. goodluck for tmo bro
I can’t believe how good this is, thank you very much you deserve a big like👍
Aitutor, you are the BEST!
seriously underrated channel
I unfortunately only found you the night before my stats/mechanics exam. Charge it tho
Could you do the 2022 edexcel paper please? I think they have just come out recently.
bruno fernandes
The very final questions you said air resistance was a limitation but the question says 'other than air resistance'. What would be another answer? Could you say the balls are massless, you assume they collide, they both have the same mass, they are thrown with equal force??
I said wind which would be a correct answer here, as wind and air resistance technically aren't exactly the same thing!
To mention anything about mass would be incorrect here, because the model does not need to account for it. Why? Because acceleration due to gravity is always g, no matter the mass of an object.
In terms of the collision: The model is valid up until the point at which they collide, so it doesn't care about the collision, only the motion before it.
Again to talk about forces isn't really what they're after either. Yes, an initial force would be required to launch the balls, and for a given initial velocity the higher the mass of the ball the more force would be required, but this question doesn't care. We're told the initial velocity and that's all that we need to worry about. All of the maths in the question would be valid no matter what the initial forces were.
What they're after is more about the _shape_ of the balls: The classic assumption is that they're particles (essentially treated as a single point), but in reality they have a shape and size, they can spin around etc., all of which will affect the motion. They'd also throw you a mark here for saying in reality g isn't exactly equal to 9.8 😊
so helpful explanations, thank you so much
I actually hate stats so much
Questions 5C clearly says, state one limitation of the model, other than AIR RESISTANCE, but he says the answer as wind, which is wrong 2:02:14
Wind is different from air resistance. Wind is an external factor whereas air resistance is the friction of an object with regards to moving through the air.
Mate you legend saved my arse
Saving arses since 2020 🔥
Not a student, just a fan of Patrick👍🏽
for question 3 mechanics in part a i found acceleration in terms of T from my second equation (3mg-T=3ma) and substituted it into the first equation (T-2mg=2ma) this doesnt give me the right answer and i dont understand why. can anyone help pls?
i did it this way and it does get the right answer. Add these 2 equations together and you get mg=5ma which means g/5 =a. Sub the value of a in and you get the right answer
For Q4 b How do we know that we need to find I F I = squared root of RA^2 + F^2 ?
its asking for the resultant force
When are you doing the 2020 papers.
I'd love to mate but I can't! They're not available for public use yet. If there's anything else though that you'd like to see let me know!
@@AITutor you gotta do this video where you go through 5 hardest A level maths Qs
@LFC Rags great shout 🔥
@@AITutor no problem. Love ur enthusiasm. It’s helping me feel better in lockdown. Let’s get those Hardest Qs Banged 💥🔥
@@AITutor any luck with that video then
Can anyone explain why wind direction (bearing or cardinal direction) is an unacceptable answer for 2. e - thanks
dunno
Im confused about question 4 for mechanics. Why isn't there a horizontal component of 20g and why is it taken as just 20g when it's not acting perpendicular? I'm really lost lol
As the point is where the centre of mass of the plank is acting through, rather than a reaction force from an object. When using up=down there's no angle as it is straight, but when using left=right or up the slope=down the slope you'd need to take respective components. Good luck tomorrow :)
question 4 for mechanics. Why isn't there a horizontal component of 20g and why is it taken as just 20g when it's not acting perpendicular? I'm really lost lol