Formaldehyde Molecular Orbitals

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  • Опубликовано: 3 янв 2025

Комментарии • 8

  • @holypeachy
    @holypeachy 2 года назад +2

    That's a very nice glass dip pen and it looks like you used a stub or italic nib for the title of the page. It's so nice seeing people use good writing instruments outside of the hobby space.
    I was just some looking for some clarification on MO theory and I found gold.

    • @Chemistryuniversity
      @Chemistryuniversity  2 года назад +2

      Thank you. I am using a flat nib fountain pen for the titles. I thought it would look nice for my videos.

  • @anjalyps4065
    @anjalyps4065 Год назад

    A big thank to you sir, actually it make my head ache while understand the digram , the correlations and all🤯 . It was so clear. Thanks a lot❤

    • @Chemistryuniversity
      @Chemistryuniversity  Год назад +1

      After having a few of these explained, and looking at several more, you will see them in a new light. You will also look at reactions differently.

  • @aaronmargolit161
    @aaronmargolit161 Год назад

    Hello, amazing video and thanks for explaination. I was just curious why the 1s hydrogen orbitals are shown with a higher potential energy than the oxygen 2p orbitals if p orbitals are to be filled after s orbitals with the Aufbau principle? Thank you for your time.

    • @Chemistryuniversity
      @Chemistryuniversity  Год назад

      This is based on the atomic energies of the orbitals. H 1s is -13.61 eV and O 2p are -15.85 eV. So the hydrogen is a higher energy. These are on different atoms so the Aufbau principle does not apply. The orbitals are individually populated based on the atomic electron configuration which does follow Aufbau. That is why there is 1 electron in each hydrogen atomic orbital to start and a total of 6 valence electrons in the oxygen orbitals.

  • @jackzhang9164
    @jackzhang9164 7 месяцев назад

    Very good explanation, just one thing, your B1 and B2 MOs don't match the number of AO, switch B1 with B2 in the MO would be perfect!

    • @Chemistryuniversity
      @Chemistryuniversity  7 месяцев назад

      Yes, it appears I labeled 1 of the orbitals incorrectly. looks like the best location is in the anitbonding orbitals.