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you only solve for the tangent case, but there are 3 other possibilities1.- No solution2.- 2 solutions3.- 1 solution (2nd quadrant)
a^(1/ln a) actually can be simplify to e😂
Yup, Lambert W function is the way to go here.😊
Yeah, I really thought he was gonna use it.
Cool!
Did this with the formula for Lambert W, x=-[1/ln(a)]W( (-ln(a)/b) ), for a,b≠0 and a≠1If a=1 and b≠0, x=1/bAnd if a,b=0 x is any real number as a trivial solution i guess.
How can we find two solutions?
What app do you use to write these equations?
Google docs
😎👏👍✌️👏👍
Where is a
(e^x)^lna=bx...(e^x)^(-lna)x=1/b..(e^x)x=(1/b)^(-1/lna)...x=W(..)
This video was not up toyour usual standards! 😟
you only solve for the tangent case, but there are 3 other possibilities
1.- No solution
2.- 2 solutions
3.- 1 solution (2nd quadrant)
a^(1/ln a) actually can be simplify to e😂
Yup, Lambert W function is the way to go here.😊
Yeah, I really thought he was gonna use it.
Cool!
Did this with the formula for Lambert W, x=-[1/ln(a)]W( (-ln(a)/b) ), for a,b≠0 and a≠1
If a=1 and b≠0, x=1/b
And if a,b=0 x is any real number as a trivial solution i guess.
How can we find two solutions?
What app do you use to write these equations?
Google docs
😎👏👍✌️👏👍
Where is a
(e^x)^lna=bx...(e^x)^(-lna)x=1/b..(e^x)x=(1/b)^(-1/lna)...x=W(..)
This video was not up to
your usual standards! 😟