To find the probability that a randomly selected student from the group likes neither mathematics nor history, we need to subtract the probability of liking either mathematics or history or both from 1. Let's denote: P(M) = Probability of liking mathematics = 0.50 P(H) = Probability of liking history = 0.40 P(M ∩ H) = Probability of liking both mathematics and history = 0.10 The probability of liking either mathematics or history or both can be calculated using the principle of inclusion-exclusion: P(M ∪ H) = P(M) + P(H) - P(M ∩ H) = 0.50 + 0.40 - 0.10 = 0.80 Therefore, the probability of liking neither mathematics nor history is: P(Neither) = 1 - P(M ∪ H) = 1 - 0.80 = 0.20 The probability that a randomly selected student from the group likes neither mathematics nor history is 0.20, or 20%.
AI RESPONSE To find the probability that at least one of A, B, or C hits the target, we can calculate the complement of the probability that none of them hit the target. The probability that A doesn't hit the target is 1 - 0.3 = 0.7. The probability that B doesn't hit the target is 1 - 0.4 = 0.6. The probability that C doesn't hit the target is 1 - 0.5 = 0.5. Since A, B, and C are firing independently, the probability that none of them hit the target is the product of their individual probabilities of not hitting the target: P(None hit) = P(A doesn't hit) * P(B doesn't hit) * P(C doesn't hit) = 0.7 * 0.6 * 0.5 = 0.21 Therefore, the probability that at least one of them hits the target is: P(At least one hits) = 1 - P(None hit) = 1 - 0.21 = 0.79 The probability of at least one of A, B, or C hitting the target is 0.79, or 79%.
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Thanks pls solution
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To find the probability that a randomly selected student from the group likes neither mathematics nor history, we need to subtract the probability of liking either mathematics or history or both from 1.
Let's denote:
P(M) = Probability of liking mathematics = 0.50
P(H) = Probability of liking history = 0.40
P(M ∩ H) = Probability of liking both mathematics and history = 0.10
The probability of liking either mathematics or history or both can be calculated using the principle of inclusion-exclusion:
P(M ∪ H) = P(M) + P(H) - P(M ∩ H)
= 0.50 + 0.40 - 0.10
= 0.80
Therefore, the probability of liking neither mathematics nor history is:
P(Neither) = 1 - P(M ∪ H)
= 1 - 0.80
= 0.20
The probability that a randomly selected student from the group likes neither mathematics nor history is 0.20, or 20%.
Jegina
Video ko ayiseram
what about 3rd round GAT exam?
Dear the video that u upload is bleared and not visible will make it clear
Would you support as, by solving questions........
Are the questions in the GAT of AASTU the same or similar as these mock exam questions?
AI RESPONSE To find the probability that at least one of A, B, or C hits the target, we can calculate the complement of the probability that none of them hit the target.
The probability that A doesn't hit the target is 1 - 0.3 = 0.7.
The probability that B doesn't hit the target is 1 - 0.4 = 0.6.
The probability that C doesn't hit the target is 1 - 0.5 = 0.5.
Since A, B, and C are firing independently, the probability that none of them hit the target is the product of their individual probabilities of not hitting the target:
P(None hit) = P(A doesn't hit) * P(B doesn't hit) * P(C doesn't hit)
= 0.7 * 0.6 * 0.5
= 0.21
Therefore, the probability that at least one of them hits the target is:
P(At least one hits) = 1 - P(None hit)
= 1 - 0.21
= 0.79
The probability of at least one of A, B, or C hitting the target is 0.79, or 79%.
How is the answer ?their is wrong answer for some question
pls tell us the link
is the 2016 EC mock exam or the previous one sir?
It is not seen clearly ?
How is the result calculated and which is passing mark? Perecentil rank or exam score out of 125?
Todays MOCK EXAM
Q75?
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18020104
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