Transformations of Graphs (stretches) : ExamSolutions
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- Опубликовано: 1 окт 2024
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Despite being here 10 years late, this video helped me so much! Great explanation! Thank you so much for taking the time to create this video :)
You're welcome, Ryan.
*Edit 11 years :)
The minus would cause a reflection after the stretch. So -af(x) is a stretch of scale factor a parallel to the y-axis followed by a reflection in the x-axis. Also f(-ax) is a stretch scale factor 1/a parallel to the x-axis followed by a reflection in the y-axis.
THANK YOU SO MUCH, I WAS SO PUZZLED BEFORE BUT THIS VIDEO TAUGHT ME SO MUCH!
Your welcome
+ExamSolutions You're*
Hello people
i am an international student and i always get confused in math class because of the language problems. but i can catch up now after watched some of your videos! thank you so much!!!!
Saved my life a decade later. Thank you!! 👏👏
Still going.
This is in the 2020 updated syllabus, right?
@@aryanb737 Yep - I was using this to revise before an assessment. 👌
@@fh17522 so, how was the exam? Were you able to solve the transformation problem?
@@aryanb737 I'd done loads of revision for paper 1 but the teacher then decided we should do paper 2. :))) it was all good though. This video is definitely good to have in your corner. 👌
Thanks mate appreciate it , really clear tutorial
still over 10 years u are still helping people (including me now)! thank u for the help !!
13 years now bruh........ he uploaded video just 10 days ago... what a consistency
@ExamSolutions Sorry not strictly correct. Nothing if you have a vertical asymptote and you strech parallel to the y-axis and nothing if you have a horizontal asymptote and stretch parallel to the x-axis. However, if you have a vertical asymptote say at x=3 and you stretch by a scale factor of 2 parallel to the x-axis then this will now be at x=6. Similarly if you have a horizontal asymptote say y=2 and stretch by a scale factor of 2 parallel to the y- axis then it will now be at y=4
Even after doing extra coaching, I had difficulties understanding this and this video literally cleared all my doubts. Thx a lot.
I am so old after 12year I am watching this video And still its helpful
Thanks alot we need more people like you
@twelveheroes This will get twisted. so y=2x say streched parallel to the y-axis by a stretch of 4 units becomes y=8x
@twelveheroes y=x/2 for the oblique asymptote and x=0 stays the same if I am reading your question correctly.
Thanks very much! Cleared all my confusions about stretching graphs :)
Good to hear that is is sorted for you. Best wishes
You're my savior! I don't understand a thing in class and now I'm understand it crystal clear that I can even teach my friends!
Thank you!
You teach them. Good luck.
Good luck
@TooPizza1994 No probs - thanks for your support.
what if I want to strech x axis variably.....as a function of x??
Thank you so much I was so confused before I saw this. Thanks for the help!
You explained it in a simple and clear manner. Helped me understand it, thank you!
I'd never properly grasped this topic, but this video was just what I needed. Thanks!
you sir are a wonderful teacher!!
Thank you, you are too kind.
thank you sooooo much
EPIC LIFE SAVER!!!!! THANK YOU!! THIS IS LIKE A LAMP OF GUIDANCE TO ME!!! You gained another subscriber!
Despite being here 14 years late this video helped me so much. Thank you
I watch your videos all the time, your just so helpful and I really appreciate your work.. Your helping my revision - 2 months to revise for ALL of A-Level maths, gotta work hard for our dreams eh! On a side note tho, is there any shortcut to answering the REALLY hard questions? In maths generally? I guess its understanding whats going on..
Hi, I am pleased to hear that the videos are proving useful to you. Is there any short cuts. Not really, it is just hard work on your part. Do tons of questions from past papers and try other boards if you exhaust your board. You will then learn to apply methods as you have rehearsed them so many times. Good luck.
ExamSolutions Wow, It's an honour for you to reply to me, honestly I've been going all night finishing of C1, and I wouldn't understand alot of these concepts if it hadn't been for your wonderful videos, respect
what would happen to the asymptotes of a graph if it's stretched?
thank you so much. Most videos explain 6 rules but they dont explain the enlargement rules, this video did exactly that.
@twelveheroes nothing
Thank you so much sir.
It's really helpful for me ☺️☺️☺️☺️.
Thanks! I was really struggling with stretches specifically and you seemed to save me!
oh my god thank you so much you've literally saved my life i know i'm 12 years late but i love you so much man
Cool
Thank you for the explanation, this was very clear and concise. It helped me understand something my book skipped over.
Thankyouu ❤❤ love from Pakistan 🇵🇰
Thanks
U use the same term stretch for both the cases when there is a compression i.e in case y= f(2x) its not a stretch its compression.
When y=af(x), shouldn't the stretch be along the x-axis instead of being parallel to the y-axis and vice-versa with y=f(ax)?
Thankyou, a really clear and detailed explanation. 👍
Thank you.
Thank u bro. I have a test tomorrow. That really helped me.
Thankyou so much, this is very helpful
if the graph is let say y=(3x+4)^2 , what would happen to the translation?
Thanks
Its a translation of x^2 by 4/3 to the left
Can we say y=af(x) as is like pulling the graph from above and y=f(x/a) pulling graph from the right.
I suppose in a kind of way but in an exam you should be encouraged to use the words stretch, scale factor and invariant line.
Watching today one day before paper😂
Nice explanation. I really didn't understand this in my maths class, but this has made me understand it much better.
i did not know it was this easy thank u so much!!!!!
I really didn’t get it, and this was literally the ONLY video which I actually understood.
I have my gcse today, thank u so much
sorry for bothering, but if i have a graph of f(1/2x), what would my oblique asymptote x=y and vertical asymptote x=0 become?
Amazing! I've been struggling for ages with this. Thank you so much!
Really really helpful. This is recommended it really helps
Ty soooo muchhhhh
Glad to help.
Thanks a lot!
Understood ❤🎉
Could you be asked to prove why it translates/reflects/stretches in the exam?
I dont get how the first graph is parallel to the y axis and vice versa
These videos are great thank you so much!! I was wondering what would happen is the value of a was negative?
I think you just solved a big math issue of mine
That's good. Thanks for watching.
watch speed =1.5. You are welcome
@ExamSolutions once again, thanks a lot. stretching parallel to the x-axis is so confusing!
Hello
@ExamSolutions even for the oblique asymptote?
Thank you so much helped a lot!
THANK YOUUUUUUUU
Thank you for watching.
This video is also very helpful. Thank you.
😍I love you
I love everyone who supports this work
Very helpful- Thank you.
great! first time someone explained it well!
@ExamSolutions thanks so much! :)
1:30
WP WAGNER ANYONE??
1:31
Cheers mate.
Thankyouu!
Awesome bro, perfectionist!
thank you!
amazing! thank you
I'm pleased to hear it helped.
Thankk uu sooo much
No problem. You are welcome.
This was the only part in the book I was stuck in and you explained it very well and have made me understand it a lot more! Thanks ever so much! (Got my GCSE in a couple of weeks so thanks for your help)!