Secant Method with MATLAB code

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  • Опубликовано: 2 окт 2024

Комментарии • 37

  • @daretodo2256
    @daretodo2256 2 года назад +1

    Great ✨✨

  • @sabamukhtar4598
    @sabamukhtar4598 2 года назад

    بہت خوب

  • @JuLy-gi5im
    @JuLy-gi5im Год назад

    Thank you sir

  • @abdullahnasir46
    @abdullahnasir46 Год назад +2

    just so u know, u r a good teacher

  • @dikshakushwaha7081
    @dikshakushwaha7081 3 года назад

    Thanks👍

  • @ShankhaSaha
    @ShankhaSaha 3 года назад

    Great work bro! Learnt a lot from your videos, but can't really use the plot function in these.

    • @ATTIQIQBAL
      @ATTIQIQBAL  3 года назад

      What do you want to plot? Every value of root?

    • @ShankhaSaha
      @ShankhaSaha 3 года назад

      @@ATTIQIQBAL yeah! I would like to plot xi vs i

    • @ATTIQIQBAL
      @ATTIQIQBAL  3 года назад +2

      Ok inside the loop just add the following two lines after you find the root i.e. line number 10
      t(i) = i
      x(i) = x2
      And at the end of code just use plot(t,x)

    • @ShankhaSaha
      @ShankhaSaha 3 года назад

      @@ATTIQIQBAL Thank you so much bro! It worked man!!😊😊😊😊

  • @Nahidkabir38
    @Nahidkabir38 7 месяцев назад

    wrong equation

  • @sushanthkaruturi07
    @sushanthkaruturi07 2 года назад

    and also what is the failure criteria for this method? like; for newton raphson, if df(x0) == 0 , newton raphson failed

  • @idreesafridi6494
    @idreesafridi6494 3 года назад +1

    Great work. Keep it up brother

  • @milkesawedajo5979
    @milkesawedajo5979 Год назад

    ❤❤❤❤

  • @SunMcLob
    @SunMcLob 2 года назад +1

    This was a great video. Very informative and simplistic enough for me to understand! Thank you so much!

    • @ATTIQIQBAL
      @ATTIQIQBAL  2 года назад

      Thank you for your feedback

  • @Tigre-
    @Tigre- Год назад

    3:37

  • @gloriac8874
    @gloriac8874 2 года назад +2

    This could be the perfect video if only the english was a little bit more understandable for the non english ones 😭

    • @ATTIQIQBAL
      @ATTIQIQBAL  2 года назад +1

      I wish I would have made my initial videos in English. I'm more sad than you after reading this comment.

    • @gloriac8874
      @gloriac8874 2 года назад

      @@ATTIQIQBAL it's still really helpfull so thank you so much for your help and effort!!!

  • @Isabella-ce1gq
    @Isabella-ce1gq 8 месяцев назад

    this was such a slay.

  • @justinelancesalvajan1265
    @justinelancesalvajan1265 Год назад

    whats the tolerance means?

  • @crrsbabes6624
    @crrsbabes6624 3 года назад

    Could you please give us the code

  • @sandhya2848
    @sandhya2848 3 года назад +1

    I have seen many videos in you tube..sab kuch complex way me hein except your videos.thank u so much finally because of u I am understanding matlab well.❤️

    • @ATTIQIQBAL
      @ATTIQIQBAL  3 года назад

      Glad my content helped you

  • @sushanthkaruturi07
    @sushanthkaruturi07 2 года назад

    Bro! our faculty taught us a different formulae like x1 = x0 - f(x0)*dx/f(x0)-f(x0-dx). where x0 = initial value , dx is some step value like 0.01. when im coding this i got some errors. can you make a video using this formula.

  • @QAYEESIMRUL
    @QAYEESIMRUL 2 года назад

    Thanks

  • @jaztynjamescerro8325
    @jaztynjamescerro8325 3 года назад

    thank you boss

    • @antonioespina2
      @antonioespina2 3 года назад

      ulol

    • @jaztynjamescerro8325
      @jaztynjamescerro8325 3 года назад

      @@antonioespina2 pls no bad words here we are a good citizen

    • @antonioespina2
      @antonioespina2 3 года назад

      @@jaztynjamescerro8325 because you got a highest score in the whole world

  • @abhinandansingh2764
    @abhinandansingh2764 2 года назад

    Really great job sir

  • @AsimAli-nq9kf
    @AsimAli-nq9kf 2 года назад

    Well done sir I really appreciate you
    Keep it up

  • @sabamukhtar4598
    @sabamukhtar4598 2 года назад

  • @abdulhaseeb1195
    @abdulhaseeb1195 2 года назад

    Great job sir ❤

  • @muhammadryan4400
    @muhammadryan4400 2 года назад

    ok