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We feel proud of you Sir . Hat's off to you for bringing quality of material with 0 Rupees so that each one whether poor or rich can dream and achieve GATE,ESE,PSU Here we don't require any quota for learning . Welldone Sohail Sir . You are our Real gem I am sure in future all institute will follow roadmap No one can stop your institute to become No.1 Leading institute Free for GATE/ IES You are Man army for each of us. Keep it up sir.
sir i took coaching from a good coaching center..but i would like to say that everything has good better and best... i just will say one thing you are a symbol of excellence. Nothing to say about your teaching skill because i am following you from 3rd year.. you are my inspiration for shifiting my life from IT domain to GATE. I always wait for getting your new lecture... really you are right that noone can explain inverter till today. last year i faced problems from inverter when i started to give test series. This year i think inverter will be crystal clear for me....you are a brand name.. noone cannot remove.... and i respect to your thinking power....really you are GATE expert..... day by day you are researching for us....thank you sir...take my love and regards.... and sir i paid 100 rs to GATEMATIC education....because up kom jor student ka hat kavi nehi chorne wala..... bohut logo k upse sikhna hai porahate kaise.....
GATEMATIC Education U r doing very very good work for us(students)...i really apreciate it...At this stage i m just a student so its not possible for me to donate anything to your channel but i will make sure that one day(kuch banjaunga toh) i will donate a large amount to this channel...cz this channel (ofcourse you sohail sir) is used to help those students who dont have enough money to go to take classes from repotated tuations..thank you sir. your content is really good and i personally understand each and everything...(try to improve commutation 'D,B' lectures and effect of source inductance in rectifiers in case of 3phase). Answers. 1.(1) 2.(405.28watt) 3.(2*405.28 watt) 4.(500 watt) 5.(2*500 watt).
the way you explain previous problem is excellent. 1) fundamental D.F=1 2)fundamental each power Ps01=405.28w 3)fundamental load power P01= 810.56w 4)power drawn by each Ps=500w 5)Total load power Pt=1000w Thank you sir
Really very helpful to understand the concept and the subject as well ....The sum up and jist after end of the video make us to solve gate problem easily along with Better understanding of questions...Thank u sir😊😎 Your Network Videos are also Appreciable
Ans- fundamental displacement factor is 1, fundamental power drown= 810.54 watt,. Fundamental load power is equal to 810.54w,. Total power drown from each source is 1000 w,. Total load power is 1000w thank you very much for you briefly description , sir thank you
#doubt Sir,while solving 3 point you consider same waveform of load and switch but in all three waveform 2 waveform is load current wavefrom and by which get average and rms value is different from switch waveform??
Homework Ans. 1. Fundamental Displacement Factor=1 2. Fundamental Power Drawn from each source=405.2w 3. Fundamental load power=810.57w 4. Total load power drawn from each source=500w 5. Total load power=1000w
Sir I have a doubt you have said that to find out RMS value we have to square of that value and finally square root of that value But while finding the value RMS value of fundamental output voltage you have not squared the value or you have not taken the square root
sir is finding out fundamental power from source not wrong ?? bcz source contains only dc source and the source current has harmonics so if we try to calculate power from fundamental current and dc source it will come out to be zero bcz of orthogonality . please sir tell about it ?
Sir thank you so much for the video.But sir at 23:28 we found I(01 rms)=root(2)Vdc/(Pi)R from Fourier series formula.But while calculating fundamental rms switch current,it came out to be I(01max)/2 = 2Vdc/2(pi)R = Vdc/(pi)R. Will you please explain this a bit?
fundamental output rms current is I (01rms)= root (2)Vdc/(pi)R. This current will be present up to time period T. For that we follow the foruier series concept. But in case of fundamental rms switch current is present only from 0 toT/2. for that no need to do find fourier series concept ..that is out put of half wave rectifier ..so we can directly use that formula... And those both currents not equal because there is change in the time period.
At 29:46 how can u consider that formula sir.. because at load side output voltage and output current both are having Harmonics in it.. so whenever we get Harmonics in both vtg. and current then we have different formula to calculate power value.. That is; Power= (Vo*Io) + (Vo1*Io1*cos@1) + (Vo2*Io2*cos@2) + (Vo3*Io3*cos@3) +....... This is the exact formula if we have harmonics in both voltage and current.. we used to study in networks also the same thing.. how can u calculate in this way I really don't understand.. ok but fortunately here we got to use the formula given by u sir since we got proof here that power absored= power delivered.. so coincindentally it became correct but it's wrong representation na sir... sir please check once please reply please
Avg current= i peak÷2 =e dc ÷4 R Is this any formula ,if yes how did it come Sorry for asking if it's a basic question...but little confused abt this formula
thank alot sir...my answers are: 1.1 2.405.28watt 3.9.00watt 4.500w 5.1000 sir for 3rd one if i apply formulae i.e., po1=vo1rms2/r===root2vdc/pieR then i am getting 9wats,but by conclusion i am getting 810.56.plz helpme out sir
Hi sir can u give lectures on PE devices ..power MOSFET , GTO, etc .questions are asked from there every year 😢. Can you give me ur upid to contribute ?
If they ask AVG of source current in half bridge inverter then what we find as there are two sources, whether we find independently and give ans or anything else ???
Please explain clearly fundamental average value of switch current. Why the fundamental component of fourier series of switch current is discontinous(why not present in negative cycle)?
Sir why u hv taken fundamental power delivered by source as total dc source voltage nd avg source current why nt fundanental voltage of source ;in total dc source voltage all other harmonics are also there na including fundamental..
Isw(avg) = (1/T) {intg of Io* sinwt} with limits 0 to T/2...where T=(2pi/w).... replacing T with 2pi/w will give you answer as Io/pi.... because at the end they will cancel out...u can try
@@conandetective2331 but why 0 to T/2....I have represented the pulse wave into Fourier na? Why not 0 to T Usually sinusoidal have 0 avg so we take avg considering half wave for such....
✅ For GATE EE/ECE Courses at unbeatable price by Sohail Sir, Check out Neospark App: t.ly/qpDn
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22:28 something is wrong. we don't get the result, unless we put T=pi. Please explain this #gatematic education
@@samikpal5585 bro that is half wave average formula
Even Better than paid coaching! Thank you sir.
We feel proud of you Sir . Hat's off to you for bringing quality of material with 0 Rupees so that each one whether poor or rich can dream and achieve GATE,ESE,PSU
Here we don't require any quota for learning . Welldone Sohail Sir .
You are our Real gem
I am sure in future all institute will follow roadmap
No one can stop your institute to become No.1 Leading institute Free for GATE/ IES
You are Man army for each of us.
Keep it up sir.
Each and everything you teach is crystal clear
Sir i am really proud of you bcz your are giving free coaching for poor student one day your channel will be success.....
sir i took coaching from a good coaching center..but i would like to say that everything has good better and best... i just will say one thing you are a symbol of excellence. Nothing to say about your teaching skill because i am following you from 3rd year.. you are my inspiration for shifiting my life from IT domain to GATE. I always wait for getting your new lecture... really you are right that noone can explain inverter till today. last year i faced problems from inverter when i started to give test series. This year i think inverter will be crystal clear for me....you are a brand name.. noone cannot remove.... and i respect to your thinking power....really you are GATE expert..... day by day you are researching for us....thank you sir...take my love and regards.... and sir i paid 100 rs to GATEMATIC education....because up kom jor student ka hat kavi nehi chorne wala..... bohut logo k upse sikhna hai porahate kaise.....
ur most welcome..all the best for gate..
GATEMATIC Education
U r doing very very good work for us(students)...i really apreciate it...At this stage i m just a student so its not possible for me to donate anything to your channel but i will make sure that one day(kuch banjaunga toh) i will donate a large amount to this channel...cz this channel (ofcourse you sohail sir) is used to help those students who dont have enough money to go to take classes from repotated tuations..thank you sir. your content is really good and i personally understand each and everything...(try to improve commutation 'D,B' lectures and effect of source inductance in rectifiers in case of 3phase).
Answers.
1.(1)
2.(405.28watt)
3.(2*405.28 watt)
4.(500 watt)
5.(2*500 watt).
Thanks a lot sir for giving such root level concepts...Homework answer:-
1) 1
2) 405.28 W
3) 810.56 W
4) 500 W
5) 1000 W
correct
Thank u sir...
Also got same values
the way you explain previous problem is excellent.
1) fundamental D.F=1
2)fundamental each power Ps01=405.28w
3)fundamental load power P01= 810.56w
4)power drawn by each Ps=500w
5)Total load power Pt=1000w
Thank you sir
correct
Best lecture of inverter. Bilkul alag hi tarika h sir apke explanation ka.
Jazak Allah khair
Rashid Imam solve the homework and comment ur answer
Sir ur lectures are helping me alot thanku sir from Kashmir ❤️❤️❤️
Sir you are the best tutor of the world😎😎😎
Really very helpful to understand the concept and the subject as well ....The sum up and jist after end of the video make us to solve gate problem easily along with Better understanding of questions...Thank u sir😊😎
Your Network Videos are also Appreciable
sir you are great educator and concepts are very very clearly understable..
Thank u sir content is at d best . I gained confidence in PE which I used to face too much difficult.
sanketdkadam solve the homework and comment ur answer
GATEMATIC Education
Q1} FDF=1
Q2}Fundamental power drawn by each source=101.42W
Q3}Load power =202.84
Q4}total power delivered by each source =125 W
check out next lecture..its wrong..
thankyou sir!! for making us better in power electronics.
we are under standing vey welll ur explaing method is very goood dont change it
thanks alot
love from pakistan
Pakistan se pyar aa Raha he sir, aap esa hi kaam karte raho.....
Ans- fundamental displacement factor is 1, fundamental power drown= 810.54 watt,. Fundamental load power is equal to 810.54w,. Total power drown from each source is 1000 w,. Total load power is 1000w thank you very much for you briefly description , sir thank you
Ans 1 1
2 405.28watt
3 810.56watt
4 500watt
5 1kwatt
And last Sir thank you for this one
Sir please continue making videos, we students really need your help.. Kindly help us sir
1-1
2-405.28
3-810.569
4-500
5-1000
Thanku so much Sirji for such efforts 🙏
and what about ur dj channel ?
Ajit Nath Tiwari 🙏🙏🙏 tiwari ji dj hu n😂😂
Are neta ji hai
rai sahab...dj band khul jay ka
Ajit Nath Tiwari Mai bs bjata hu😂
Very useful vedio sir and your teaching style always effective.
Thank you soo much sir
after watching your videos my concepts about inverter is cleared very well
concept is clear by making solution of your HOMEWORK question
Too good sir
Really helpful
Thanks GATEMATIC
ur most welcome..all the best
Nice explanation sir
1:1
2:405.28w
3:810.56w
4:500w
5:1000w
correct
But unique style of tutorial.
Thanks sir ji
Thank you sir you changed my view of harmonics
it is interesting to watch rms and average values concept.
now the answer 1.1
2.405.28 watts
3.4.05 watts
4.500 watts
5.1000 watts
check the question no 3...u have to correct that..
sir, just a minor correction: when integrating with respect to "wt", limits will be from 0 radians to "pi" radians.
please watch my video also for this topic 🙏🙏
#doubt
Sir,while solving 3 point you consider same waveform of load and switch but in all three waveform 2 waveform is load current wavefrom and by which get average and rms value is different from switch waveform??
Ya....I got the same doubt...
Sir i think distortion factor will be 2 root 2 / (pi) ????
Homework Ans.
1. Fundamental Displacement Factor=1
2. Fundamental Power Drawn from each source=405.2w
3. Fundamental load power=810.57w
4. Total load power drawn from each source=500w
5. Total load power=1000w
Finally..... Thank u very very very much Sir
Love you sir thanks so much all lecture vvv helpful
Sir I have a doubt you have said that to find out RMS value we have to square of that value and finally square root of that value
But while finding the value RMS value of fundamental output voltage you have not squared the value or you have not taken the square root
Understand sir... Thank you so much sir.. and my answers are
1) 1
2) 405.28 W
3) 2*405.28=810.56 W
4) 500 W
5) 2*500=1000 W
correct
Best lecture of inverter.
Athrul israr solve the homework and comment ur answer
Sir it would very beneficial to us if u provide ur notes of these lectures
👍👍 really help me to clear my doubt
Expose News solve the homework and comment ur answer
Fantastic sirji 🙏
I understood very well... thank you sir
Great as always
Super explain sir g
Sahii me sir....Maja aa gaya
sir is finding out fundamental power from source not wrong ?? bcz source contains only dc source and the source current has harmonics so if we try to calculate power from fundamental current and dc source it will come out to be zero bcz of orthogonality . please sir tell about it ?
Sir thank you so much for the video.But sir at 23:28 we found I(01 rms)=root(2)Vdc/(Pi)R from Fourier series formula.But while calculating fundamental rms switch current,it came out to be I(01max)/2 = 2Vdc/2(pi)R = Vdc/(pi)R. Will you please explain this a bit?
fundamental output rms current is I (01rms)= root (2)Vdc/(pi)R. This current will be present up to time period T. For that we follow the foruier series concept. But in case of fundamental rms switch current is present only from 0 toT/2. for that no need to do find fourier series concept ..that is out put of half wave rectifier ..so we can directly use that formula... And those both currents not equal because there is change in the time period.
1)1
2)405.284
3)810.569
4)500
5)1000
Correct
wahh. just awesome content
Answers of Homework:
1. FDF =1
2.405.285 watts
3.810.57 watts
4.500 watts
5.1000 watts
thank you :)
1-unity
2-636.61watt
3-405.28 watt
4-500 watt
5-1000 watt
correct
Nice explanation
1. 1
2. 405.28watt
3. 810.569watt
4. 500watt
5. 1000watt
Thanq sir..
correct
Watching ur lectures made me feel power electronics is so easy. I dont know how to get fundamental average value of switch current i.e I01mmax/pi
Around 1 year i used to study gatematic channel... But no new videos upto now..... what happened to sohail ansari sir????
Great job
Nice explanation sir, thank u
Amiya Lenka solve the homework and comment ur answer
At 29:46 how can u consider that formula sir.. because at load side output voltage and output current both are having Harmonics in it.. so whenever we get Harmonics in both vtg. and current then we have different formula to calculate power value..
That is;
Power= (Vo*Io) + (Vo1*Io1*cos@1) + (Vo2*Io2*cos@2) + (Vo3*Io3*cos@3) +.......
This is the exact formula if we have harmonics in both voltage and current.. we used to study in networks also the same thing.. how can u calculate in this way I really don't understand.. ok but fortunately here we got to use the formula given by u sir since we got proof here that power absored= power delivered.. so coincindentally it became correct but it's wrong representation na sir... sir please check once please reply please
I have a question: why are two symmetrical voltage sources used?
1. dpf is 1
2.101.3
3.202.64
4.125
5.250
Great sir
Avg current= i peak÷2 =e dc ÷4 R
Is this any formula ,if yes how did it come
Sorry for asking if it's a basic question...but little confused abt this formula
Thanks sir very usefulll
Homework answer
1. One
2. 405.17 watt
3. 810.569 watt
4. 500 watt
5. 1000 watt
correct.
Hello sir I have a question. Can I ask?
1. Unity
2. 405.285 W
3. 810.569 W
4. 500 W
5. 1000 W
1)1
2)405.28W
3)810.56W
4)500W
5)1000W
thank alot sir...my answers are: 1.1
2.405.28watt
3.9.00watt
4.500w
5.1000
sir for 3rd one if i apply formulae i.e., po1=vo1rms2/r===root2vdc/pieR then i am getting 9wats,but by conclusion i am getting 810.56.plz helpme out sir
Hi sir can u give lectures on PE devices ..power MOSFET , GTO, etc .questions are asked from there every year 😢.
Can you give me ur upid to contribute ?
#doubt
During Fundamental power delivered by each source why did you took switch current why not load current though till T/2 both has the same value
Super Sir!
If they ask AVG of source current in half bridge inverter then what we find as there are two sources, whether we find independently and give ans or anything else ???
great sir
nice video sir
Sir, does output power factor of inverter exist? ,Just like input power factor for rectifiers. If it exists how to find it? Please explain me.
find it by taking cos between angle of output voltage and current
Can you put a summary of all the important equations derived at the end of the lecture?
sir can you provide vedios on cycloconverter or AC chopper modelling analysis
sir thank you very much
thiru malai solve the homework and comment ur answer
1) 1
2) 405.28 Watt
3) 810.569 Watt
4) 500 Watt
5) 1000 Watt
1. FDF =1
2. 405.283W
3. 810.56W
4.500W
5.1000W
Please explain clearly fundamental average value of switch current. Why the fundamental component of fourier series of switch current is discontinous(why not present in negative cycle)?
I think this concept is being taught wrong
if you do a fourier series of the switch current and then take the rms value ofthe fundamental you get a different answer
1)1
2)405.28w
3)810.5w
4)500w
5)1000w
Correct..keep going..all the best
Sir why u hv taken fundamental power delivered by source as total dc source voltage nd avg source current why nt fundanental voltage of source ;in total dc source voltage all other harmonics are also there na including fundamental..
Thank you sir ji
1-1
2-405.69
3-811
4-500
5-1000
thanks for home work questions, sir keep giving
1)1
2)405.28
3)810.56
4)500
5)1000
1. 1
2. 405.284w
3. 810.56w
4. 500w
5. 1000w
Sir is multiphase conveter video is enough for that topic
Ranjan Keshri solve the homework and comment ur answer
Sir, In obtaining Switch current RMS and average... We considered time period as T but not pie. So doesnt that change the RMS value expression..?
Isw(avg) = (1/T) {intg of Io* sinwt} with limits 0 to T/2...where T=(2pi/w).... replacing T with 2pi/w will give you answer as Io/pi.... because at the end they will cancel out...u can try
@@conandetective2331 thanks
@@conandetective2331 but why 0 to T/2....I have represented the pulse wave into Fourier na? Why not 0 to T
Usually sinusoidal have 0 avg so we take avg considering half wave for such....
1) 1
2) 405.28 watts
3) 811.39 watts
4) 1000 watts
5) 1000 watts
Splendid
1.)1
2.)405.28W
3.)810.56W
4.) 1000 W
5.) 500 W
1- 1
2- 405.69
3- 811.39 W
4- 500 W
5- 1000 W
correct
1.1
2.405.28 w
3.810.56 w
4.500 w
5.1000 w
sir for switch current rms you took load current fundamental rms instead if considering switch current square wave form
and again applying forier
Its correct
it is wrong . i support srinu kanithi
@@cvmanjunath3682 I too
1--->1
2---->405.69
3--->811.39
4---->500
5---->1000
How to find input power factor of half bridge inverter?
1. Fdf=1
2. 405
3. 810
4. 500
5. 1000
correct
sir,
why is switch current and source current same
i(source)=i(switch1)+i(switch2)
is this not the case?
please explain.
It cannot be the sum of two right?... because they are working in complementary fashion?