for 4.5 the y-value of A = -2, bcs its on the same line as p & c, then i just put -2 into y=2x-2 to get the x value of A, which also gave me 0 for the gradient of AC
4.5, they say APC is a diameter so A,P,C have the same Y coordinate which is -2 then you substitute -2 in their equation y=2x-4 and y=-half x - 7over2 to get your respective answers
My principal once said "If you are able to draw a perfect circle without any equipment , you are crazy." 🤪So Kevin it is normal not to be able to draw perfect circle.
4.5 after getting the co-ordinate of of C you simply see that point A and C share the same y co-ordinate value then just substitute the y value into the equation of the striaght line to get the x value then find the gradient ❤
I used the converse midpoint to prove that S is the midpoint of AB and then use that fact to show that SR//AC using direct midpoint, did yal'l do the same thing?
In your first video of "equation of the circle" you said that when you want a radius you calculate the length then after calculating the length in order to find the the radius from the length you have to divide the length by 2 to get the raduis
in 4.5 we could have used the fact that a line drawn from the center of a circle to the chord bisects the chord which mean we could have done what we did to find C to find A
11:21 Hi kevin, i was wondering if wether you could prove that the two lines are parallel by using angles of inclination? By finding the corresponding angles.
Kevin in 4.5 would they allow me to use euclidean geometry laws and say that AbC is 90 degrees and AsB is 90 degrees line from center to midpoint of chord AB,and then conclude by saying that they are parallel converse corresponding angles
Kevin,is it wrong to assume that line BC intersects the circle with centre R?and then substitute the eq. of BC on the circle with centre R to find coordinates of C cause I also got 11 as the x coordinate and -2 as the y-coordinate
For 4.5, I used the same reverse midpoint method to get A. Since the first question was the coordinates of P, I used P and C coordinates to get A with the same method, and I got the same answer. Is it wrong if I do it like that?
kevin i first got gradient of SR for the question 4.5 then i did midpoint reverse formula to get A co ordinate cause i solved ahead of time for C then i got gradient of AC is that a reliable way or is it better to do your way for future questions
Hi Kevin, how i worked out the co-ordinates of A&C was by using inspection, i took the radius of the circle and calculated the shift between the centre and A which i minused 5 and plused 5 for C, I still ended up with the correct co-ordinate values. My question is: will I be penalised if I don't show how the working out I got my co-ordinates but I state the use of inspection using the radius.
Sir for 4.4 after getting the distance of BR aren't we suppose to double the distance so it can be equal to the distance of BC ....and the equation of the circle would be ( x-7)²+y²=80😢😢😢 6:49
for 4.5 the y-value of A = -2, bcs its on the same line as p & c, then i just put -2 into y=2x-2 to get the x value of A, which also gave me 0 for the gradient of AC
4.5 after finding the coordinates of c, you could've simply found the gradient of pc by using p, we know that Mpc=Mac since its a str line
😅I did the same and I was terrified that I must have done something wrong when I saw sir not doing it like that
The fact that we're all learning this the day before finals💀
4.5, they say APC is a diameter so A,P,C have the same Y coordinate which is -2 then you substitute -2 in their equation y=2x-4 and y=-half x - 7over2 to get your respective answers
That's brilliant 🎉
For 4.5 i just did the midpoint formula in reverse again for AC and then worked out their gradients to 0
My principal once said "If you are able to draw a perfect circle without any equipment , you are crazy." 🤪So Kevin it is normal not to be able to draw perfect circle.
4.5 after getting the co-ordinate of of C you simply see that point A and C share the same y co-ordinate value then just substitute the y value into the equation of the striaght line to get the x value then find the gradient ❤
Sir,for 4.5 I used the midpoint formula in reverse using the co-ordinates of B and S to get the co-ordinates of A and I got the same answer
I did the same thing
Same here
Same 🥺🙆🔥🔥🔥🔥
I used the converse midpoint to prove that S is the midpoint of AB and then use that fact to show that SR//AC using direct midpoint, did yal'l do the same thing?
In your first video of "equation of the circle" you said that when you want a radius you calculate the length then after calculating the length in order to find the the radius from the length you have to divide the length by 2 to get the raduis
in 4.5 we could have used the fact that a line drawn from the center of a circle to the chord bisects the chord which mean we could have done what we did to find C to find A
sir, we could’ve used midpoint S to find A as well because PS is a line drawn from the centre to the chord BA therefore it bisects the chord 10:32
11:21 Hi kevin, i was wondering if wether you could prove that the two lines are parallel by using angles of inclination? By finding the corresponding angles.
Kevin in 4.5 would they allow me to use euclidean geometry laws and say that AbC is 90 degrees and AsB is 90 degrees line from center to midpoint of chord AB,and then conclude by saying that they are parallel converse corresponding angles
Kevin,is it wrong to assume that line BC intersects the circle with centre R?and then substitute the eq. of BC on the circle with centre R to find coordinates of C cause I also got 11 as the x coordinate and -2 as the y-coordinate
no doing that is fine
For 4.5, I used the same reverse midpoint method to get A. Since the first question was the coordinates of P, I used P and C coordinates to get A with the same method, and I got the same answer. Is it wrong if I do it like that?
Correct, also did that
kevin i first got gradient of SR for the question 4.5 then i did midpoint reverse formula to get A co ordinate cause i solved ahead of time for C then i got gradient of AC is that a reliable way or is it better to do your way for future questions
Hi Kevin, how i worked out the co-ordinates of A&C was by using inspection, i took the radius of the circle and calculated the shift between the centre and A which i minused 5 and plused 5 for C, I still ended up with the correct co-ordinate values. My question is: will I be penalised if I don't show how the working out I got my co-ordinates but I state the use of inspection using the radius.
I realized that A P and C are on the same line which means they share the same y-intercept
Sir for 4.4 after getting the distance of BR aren't we suppose to double the distance so it can be equal to the distance of BC ....and the equation of the circle would be ( x-7)²+y²=80😢😢😢 6:49
😊😊 Thanks ❤❤
Who is Inga
thats what i was wondering 🤣🤣🤣
🎉 thanks 🙏
Sir is it wrong if I do this:
BSR=tan-1(2)=63,43
BAP=tan-1(2)=63,43
Therefore AC//SR Corresp.
Today sir literally to use all the long ways