I've been struggling with this for two weeks. I read my textbook over and over, read my professor's notes over and over, still no dice. Then I watched your video and got it in 5 minutes. Thank you for uploading such a useful resource.
Hey there Mr. Hren!! One sorrowful day, I got a packet of Specific Heat. While the lesson was being taught, I listened but was staring at my friend in front of me. My teacher assigned us this packet, and off we went. Later, I realized that I literally had no IDEA of what to do. Khanacademy, was hard to understand so I watched this. You really helped me and my grades. Thanks a lot!! :-)
i’m taking chem hn rn, and everyone learns the lessons faster than me, and my teacher doesn’t explain it thoroughly. I watched this, and picked it up faster than his 40 minute lesson. wheeeew, that’s saying something.
This just shows me that teaching isnt for everyone. You made it so easy. I cannot understand a thing when my professor explains it. Maybe in college the professors just forget they need to take it step by step first.
you really helped me understand this topic where my 15th edition $120 textbook could not. the school textbook system is warped. i cant learn my homework by reading alone. i need visual observation to see it as it goes.
i have to write a lab report on Specific Heat of Al. I need help with answering questions like the purpose of the expierment and the limitations/ expiermental error.? can you help me please.??
I found this question and couldn't answer it. Could you give it a shot? Thank you! Two identical systems, with heat capacity at constant volume that varies as Cv=bT^3 (where b is a constant) are thermally isolated. Initially, one system is at a temperature 100K and the other is at 200K. The systems are then brought into thermal contact and the combined system is allowed to reach thermal equilibrium. What will be the final temperature of the combined system?
How many grams of water would require 2.20 x 10^4 calories of heat to raise its temperature from 34.0 oC to 100.0 oC? (Remember the specific heat of water is 1.00 cal/g x oC) WHAT DO I DO HERE SINCE WE HAVE 2.20 X 10 ^4
Is there a difference in how you solve this equation and when you use two substances with specific weight measurements and the heat capacity of the other substance is given? I have a question about sand being mixed with water. The water has it's measurements and heat capacity given. My question is can I solve this problem and ignore the values of the water given?
What if c is missing so the solution and formula/conversion will be divided bcs if q is missing we use triangle method to answer for ula and solution but urs is always divide
Hi,I need to calculate the temperature and pressure drop of the gas flowing in a pipe.I have following inputs - inlet flow rate, inlet temperature and pressure, properties of pipe and insulation surrounding it.Can you guide how I can calculate it?
please help with this question... When 1.5 * 10 ^3J of heat energy is absorbed by a beaker of water, its temperature rises by 3.1 degrees celcius. What is the heat capacity of the beaker?
If the iron metal is cooled from 456 to 22, does that not mean that 456 is the initial temperature and that the is the final? I'm, just curious because that does not seem right when I read it.
I'm having trouble with this one. Some help would be awesome! The Specific Heat of a substance is the energy (Joules) required to raise one gram of substance by one degree celsius, (units J/goC). Heating 115 cm3 of a solid from 35.05 oC to 75.35 oC takes 13750 J of energy. The density of the solid at 35.05 oC is 2.7 g/cm3. What is the Specific Heat of the solid in this experiment?
The only thing that's not straight forward is how to calculate the mass. However since they've given you both density and volume of the substance it shouldn't be hard enough to plug them into the formula d=m/v which you should rearrange to get m=d(v). After finding the mass simply plug the numbers you've got into the formula E=mc(change in temp.) That's about it! :D Although you're getting help after a year! 😂 hope this helps!
calculate the heat of 15.2g of substance that required 362.7 calories of heat raise its temperature from -19 degrees C to 27 degrees C? how would i do this problem?
What is moles gets involved Aluminum metal has a specific heat of 0.900 J/g•degrees C. Calculate the amnt of heat required to raise the temp. Of 10.5 moles of Al from 30.5degrees C to 225degrees C Please help
+RaeAnna Cardenas I think you just need to convert the moles of Al into grams. Just multiply 10.5 mods Al by 1 mole and divide by the molar mass of Al. Then use that number as your mass. I hope this answers your question, and I hope I'm right! (I'm in AP chem in year 11)
How do you calculate the joules of heat applied before knowing what the specific heat of the object is? Just give me the formula and explain it please. EX: Things given: Object: Mountain Dew Mass: 0.50 LB Change in temperature: 50*C to 49*C Specific heat=? Joules of heat applied=?
Calculate the specific heat (J/g∘C) for a 25.0 g sample of a metal that absorbs 641 J when temperature increases from 41.2 ∘C to80.1 ∘C. I've tried to plug everything as you did and divide and my answer is still incorrect. I'm having an issue. I just don't understand specific heat.
Specific heat (C) = Heat added x 1/mass x 1/temp. change Substituting the values, we get: C = 641 x 1/25 x 1/(80.1 - 41.2) C = 641 x 1/25 x 1/38.9 C = 6.59 x 10^-1 J/(g x deg. C)
Bailey W Suppose im a wee bit late, but when calculating the change in temperature, as long as the unit stays consistent, it makes no difference. Coincidentally explained later in the video, the difference between -45 degrees celsius and 15 degrees celsius amounts to a change in temperature of 60 degrees celsius. The same answer applies for -15 to 45 degrees celsius. Thus why kelvin is very easy to work with. Hopefully this helps clear up misunderstandings from reading the above comment, which is the sole purpose of this reply.
I've been struggling with this for two weeks. I read my textbook over and over, read my professor's notes over and over, still no dice. Then I watched your video and got it in 5 minutes. Thank you for uploading such a useful resource.
same here !
Well I wish my proffesor talked like you , he makes it so complicated and didn't understand until watching you 😇🙌
Hey there Mr. Hren!!
One sorrowful day, I got a packet of Specific Heat. While the lesson was being taught, I listened but was staring at my friend in front of me. My teacher assigned us this packet, and off we went. Later, I realized that I literally had no IDEA of what to do. Khanacademy, was hard to understand so I watched this. You really helped me and my grades. Thanks a lot!! :-)
i always come back here when i need help, thank you so so so much!
So glad I found your page! Saving my chemistry grade. Thanks dude!
seeing your video with `4 minutes of pen and paper exercise problems gave me a tender inner warmth, that I will be ok. Thank you for this!
i’m taking chem hn rn, and everyone learns the lessons faster than me, and my teacher doesn’t explain it thoroughly. I watched this, and picked it up faster than his 40 minute lesson. wheeeew, that’s saying something.
I love the way you write the meaning of each one out on top.. it helps.. especially for someone like me who is a visual learner. =) Thank you!
Temperature change is T(final)-T(initial)
He was suppose to get negative numbers on the first and last problem
exactlyyyyy!!
i was thinking the exact same thing this is not a good chem teacher
How can heat be negative
@@fishers27mankid38 thats called exothermic reaction (realese heat) thats why its minus
@@Maorsol thanks
I am in Physics and I found this completely helpful! Thank you so much!:)
Thanks you just saved my Chem grade
Dan koch this is physics
This just shows me that teaching isnt for everyone. You made it so easy. I cannot understand a thing when my professor explains it. Maybe in college the professors just forget they need to take it step by step first.
Taught better than 99% of online school teachers
you really helped me understand this topic where my 15th edition $120 textbook could not. the school textbook system is warped. i cant learn my homework by reading alone. i need visual observation to see it as it goes.
Thank you!! You helped me out so much more than my book does!
AMAZING . I LOVED THE STEPS. GREAT JOB SIR!
what happened to the Sig Figs??
Gone. Reduced to atoms.
Thank you so much love from India
you have saved my grade on an upcoming chemistry test
Good explanations. I would think isolating c without numbers first might be easier for your students to do the math part.
Thank you so much for this video! I love how you teach and how simple you make it. god bless
i love this video
Thank you so much for this
Nice explanation sir.
i think i love you mr hren this helped me so much!
Thank you so much!!😭
i have to write a lab report on Specific Heat of Al. I need help with answering questions like the purpose of the expierment and the limitations/ expiermental error.? can you help me please.??
-ve sign is use in 1st problem because temp. 22 -456 and it is also exothermic process.
Thank you very much for this video,it really helped me too
This was so helpful! Thanks
I OWE YOU, THANK YOU
You just save my life!!
Thanks for your help
Thank You so much Your the best!!!!!!!!!!!!
I found this question and couldn't answer it. Could you give it a shot? Thank you!
Two identical systems, with heat capacity at constant volume that varies as Cv=bT^3 (where b is a constant) are thermally isolated. Initially, one system is at a temperature 100K and the other is at 200K. The systems are then brought into thermal contact and the combined system is allowed to reach thermal equilibrium. What will be the final temperature of the combined system?
Delta T is 22- 456.
yes but its always absolute value of the numbers. lol this was 6 months ago but still
we want more videos about Heat transfer :)))
thank you🙏
which of the following (with specific heat capacity provided)would show the smallest temperature change upon gaining 200.0 j of heat?
How many grams of water would require 2.20 x 10^4 calories of heat to raise its temperature from 34.0 oC to 100.0 oC? (Remember the specific heat of water is 1.00 cal/g x oC)
WHAT DO I DO HERE SINCE WE HAVE 2.20 X 10 ^4
Is there a difference in how you solve this equation and when you use two substances with specific weight measurements and the heat capacity of the other substance is given? I have a question about sand being mixed with water. The water has it's measurements and heat capacity given. My question is can I solve this problem and ignore the values of the water given?
What if c is missing so the solution and formula/conversion will be divided bcs if q is missing we use triangle method to answer for ula and solution but urs is always divide
Hi,I need to calculate the temperature and pressure drop of the gas flowing in a pipe.I have following inputs - inlet flow rate, inlet temperature and pressure, properties of pipe and insulation surrounding it.Can you guide how I can calculate it?
Our method is kinda diff bcs were not in same country?
you just helped me soooo much!
How do you find the temperature if it is not given in the problem? Thank you.
Thank you much!!!
Thank you.
please help with this question... When 1.5 * 10 ^3J of heat energy is absorbed by a beaker of water, its temperature rises by 3.1 degrees celcius. What is the heat capacity of the beaker?
If the iron metal is cooled from 456 to 22, does that not mean that 456 is the initial temperature and that the is the final? I'm, just curious because that does not seem right when I read it.
yes it should be.
Calculate the number of kilojoules to warm 125 g of iron from 23.5 to 78.0 degrees Celsius. how do i plugg these numbers into the formula
so if piece of that Al is given in grams we convert it to kilograms or convert its specific heat to grams??
could you post a video about converting grams and kg to kg or grams over mols?
Does it make any difference if the unit of specific heat is in Kelvin?
Sir plz answer this question with explanation- Specific heat of an element is 0.1. The nearest atomic weight of that element will be.....
How to solve for cooling at -5 °C
I'm having trouble with this one. Some help would be awesome!
The Specific Heat of a substance is the energy (Joules) required to raise one gram of substance by one degree celsius, (units J/goC).
Heating 115 cm3 of a solid from 35.05 oC to 75.35 oC takes 13750 J of energy. The density of the solid at 35.05 oC is 2.7 g/cm3.
What is the Specific Heat of the solid in this experiment?
The only thing that's not straight forward is how to calculate the mass. However since they've given you both density and volume of the substance it shouldn't be hard enough to plug them into the formula d=m/v which you should rearrange to get m=d(v). After finding the mass simply plug the numbers you've got into the formula E=mc(change in temp.)
That's about it! :D
Although you're getting help after a year! 😂 hope this helps!
+Susan Crasto
where were you when I needed you 😂
calculate the heat of 15.2g of substance that required 362.7 calories of heat raise its temperature from -19 degrees C to 27 degrees C? how would i do this problem?
For Delta T, isnt it supposed to be (Temperature Final - Temperature Initial) . So (22°C - 456°C)
Im really confused with this topic on my CHM lab
thats what i thought; in which case it would be a negative value
Wait how did you get 2500?
Nevermind i got it. Thanks
+poop butt how did he get 2500? please help me
hi I really need help with a problem, and I have no clue how to do it. Please help??
Awesome vid thx!
Glad it helped. Thanks!
It said decrease from 45 to 40 wouldnt it be -5?
What is moles gets involved
Aluminum metal has a specific heat of 0.900 J/g•degrees C. Calculate the amnt of heat required to raise the temp. Of 10.5 moles of Al from 30.5degrees C to 225degrees C
Please help
+RaeAnna Cardenas I think you just need to convert the moles of Al into grams. Just multiply 10.5 mods Al by 1 mole and divide by the molar mass of Al. Then use that number as your mass. I hope this answers your question, and I hope I'm right! (I'm in AP chem in year 11)
Question, At 5:20 why did he write his final answer as Q = 1.25x10^5J How did he make 125368.02J into that? Can someone help
Derek DarkHeart pretty sure he just rounded
How do you calculate the joules of heat applied before knowing what the specific heat of the object is? Just give me the formula and explain it please.
EX: Things given:
Object: Mountain Dew
Mass: 0.50 LB
Change in temperature: 50*C to 49*C
Specific heat=?
Joules of heat applied=?
Damn 6 years ago
so theres basically two formulas that you use?im really confused ik how to but idunno like what formulas to use it gets me confused
I formula q=t*c*m u use this formula to rearrange ur equation to find m,c or t
Calculate the specific heat (J/g∘C) for a 25.0 g sample of a metal that absorbs 641 J when temperature increases from 41.2 ∘C to80.1 ∘C.
I've tried to plug everything as you did and divide and my answer is still incorrect. I'm having an issue. I just don't understand specific heat.
You have mass, energy and temp change. You need to solve for the heat capacity
Specific heat (C) = Heat added x 1/mass x 1/temp. change
Substituting the values, we get:
C = 641 x 1/25 x 1/(80.1 - 41.2)
C = 641 x 1/25 x 1/38.9
C = 6.59 x 10^-1 J/(g x deg. C)
Final heat - starting heat
sir how can i calculate the specific heat of biscuit ? plz do reply sir, as it was asked by my boss, i work in biscuit manufacturing company
My suggestion. Eat the biscuit, if it is that kind of biscuit. If not, use a calorimeter.
You are cool
Yeah
we do this in physics in ireland??
Laura Rahill Yes sometimes it is covered in physics here as well. Just depends on the curriculum.
Hi mr hren can you clear my doubts
I love you
have you ever done a problem where you insert liquid into a hot pot and find the change of heat in the pot?
9:41
how are you doing today
what does j represent?
+Emmanuel Delarosa J represents joules.
Hiiiiiiiiii :3
haiiiiiiiii :3
its asking for energy so obviously it's going to be J
He did it wrong. It's Tf-Ti which gives you a negative number
For #1, it should be negative. This is because Delta T is Final Temp - Initial Temp, you did Initial Temp - Final Temp
Bailey W Suppose im a wee bit late, but when calculating the change in temperature, as long as the unit stays consistent, it makes no difference. Coincidentally explained later in the video, the difference between -45 degrees celsius and 15 degrees celsius amounts to a change in temperature of 60 degrees celsius. The same answer applies for -15 to 45 degrees celsius. Thus why kelvin is very easy to work with.
Hopefully this helps clear up misunderstandings from reading the above comment, which is the sole purpose of this reply.
I'm 10th grade but it not like dis
POV ur chemistry teacher can’t teach
u dont have to put the units in the equation...
My teacher is 70 and talks like joe biden
Thank you much!!!