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[@arturdietrich]

Nice!

[@superacademy247]

Thanks for the kind words! 😊Glad you enjoyed it! 🤩

[@thomasgreene5750]

Another, quicker way of getting to the solution is to use Euler's Identity, exp(ix)=cosx+i*sinx, to write 8i as 8*exp(i*pi/2) and k=(+/-)2sqrt(2)*exp(i*pi/4) = (+/-)2sqrt(2)*[sqrt(2)/2+i*sqrt(2)/2]. Simplifying, k = (+/-)2*(1+i).

[@superacademy247]

Thanks for sharing your method!That's a powerful approach. 🤩💪

[@bigjazbo9217]

I think neither a or b can be imaginary. This is because when you equated the real and imaginary parts of k2 = 8i, with k = a + bi, you are assuming a and b to be real. If a and b are allowed to be i.aginary or complex, you cannot equate real and imaginary parts.

[@sonicbreaker00]

you so called teachers need to learn math first before you make these videos. what takes 2 lines with polar form took you an entire notebook !

[@superacademy247]

I appreciate you taking the time to share your perspective. 🤩 It's a great idea to try different methods for solving problems. 💪

[@sonicbreaker00]

@@superacademy247 what do you get out of these videos that you make ?

[@superacademy247]

I help thousands of learners from around the world on how to solve Math problems. I've improved Math skills 😍 of many students across the globe.💡💡💡👏👏👏

[@cazacumihail3671]

@@superacademy247, yet a , b must be real !! Learn more about complex numbers