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Thank you sir. It is very useful for exam. Please put more videos sir.
Yes sir u teach really niceee share link of ur previous videos
So here's the timestack1:19 - - >Question3:00 - - >TMOD config(Step1) 6:22--> Steps to solve problem8:48 - - >Step 2(load initial value) )Oh fuck this!
Great lecture sir. Thanks for sharing
Nice explanation...make more video for embedded systems
sir you teach very nice.. but please improve the audio quality. your efforts are highly appreciated.
can I get link of your previous lectures! thanks
Very nice video sir.Thank you so much.
No clear sound
Thk u sir
very good explaination thanks.
Thank you so much sirNice explanation
Nice put more videos
What to do when we get number of count as 6666.666
thank u very much sir...it was really helpful
thankyou very much sir,really helpful
why we always divide the crystal frequency by 12 ?
every machine cycle contain 12 cycle
Thank you sir👌
Thank you sir🖤
Thank U sir
thank you sir
Thanks
Audio is not up-to the mark...
Sir me explian kro na
Thank you sir. It is very useful for exam. Please put more videos sir.
Yes sir u teach really niceee share link of ur previous videos
So here's the timestack
1:19 - - >Question
3:00 - - >TMOD config(Step1)
6:22--> Steps to solve problem
8:48 - - >Step 2(load initial value) )
Oh fuck this!
Great lecture sir. Thanks for sharing
Nice explanation...make more video for embedded systems
sir you teach very nice.. but please improve the audio quality. your efforts are highly appreciated.
can I get link of your previous lectures! thanks
Very nice video sir.Thank you so much.
No clear sound
Thk u sir
very good explaination thanks.
Thank you so much sir
Nice explanation
Nice put more videos
What to do when we get number of count as 6666.666
thank u very much sir...it was really helpful
thankyou very much sir,really helpful
why we always divide the crystal frequency by 12 ?
every machine cycle contain 12 cycle
Thank you sir👌
Thank you sir🖤
Thank U sir
thank you sir
Thanks
Audio is not up-to the mark...
Sir me explian kro na