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SFD is drawn wrong. As joint A will have the upward reaction which will resist the UDL load so you will have the diagram in the +ve direction.
Thanks bro❤
Yes bro u right ….how these teachers have audacity to upload videos without proper knowledge
SFD should be in positive,? Its just a doubt
yup he made a mistake I guess
Yes
Yes SFD will be positive
Yes,SFD should be positive
Yes sfd should be positive
What happen when we take x from fixed end?
When SF is minimum then BM must be maximum and vice versa right ? So how could both of them be zero at end ?
SF is nothing but slope of BM so if BM=0; SF =0. U confuse with point of contraflexure which is valid only for point loads. But in case of UDL and UVL it is not true.Correct me if I am wrong...
The Point where BM is maximum SF must be '0' but this is not valid when there is a presence of concentrated moments on the beam.
Sir please tell me.. The bending moment along the length of a Cantilever beam with uniformly distributed load varies non linearly or linearly??
It's parabolic as the equation of of bending moment has x^2
Hi mehak gupta ji
How are you
For udl, load is 300kg and length is 2800mm then what is bending moment with units ..i am confusion.. please help me
Why we use section for calculation?
sir.........there is a problem in S F D
SFD DIAGRAM WRONG HAY 😂😂😂WAAH GURUJI MAAN GAYE 🙇🙇
SFD should be positive sir
dont draw shear force below bending moment misleading>>>>>>>>>>>>>>>>>
Wrong SFD
Sir galat padha diye☝️🤗
Tuje SFD banana hi nhi aata kya smjha rha h
SF +
Galat h SF dia..
Galat hai ye
🙄🙄🙄
Watch more Videos on Strength of Materials Here: ruclips.net/p/PLWPirh4EWFpHse06JObGNlWpSNpsKGpoC&si=08uZAAPXm-YKtgO3
SFD is drawn wrong. As joint A will have the upward reaction which will resist the UDL load so you will have the diagram in the +ve direction.
Thanks bro❤
Yes bro u right ….how these teachers have audacity to upload videos without proper knowledge
SFD should be in positive,? Its just a doubt
yup he made a mistake I guess
Yes
Yes SFD will be positive
Yes,SFD should be positive
Yes sfd should be positive
What happen when we take x from fixed end?
When SF is minimum then BM must be maximum and vice versa right ? So how could both of them be zero at end ?
SF is nothing but slope of BM so if BM=0; SF =0. U confuse with point of contraflexure which is valid only for point loads. But in case of UDL and UVL it is not true.
Correct me if I am wrong...
The Point where BM is maximum SF must be '0' but this is not valid when there is a presence of concentrated moments on the beam.
Sir please tell me..
The bending moment along the length of a Cantilever beam with uniformly distributed load varies non linearly or linearly??
It's parabolic as the equation of of bending moment has x^2
Hi mehak gupta ji
How are you
For udl, load is 300kg and length is 2800mm then what is bending moment with units ..i am confusion.. please help me
Why we use section for calculation?
sir.........
there is a problem in S F D
SFD DIAGRAM WRONG HAY 😂😂😂
WAAH GURUJI MAAN GAYE 🙇🙇
SFD should be positive sir
dont draw shear force below bending moment misleading>>>>>>>>>>>>>>>>>
Wrong SFD
Sir galat padha diye☝️🤗
Tuje SFD banana hi nhi aata kya smjha rha h
SF +
Galat h SF dia..
Galat hai ye
🙄🙄🙄