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Great and easiest explanation... Thanks bro. Pls upload more videos on SFD and BMD problem solving
Thank you so much for the clear explanation!
Glad it was helpful!
Thank you for the detailed explanation
You are welcome!
Sir how to get x value 3.57
Sister u clarify how to get x value 3.67
Sry 3.57
Much appreciated your explanation❤
Great video, have being trying to understand udl and your video helped me a lot, much love from Kenya 🇰🇪
Could you clarify how length x=3.57 become force at maximum point E?
Same question
Look back 10 Standard Maths Similarity of Triangles
how did you get Rb value 5.86kn
41/7
@@mahendratripura800I think moment=(8*4*(4/2))+(5*5)-(Rb*7) = Rb = 12.71 kn
Sorry sir, SFdr for SF diagram should be - 4.14 or - 5.86?
你超猛的,聽不懂你的語言我卻看得懂整個分布圖,
Thank you so much
Non uniformly Kaha milega sir
Great Teaching
while taking moment at E its length is 3.57, doesnt the point load 8 kN will be counted as Moment at E = 7.14*3.57-2*3.57²/2-8*1.57 ??
Bro 8 KN is UDL and 3.57 is also udl but 3.57 is part of 8 hence we will neglect it because we Have created Individual Udl of that
Perfect method. Thank you.
You're welcome!
Can you also do for moving loads, and triangular loads example? Thank you.
your the goat
Sir when you find out moment of udl that time 8×4×(4÷2) +5×5=Rb×6 hona chahiye
Right
Hlo any one tell me how to get 3.57 answer
There's something wrong here
Is that you talking about hinge support?
How Rb =5.86kn
💩
Great and easiest explanation... Thanks bro. Pls upload more videos on SFD and BMD problem solving
Thank you so much for the clear explanation!
Glad it was helpful!
Thank you for the detailed explanation
You are welcome!
Sir how to get x value 3.57
Sister u clarify how to get x value 3.67
Sry 3.57
Much appreciated your explanation❤
Great video, have being trying to understand udl and your video helped me a lot, much love from Kenya 🇰🇪
Could you clarify how length x=3.57 become force at maximum point E?
Same question
Look back 10 Standard Maths Similarity of Triangles
how did you get Rb value 5.86kn
41/7
@@mahendratripura800I think moment=(8*4*(4/2))+(5*5)-(Rb*7) = Rb = 12.71 kn
Sorry sir, SFdr for SF diagram should be - 4.14 or - 5.86?
你超猛的,聽不懂你的語言我卻看得懂整個分布圖,
Thank you so much
Non uniformly Kaha milega sir
Great Teaching
while taking moment at E its length is 3.57, doesnt the point load 8 kN will be counted as Moment at E = 7.14*3.57-2*3.57²/2-8*1.57 ??
Bro 8 KN is UDL and 3.57 is also udl but 3.57 is part of 8 hence we will neglect it because we Have created Individual Udl of that
Perfect method. Thank you.
You're welcome!
Can you also do for moving loads, and triangular loads example? Thank you.
your the goat
Sir when you find out moment of udl that time 8×4×(4÷2) +5×5=Rb×6 hona chahiye
Right
Hlo any one tell me how to get 3.57 answer
There's something wrong here
Is that you talking about hinge support?
How Rb =5.86kn
41/7
💩