Uniformly Distributed Load (UDL): Shear Force and Bending Moment Diagram [SFD BMD Problem 4]

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  • Опубликовано: 3 дек 2024

Комментарии • 36

  • @md.hasanuzzamanjihad4623
    @md.hasanuzzamanjihad4623 Год назад +4

    Great and easiest explanation... Thanks bro. Pls upload more videos on SFD and BMD problem solving

  • @FilmonAron-qx4gg
    @FilmonAron-qx4gg Год назад +4

    Thank you so much for the clear explanation!

  • @AnanyaAugustine
    @AnanyaAugustine Год назад +2

    Thank you for the detailed explanation

  • @gabrielatem1121
    @gabrielatem1121 Год назад +1

    Much appreciated your explanation❤

    • @YvonneMbinya-r7x
      @YvonneMbinya-r7x Год назад

      Great video, have being trying to understand udl and your video helped me a lot, much love from Kenya 🇰🇪

  • @gabrielatem1121
    @gabrielatem1121 Год назад +4

    Could you clarify how length x=3.57 become force at maximum point E?

    • @aqsanazir4819
      @aqsanazir4819 Год назад +1

      Same question

    • @zyler548
      @zyler548 Год назад +2

      Look back 10 Standard Maths Similarity of Triangles

  • @prashanthakumar4573
    @prashanthakumar4573 Год назад +5

    how did you get Rb value 5.86kn

    • @mahendratripura800
      @mahendratripura800 7 месяцев назад

      41/7

    • @arcreation2732
      @arcreation2732 2 месяца назад

      ​@@mahendratripura800I think moment=(8*4*(4/2))+(5*5)-(Rb*7) = Rb = 12.71 kn

  • @baiklahtu
    @baiklahtu Год назад +1

    Sorry sir, SFdr for SF diagram should be - 4.14 or - 5.86?

  • @為志揚
    @為志揚 Год назад +2

    你超猛的,聽不懂你的語言我卻看得懂整個分布圖,

  • @forouzanhabibi
    @forouzanhabibi Год назад +1

    Thank you so much

  • @palakramawat4983
    @palakramawat4983 9 дней назад +1

    Non uniformly Kaha milega sir

  • @charukadilshan4599
    @charukadilshan4599 7 месяцев назад

    Great Teaching

  • @gluton07
    @gluton07 5 месяцев назад +1

    while taking moment at E its length is 3.57, doesnt the point load 8 kN will be counted as Moment at E = 7.14*3.57-2*3.57²/2-8*1.57 ??

    • @Rahulterabhaisabsebhar.i
      @Rahulterabhaisabsebhar.i 4 месяца назад +1

      Bro 8 KN is UDL and 3.57 is also udl but 3.57 is part of 8 hence we will neglect it because we Have created Individual Udl of that

  • @satazer5824
    @satazer5824 Год назад

    Perfect method. Thank you.

  • @kenken578
    @kenken578 Год назад

    Can you also do for moving loads, and triangular loads example? Thank you.

  • @olivergrennan309
    @olivergrennan309 7 месяцев назад +1

    your the goat

  • @strdpra0z
    @strdpra0z 10 месяцев назад +1

    Sir when you find out moment of udl that time 8×4×(4÷2) +5×5=Rb×6 hona chahiye

  • @VijayVijji-yr3lz
    @VijayVijji-yr3lz 2 месяца назад

    Hlo any one tell me how to get 3.57 answer

  • @kerinekylie
    @kerinekylie 5 месяцев назад +2

    There's something wrong here

    • @Parmar2114
      @Parmar2114 2 месяца назад +1

      Is that you talking about hinge support?

  • @patilgouda
    @patilgouda 11 месяцев назад

    How Rb =5.86kn

  • @Lazycrusher886
    @Lazycrusher886 Год назад

    💩